TQW Pt. II Flashcards
(145 cards)
Free particle wavevfunction calculation.
Free particle properties. Note that you can get rid of one of the wavefunction terms (in this case B) since the +ve or -ve just represents the direction of motion.
By ‘what is’ I mean how can you express?
What is position in 2D systems?
What is momentum in 2D?
What is del in 2D?
True or false, you can seperate the vector momentum operator into N components (where N is the number of dimensions)?
Breaking the momentum operator into its components can make N-dimensional problems a lot easier, rather than doing it all in a vector. I.e. with the free particle in 2D.
What is the relation between the Hamiltonian and Momentum operator (when Potential, V= 0)?
What is the commutation between the Hamiltonian and Momentum operator for a free particle(V=0)? Answer for each of the components of the Momentum Operator.
T/F? The eigenstates/eigenfunction of the Hamiltonian and Momentum operators are the same. Why is this the case?
True, the eigenstates of the Hamiltonian and Momentum operators are identical. This is because the commutation of the Hamiltonian of a free particle and Momentum are compatible (commute to 0).
Starting with the equation of a plane wave (in 2D), show that it is the eigenstate to the Momentum operator and find the eigenvalues of momentum.
Do the same with the Hamiltonian- remember the del^2 operator is not a vector.
Vector momentum tip, break the vector momentum operator into its components, Px[hat] and Py[hat], allow both of these to act on the wavefunction, not forgetting to state their direction/unit vector when stating the final answer.
Note: Error in slide; corresponding momentum eigenvalue should be
hbarK = hbarKxex + hbar*kyey
What are the boundary conditions for a particle in a 2D infinite potential box of units of length Lx * Ly?
What is Schrodinger’s equation for this wavefunction?
If you are seeking a seperable solution, how can you reduce (10) to 2 independent 1-Dimesional equations?
Since you are effectively applying the hamiltonian to each dimension individually, they will return eigenvalues epsi(x) and epsi(y), which is NOT the energy eigenvalue of the eigenstate, only a fraction of it.
The energy eigenvalue = sum of eigenvalue for each dimension i.e. E = epsi(x) + epsi(y).
Hints:
Born Rule Pn = I Cn I^2
Total probablility = 1 = P(3,2)+P(3,2)+P(4,3)
- Find what L is equal to
- Use this to find the probabiliy of each state (apply into born rule equation again).
- Expected energy = sum of (Pn*E(n,m))
What is the wavefunction of a 2D box?
What are the energy eigenstates in a 2D box?
(The equation of)
What does it mean for states to be degenerate?
What does this mean for the superposition of 2 Eigenstates?
Degenerate states have the same Energy eigenvalue.
Superposition of degenerate eigenstates is also a eigenstate.
How can you lift the degeneracy of a system?
Breaking symmetry lifts degeneracy, i.e. changing dimensions of container.
If Ia> and Ib> return the same energy eigenvalue, is their sum also an eigenstate?
If Ia> and Ib> return the same eigenvalue then they are degenerate. Any combination of them will produce an eigenstate.
State an orthogonal combination of
(u4,3 - u3,4)/sqrt(2).
Are degenerate eigenstates orthogonal to each other eigenstates of the same degeneracy?
What about to eigenstates of a different degeneracy or that return different eigenvalues?
Eigenstates of the same degeneracy may or may not be orthogonal since they do not return different eigenvalues.
Degenerate eigenstates are always orthogonal to all other states.
Suppose the particle is in an arbitrary state Iψ>, what is the probability that a measurement of its energy will give a particular result?
(a) that the measurement is not an eigenvalue of the Hamiltonian.
(b) that the measurement is an eigenvalue.
For a square box:
What combination of states yield 2ϵ , 5ϵ and 65ϵ . For each, what would the probability be for yielding each of the results if the particle is in an arbitrary state?
Hint for 65ϵ (4,7) and (1,8) both have a sum of squares of 65.
Don’t forget potential degeneracies!!
After the measurement of an arbitrary wavefunction, what happens?
What happens if the wavefunction it collapses into is degenerate i.e. give the wavefunction after the collapse in dirac-delta notation.
Do this for the eigenvalue of 5e.
State the normalisation constant of this state.
After measurement, wavefuction collapses to reflect the measurement obtained.
Give the form of a central force in terms of a central potential. Hint: Vector calculus notation.