Quadratic Processes Flashcards

1
Q

To find x-intercepts for a parabola, the easiest form to use is…

A

Factored Form

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2
Q

To find y-intercepts for a parabola, the easiest form to use is…

A

Standard Form

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3
Q

To find x-intercepts for a parabola from Vertex Form there are 3 techniques…

A

Solve for x after setting y=0; OR
Convert to Factored Form; OR
Use the Quadratic Formula after converting to Standard Form

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4
Q

To find x-intercepts for a parabola in Standard Form there are 2 techniques…

A

Convert to Factored Form; OR
Use the Quadratic Formula

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5
Q

Even though there are multiple paths to finding x-intercepts, in the end they are all the same as Solving for x after…

A

Solving for x after setting y=0

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6
Q

Finding y-intercepts, requires Solving for y after…

A

Solving for y after setting x=0

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7
Q

If a parabola has no x-intercepts, the best way to demonstrate this is…

A

By showing that the Quadratic Formula is not possible due to it resulting in a negative number under the root sign

which is when b² - 4ac < 0

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8
Q

If a quadratic function can’t be factored using the simple or integer techniques learned in class, there are 2 possibilities…

A

The Quadratic Formula is required; or the quadratic is not factorable

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9
Q

If it seems a quadratic can’t be converted to factored form to find the x-intercepts, there are 2 possibilities…

A

The Quadratic Formula is required to find the x-intercepts; or the Quadratic Formula shows that there are no x-intercepts.

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10
Q

It is not possible to convert to Factored Form, if…

A

b² - 4ac < 0
which is the same as saying…
whenever the Quadratic Formula fails due to a negative value under its root sign

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11
Q

To convert to Vertex Form there are 2 possibilities…

A

If you know the vertex and 1 other point, use y=a(x-h)² +k directly; OR
If the quadratic is in Standard Form, complete the square

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12
Q

When converting to Factored Form, which 4 factoring techniques could be required?

A
  1. Common Factoring
  2. Simple trinomial factoring, x²+bx+c
  3. Complex trinomial factoring, ax²+bx+c
  4. Special Binomial / Difference of Squares, x²-c²
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13
Q

When Completing the Square, what is the side calculation needed to start the process from Standard Form?

A

Given x²+bx+c, the first step is to calculate (b/2)²

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14
Q

When Completing the Square given x²+6x+2, you have calcuated (6/2)² = 9. Where does this value go in the next step?

A

x²+6x+2
=(x²+6x+9-9)+2
=(x²+6x+9)-9+2

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15
Q

After converting Standard Form to Vector or Factored Form, what could you do to check your solution?

A

Expand your solution from Vector or Factored Form back to Standard Form!

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16
Q

To find the Vertex, there are 3 possibilities…

A

Convert to Vertex Form; OR
From Factored Form average the x-intercepts to find the axis of symmetry; OR
From the Quadratic Formula average the x-intercepts to find the axis of symmetry

The axis of symmetry has 1 extra step to find the y-value of the vertex