Organic Chemistry Reactions Flashcards

1
Q

What is the rate law for an SN2 reaction?

A

An SN2 reaction is bimolecular. The rate depends on both the substrate and the nucleophile. The formation of the transition complex (which involves both the substrate and the nucleophile) is the rate-limiting step.

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2
Q

What is the rate law for an SN1 reaction?

A

An SN1 reaction is unimolecular. The rate depends on just the substrate. Specifically, the formation of the carbocation is the rate-limiting step.

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3
Q

What type of solvents are best suited for an SN1 reaction? Why?

A

Polar protic solvents are best for SN1 reactions. This is becuase they help stabilize carbocations, and aid in removal of the leaving group.

Below are the most common polar protic solvents

Examples of polar protic solvents: alcohols, carboxylic acids, ammonia, Bronsted acids (typically aqueous), and of course water.

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4
Q

What type of solvents are best suited for an SN2 reaction?

A

Polar aprotic solvents are best for SN2 reactions, which allow for the nucleophile to react with the substrate without interacting with the solvent.

Below are the most common polar aprotic solvents

Examples of polar aprotic solvents: acetone, dimethyl sulfoxide (DMSO), ethers, alkane (i.e. hexane), and chloroform.

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5
Q

For an E2 reaction, what orientation must the substrate be in?

A

The leaving group and cleaved proton must be anti-coplanar in respect to one another.

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6
Q

List the thermodynamic stability trend for alkenes

A

Unsubstituted < monosubstituted < cis-disbustituted < trans-disubstituted < trisubstituted < tetrasubstituted

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7
Q

For an E2 reaction, why do we consider the thermodynamic stability of the product?

A

The most thermodynamically stable product (the Zaitsev product) will be favored when using a nonbulky base (minimizing steric hindrance) and the less thermodynamically stable alkene (the Hoffman product) will be formed when using a bulky base.

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8
Q

List the stability trend for carbocations

A

The alkyl groups around a carbocation will help stabilize the positive charge due to their positive inductive effect (increasing electron density at the carbocation center). Also, remember that mesomeric effects (resonance stabilization) is stronger than inductive effects.

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9
Q

What is the rate-limiting step for an SN1 reaction?

A

The formation of the carbocation

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10
Q

What is a Lewis base?

A

A substance that can donate a pair of nonbonding electrons (such as the lone pair of an oxygen or nitrogen atom). Many Lewis bases are utilized for this chemical trait due to their nucleophilicity.

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11
Q

What is a Lewis acid?

A

A substance that can accept an electron pair (an electrophile) due to a vacant orbital. Many cationic metals are Lewis acids (Ag+</sub>,Cu+, Al3+), also a common Lewis acid is BF3.

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12
Q

What is a nucleophile?

A

A molecular or atomic species that can attack a nucleus (nucleophile - nucleus loving) typically a positively charged or partially positive center.

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13
Q

What is the rate-limiting step for an E2 reaction?

A

The formation of the transition-state complex.

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14
Q

What is an electrophile?

A

Electrophiles are chemical species that are attract/attracted to electron dense species (electrophile - electron loving).

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15
Q

How does a positive inductive effect impact the acidity of a carboxylic acid?

Will the pKa increase or decrease?

A

The pKa will increase, the positive inductive effect will increase the electron density of the O-H bond and consequently strengthen the bond (decreasing the acidity).

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16
Q

How does a positive inductive effect impact the acidity of a carboxylic acid?

Will the pKa increase or decrease?

A

The pKa will decrease, the negative inductive effect will decrease the elctron density of the O-H bond, weaknening the bond so that the proton is more likely to dissociate (becoming more acidic).

17
Q

What is the rate-limiting step for an E1 reaction?

A

The formation of the carbocation

18
Q

What is the rate-limiting step for an SN2 reaction?

A

The formation of the transition-state complex

19
Q

What type of nucleophile is needed to obtain the Hoffman product in an E2 mechanism?

A

A strong, bulky base (i.e. potassium tert-butoxide)

20
Q

What conditions are suitable for an E1 reaction?

A

A strong acid and heat, as long as the substrate is capable of forming a carbocation. Becuase an E1 and SN1 share this step, they can compete with each other. It is common to find both products in a reaction mixture (heat will increase the E1 %yield).