Reagents sem 2 Flashcards
(47 cards)
Diene + Dienophile
Diels alder (forming 6 membered ring)
- Diene needs EDG
- dienophile needs EWG
- retention of OG stereochem
- ENDO rule
Benzene + [HNO3, H2SO4]
Adds NO2 via Electrophilic Aromatic Substitution
nitrobenzyl + [Zn, HCl]
nitro to amine
- can be Zn, Sn, or Fe
Benzene + [Br2, FeBr3]
adds bromine to the aromatic ring
- rds is step 1, A–>NA
Benzene + [Cl2, AlCl3 or FeCl3]
adds chlorine to the aromatic ring
- rds is step 1, A–>NA
Benzene + [I2, HNO3]
adds iodine to the aromatic ring
Benzene + [SO3, H2SO4]
adds SO3H to aromatic ring
Benzene with SO3H + [H2SO4, H2O, heat]
Takes off SO3H
Benzene + [alkyl halide, AlCl3 or FeBr3]
Friedel craft alkylation
- doesnt work on ar compounds containing an EWG
- C+ rearr can occur on halide
- Multiple alkylations may occur
Benzene + [1)acid chloride, AlCl3 or FeBr3, 2)H2O]
Friedel craft acylation
-doesnt work on ar compounds containing an EWG
- no rearr
- no multiple acylatinos
- H2O is needed
What does the clemmenson reduction do and what are the reagents?
Zn(Hg), HCl
- reduces C=O
Anisole + [CO, HCl, AlCl3/CuCl]
Gatterman Koch synthesis
- adds aldehyde para on
- doesnt have to have anisole, can be any aromatic compund
Explain nucleophilic aromatic substitution (NAS): Addition Elimination
Substitutes nuc with LG
- requires EWG in o or p position to LG
- can work with NH3, NaOH, or NaOR
Explain nucleophilic aromatic substitution (NAS): elimination addition
- Creates benzyne
- Works with strong base (NaNH2 or NaNr2) or base with heat (NaOH, NaOR)
- attacks both benzyne spots equally
Explain the reaction of carboxylic acid with [1)2 eq of grignard 2)H3O+]
turns it into a ketone
- first grignard does acid base
- second grignard attacks carbonyl
explain the reaction of nitrile with [1) grignard 2)H3O+]
turns it into imine then ketone via hydrolysis
explain the reaction of nitrile with [1) DIBAL-H 2)H3O+]
Turns nitrile into aldehyde
- only 1 H-
- hydrolysis turns it from “imine” to aldehyde
CA + [1)SOCl2 2)LiAlH(OtBu)3]
1) SOCl2 turns it into acid chloride
2) turns it into aldehyde
- must be 2 steps
Acid Chloride + [R2CuLi]
turns it into ketone
Ester + [1)DIBAL-H 2)H2O]
turns ester into aldehyde
Ketone + [1°,2° Amine + acid]
- what would happen if reacted with a 3° amine
forms imine
- 3° amine would form an enamine
- reversible reaction
Ketone/aldehdye + [2eq of ROH + Acid]
formation of acetal
- reversible reaction
- remember aldehyde is faster than ketone
Explain what happens when Ph3P reacts with [1) Ch3Ch2Br 2) BuLi 3) Acetone]
- steps 1 and 2 with the starting material create the wittig reagent
- reaction with acetone replaces O on carbonyl with Carbon chain (Z)
Aldehydes + [Ag2O]
turns it into CA