paper 2 Flashcards
(101 cards)
practical 2.33B - investigate the energy content in a food sample
BANANA CHIP
- attach a boiling tube to a clamp stand
- Use the measuring cylinder to measure out 25cm3 of water and pour it into the boiling tube
- Record the starting temperature of the water using the thermometer
- Weigh the initial mass of the food sample
- Set fire to the sample of food using the bunsen burner and hold the sample 2cm from the bottom of the
boiling tube until it has completely burned - Record the final temperature of the water
- (Once cooled) weigh the mass of any remaining food and record
- Repeat the process with different food samples
A larger increase in water temperature indicates a larger amount of energy contained by the sample
We can calculate the energy in each food sample using the following equation:
Energy transferred (J) =
(mass of water (g) x 4.2 x temperature increase (°C)) ÷ (mass of food (g))
how is water absorbed by the root hair cells
plants take in water from the soil through the root hair cells. the root hair cells (RHC) are specialized to increase their surface area which then increases rate of active transport.
the plant actively transports the mineral ions from the soil into the root hair cells. the mineral ions lower the water potential of the root hair cells. the water will then osmosis from the soil to the RHCs as the RHCs have the lower water potential. (osmosis - water moves from high to low conc)
this gradient is maintained as the water is continually being taken up by the xylem.
transpiration
water lost from the leaves, mainly from the stomata due to evaporation off of the leaf surface
(water evaporates into the air spaces in the spongy mesophyll then diffuses out of the stomata)
how is transpiration rate affected by humidity
Very humid air contains a great deal of water vapour – there is a smaller concentration gradient, so transpiration slows down.
In dry air the diffusion of water vapour from the leaf to the atmosphere will be rapid.
Transpiration therefore increases if humidity decreases.
how is transpiration rate affected by wind speed
In still air, the region around a transpiring leaf will become saturated (full) with water vapour so that no more can escape from the leaf –causing transpiration to slow down.
In moving air, the water vapour will be blown away from the leaf as fast as it diffuses out. This will speed up transpiration.
Transpiration therefore increases as wind speed increases.
how is transpiration rate affected by temperature
On a hot day, water will evaporate quickly from the leaves of a plant as the water molecules have more kinetic energy.
Transpiration therefore will increase as temperature increases
how is transpiration rate affected by light intensity
Light itself does not affect evaporation, but in daylight the stomata of leaves are open to supply carbon dioxide for photosynthesis.
This allows more water to diffuse out of the leaves and into the atmosphere
2.58B practical - investigate the role of wind in determining the rate of transpiration for a leafy shoot
potometer!!
- The potometer must be set up under water - this prevents any air bubbles from entering the
system and blocking the xylem.. - Cut the stem of a shoot whilst submerging the shoot
- Put the shoot stem into the bung, grease the joint with plenty of petroleum jelly - this prevents
water loss and air entry - Put the bung into the potometer.
- Make sure the tap is closed and it is full of water (no bubbles). Then lift the potometer out of the
water. - Leave the end of the capillary tube out of the water until an air bubble forms then put the end
into a beaker of water. - place a hairdryer so its blowing on the plant to recreate wind
- You can measure the transpiration rate as distance the bubble travels in five minutes (or the
time taken for the bubble to travel a set distance). You should take a number of readings and
calculate a mean rate.
2.58B practical - investigate the role of increased temperature in determining the rate of transpiration for a leafy shoot
potometer!!
- The potometer must be set up under water - this prevents any air bubbles from entering the
system and blocking the xylem.. - Cut the stem of a shoot whilst submerging the shoot
- Put the shoot stem into the bung, grease the joint with plenty of petroleum jelly - this prevents
water loss and air entry - Put the bung into the potometer.
- Make sure the tap is closed and it is full of water (no bubbles). Then lift the potometer out of the
water. - Leave the end of the capillary tube out of the water until an air bubble forms then put the end
into a beaker of water. - make the room hot
- You can measure the transpiration rate as distance the bubble travels in five minutes (or the
time taken for the bubble to travel a set distance). You should take a number of readings and
calculate a mean rate.
