Probit Model Flashcards

(12 cards)

1
Q

What is the first steps in moving from a LPM to a probit model

A
  • We allow p to vary, depending on x
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

How do we keep p within the [0,1] interval

A
  • We need a non-linear relationship between x and p
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What type of curve do we need for the interval of p to be between [0,1]

A
  • An S-shaped curve
  • The slope is not constant as in the LPM
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

What defines the probit model

A
  • The choice of a standard normal distribution for the relationship between x and p
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Why cant the coefficients be used to find the magnitude of the effect for a probit model

A
  • The x’s are a non linear function of p
  • Interpretation is done through the examination of marginal effects of a one-unit change in x on the probability that y=1
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Write down how a probit model is defined

A
  • pi = P[Z <= b0 + b1xi]
  • pi = Φ(b0 + b1xi)
  • pi = integral of 1/(2π)^1/2 * e^-t^2 / 2 dt between b0+b1xi and -∞
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

How to we find the partial effect of a continuous variable in a probit model

A
  • We need to take the partial derivative with respect to that variable
  • ∂Pr(y=1|x1,…,xk) / ∂xk = ∂Φ(b0h + b1h * x1 + … + bkh * xk) / ∂xk = φ(b0h + b1h * x1 + … + bkh * xk) * bkh
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

What is the difference between φ and Φ

A
  • φ is the normal density function of Φ
  • The derivative of the cumulative distribution function Φ is the density function φ
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

How is the marginal effect of the variable determined

A
  • Determined by the sign of bkh, since the pdf part of the marginal effect is always positive
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How is computing the partial effect of a discrete variable different to a continuous variable

A
  • The first derivative cannot be used
  • We must find the discrete change in probability
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

How do we find the discrete change in probability for a discrete random variable

A
  • Subract P(y=1 | x=1) from P(y=1 | x=0)
  • Φ(bh0 + bh1 * 1 + bh2 * x2 + … + bhk * xk) - Φ(bh0 + bh1 * 0 + b2h * x2 + … + bhk * xk)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q
A
How well did you know this?
1
Not at all
2
3
4
5
Perfectly