Quantum Flashcards

1
Q

Photoelectric effect definition

A

Phenomenon where electrons are emitted from a metal surface where electromagnetic radiation of sufficiently high frequency is incident on

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2
Q

Particulate nature of EM

A

Em radiation exists as discrete quanta of energy known as photons.

(Photons are discrete bundles of EM energy)

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3
Q

Energy of single photon

A

E=hf

Photon energy only dependent on frequency

Intensity just gives no. of photons per unit time

I=P/A = Etotal/tA = NE/tA = Nhf/tA

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4
Q

Energy of single photon

A

E=hf

Photon energy onl y

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5
Q

Photoelectric equation

A

hf = φ + Ekmax

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6
Q

What does intensity increase

A

Rate of incident photons thus rate of electrons emitted

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7
Q

Describe how the photoelectric effect provide evidence for the particulate nature of electromagnetic radiation.

A
  1. The existence of a threshold frequency below which no photoelectrons are emitted proves that EM radiation consists of discrete quanta energy given by hf.
  2. The instantaneous emission of photoelectrons when all the photon energy is transferred immediately to the electron gives evidence of particulate nature of EM.
  3. The maximum kinetic energy of photoelectrons being dependent only on frequency of radiation f, which relates to the discrete energy of photon, and independent on the intensity of radiation gives evidence for the particulate nature of EM.
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8
Q

Stopping potential setup

A

When metal E is illuminated with an EM radiation of sufficiently high frequency, electrons are emitted from E.

Adjust the potential difference between emitter E and colector C such that potential of C is held negative with respect to E, by reversing the polarity of the voltage source.

Adjust the variable voltage source slowly such that the negative potential is made more negative just until no electron can reach C indicated by 0 photocurrrent on ammeter

This is stopping potential where even the minimum negative potential will stop the most energetic electron from reaching C

All the KE of fastest electrons will be converted to electric PE just before reaching C

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9
Q

Stopping potential

A

Minimum retarding potential to stop all the emitted electrons from reaching the collector plate

Ekmax =eVs

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10
Q

Threshold frequency

A

Minimum frequency of the incident radiation for electron to escape

f = φ/h

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11
Q

Work function energy

A

Minimum amount of energy required to remove an electron from surface of material

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12
Q

Criteria for emission of electrons

A

Frequency greater of equal to threshold frequency

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13
Q

For observable wave nature..

A

The de broglie wavelength should not be too small ( ~10^-15). Given value of h is small, mass of particle must also be very small for wavelength to be noticable.

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14
Q

Evidence that light behaves like a wave

A

Interference/ diffraction of light
eg
youngs double slit
single slit: diffraction grating
Polarisation of light

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15
Q

Evidence that light behave as particles

A

Photoelectric effect

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16
Q

Electrons behave as particles

A

Electrons undergo collision, has mass and charge

17
Q

Electrons behave as waves

A

Electron diffraction

18
Q

Evidence for existence of discrete energy levels in atom

A

Line spectra

19
Q

Why do energy levels have negative values?

A

The energy level of an electron in the orbit of an atom is negative as the electrons require energy in order to be removed from the attraction of the nucleus. Showing that an electron is bound to nucleus.

When the electron gain energy and transit to an higher orbit, the energy level of the electron tend to zero when it reaches highest energy level of n= ∞. The position correspond to not being bound to nucleus.

Or

electrons and nucleus forms a bound system, where force between electrons and nucleus is attractive.
Given potential at infinity is negative, energy levels closer to nucleus will be lower and negative.

20
Q

What is an emission line spectrum

A

Emission line spectrum consist of discrete bright coloured lines in a dark background

Observed when a gas at low pressure is made to glow by heating or an electric discharge(applying high voltage)

21
Q

Describe how the line spectra can be explained using the idea of discrete electron energy levels in isolated atoms

A
  • Each line correspond to a specific photon energy
  • Photon is emitted when electron makes a transition from high to low E level
  • Since photon energy is of a specific value, it implies thst energy change between E levels are of a discrete amount.
  • Discrete energy level changes implies that energy levels are discrete.
22
Q

How is an emission line spectrum produced?

A
  1. Gas such as H or Ne can be placed in a discharge tube at low pressure.
  2. A voltage is applied between the metal electrodes in the tube large enough to produce an electric current in the gas
  3. The gas atoms become excited by the collsions with the electrons passing through the tube from cathode to anode of tube.
  4. The excited gas atoms are unstable and transits to a lower energy level.
  5. Since atoms have deicrete energy levels, inly specific high to low energy level transitions are possible, thus photons emitted are of specific energies and specific frequencies
  6. Coloured lines present in tube correspond to these photons of specific frequencies
23
Q

Absorption line spectrum

A

Dark lines against a continuous spectrum of white light

24
Q

How is an absorption line spectrum produced?

A
  1. Produced when white light passes through cold gas
  2. Gas atoms are excited to higher energy levels when they absorb photons from white light
  3. Since atoms have discrete energy levels, only specific low to high energy level transitions are possible. Thus photons absorbed are of specific energies and specific frequencies.
  4. When atoms transit back to ground state, photons of same frquencies are reradiated in all directions
  5. The part of absorption spectrum that correspond to these frequencies appear as dark lines in comparison to the non absorbed frequencies.
25
How are xrays produced?
1. Cathode is heated to a high temperature, causing it to emit electrons 2. The cathode and anode have an accelerating potential, causing electrons to be accelerated through potential difference of several thousand volts, gaining very high KE. 3. Electrons strike metal on anode. Loss in KE is converted to high energy Xrays.
26
Explanation for continuous xray spectrum
27
Why is saturation current reached?
At a particular intensity of light, there will be max no of photoelectrons emitted. When all electrons emitted are collected
28
Given intensity voltage graph, how are electrons still emitted when V=0 (ie Intensity not 0)
The emitted electrons move with a range of velocities in all directions. in the absence of an electric force, the electrons can still reach the collector plate if they have sufficient KE
29
Explanation for continuous Xray spectrum
1. An electron with high initial KE collides with metal atom at target atom nucleus at anode 2. As electron approaches target nucleus, it deflects due to the attractive force between nucleus and electron, in the process, KE initial is converted to KE final due to the large deceleration 3. Loss of KE is converted to EM energy as Xray photon of energy hf 4. As energy of photon is dependent on magnitude of acceleration, the closer an electron is to the nucleus, the larger the deflecting force, the larger the energy of photon emitted 5. As numerous electrons strike the target, deflection occur at a range of proximities, resulting in a distribution of photon energies, hence large range of wavelengths, forming a continuous spectrum.
30
Explanation for characteristic xray peaks
1. High energy electron collides with an atom in target metal 2. Collision results in ionised L/K shell electron, leaving a vacancy in the L/K shell. 3. _ shell electron deexcites to L/K shell, resulting in emitted _ (Ka/Kb/La/Lb) xray photon
31
How would stopping potential change if smaller wavelength of light used
Magnitude of stopping potential would become bigger Photons of smaller wavelength has more energy When photons of higher energy are absorbed by the electrons in the rhodium metal, the max KE of photelectrons emitted is higher since the work function energy remains the same for the same metal. Since the stopping potential depends on the max KE of photoelectrons emitted, the magnitude of stopping potential required is bigger.
32
How to find maximum energy of X-ray photon produced.
All KE of accelerated electron is converted to one single photon of X-ray. Loss in EPE=Gain in KE eV = 1/2mv^2 =hf
33
Saturation current relates to
Photoelectrons emitted