2.58B practical - investigate the role of humidity in determining the rate of transpiration for a leafy shoot
potometer!!
- The potometer must be set up under water - this prevents any air bubbles from entering the
system and blocking the xylem.. - Cut the stem of a shoot whilst submerging the shoot
- Put the shoot stem into the bung, grease the joint with plenty of petroleum jelly - this prevents
water loss and air entry - Put the bung into the potometer.
- Make sure the tap is closed and it is full of water (no bubbles). Then lift the potometer out of the
water. - Leave the end of the capillary tube out of the water until an air bubble forms then put the end
into a beaker of water. - surround the plant in a clear plastic bag
- You can measure the transpiration rate as distance the bubble travels in five minutes (or the
time taken for the bubble to travel a set distance). You should take a number of readings and
calculate a mean rate.
2.58B practical - investigate the role of light in determining the rate of transpiration for a leafy shoot
potometer!!
- The potometer must be set up under water - this prevents any air bubbles from entering the
system and blocking the xylem.. - Cut the stem of a shoot whilst submerging the shoot
- Put the shoot stem into the bung, grease the joint with plenty of petroleum jelly - this prevents
water loss and air entry - Put the bung into the potometer.
- Make sure the tap is closed and it is full of water (no bubbles). Then lift the potometer out of the
water. - Leave the end of the capillary tube out of the water until an air bubble forms then put the end
into a beaker of water. - make the room dark
- You can measure the transpiration rate as distance the bubble travels in five minutes (or the
time taken for the bubble to travel a set distance). You should take a number of readings and
calculate a mean rate.
what does the kidney do
excrete toxic waste products and substances in excess
osmoregulation
whats osmoregulation
the process of maintaining water and salt concentrations across membranes in the body
example of homeostasis
what are the 3 parts of the kidney
cortex - the outmost region
Medulla - the inner section of the kidney
Renal pelvis - the tube linking the kidney to the ureter
where are the nephrons
in the kidney
Nephrons start in the cortex of the kidney, loop down into the medulla and back up to the cortex
where do the contents of the nephron go
drain into the renal pelvis and the urine collects there before it flows into the ureter to be carried to the bladder for storage
structure of the nephron
The nephron is made up of a kidney tubule which has several sections:
glomerulus inside the bowman’s capsule
Proximal convoluted tubule
Loop of Henlé
Distal convoluted tubule
Collecting duct
what is the proximal convoluted tubule
section of nephron after the bowmans capsule and before the loop of henle
what is the distal convoluted tubule
section of nephron after the loop of henle and before the collecting duct
how does the kidney excrete
Ultrafiltration
Selective reabsorption of glucose
Reabsorption of water and salts
what is ultrafilterisation
Arterioles branch off the renal artery and lead to each nephron, where they form a knot of capillaries (the glomerulus) sitting inside the cup-shaped Bowman’s capsule
The capillaries get narrower as they get further into the glomerulus which increases the pressure on the blood moving through them (which is already at high pressure because it is coming directly from the renal artery which is connected to the aorta)
This eventually causes the smaller molecules being carried in the blood to be forced out of the capillaries and into the Bowman’s capsule, where they form what is known as the filtrate
This process is known as ultrafiltration
The substances forced out of the capillaries are glucose, water, urea, salts
Some of these are useful and will be reabsorbed back into the blood further down the nephron
what is in the glomerular filtration
glucose, water, urea, salts
selective reabsorption of glucose
After the glomerular filtrate enters the Bowman’s Capsule, glucose is the first substance to be reabsorbed at the proximal convoluted tubule
This takes place by active transport (by specialized cells)
The pct is adapted for this by having many mitochondria to provide energy for the active transport of glucose molecules
Reabsorption of glucose cannot take place anywhere else in the nephron as the gates that facilitate the active transport of glucose are only found in the proximal convoluted tubule
whats in urine
water, urea, ions