Rules of Replacement Flashcards

1
Q

p ⁘ ~~p

A

Double Negation (DN)

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2
Q

Double Negation (DN)

A

p ⁘ ~~p

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3
Q

p & q ⁘ q & p
p v q ⁘ q v p

A

Commutation (Comm)

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4
Q

p & (q & r) ⁘ (p & q) & r
p v (q v r) ⁘ (p v q) v r

A

Association (Assoc)

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5
Q

~(p & q) ⁘ ~p v ~q
~(p v q) ⁘ ~p & ~q

A

DeMorgan (DeM)

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6
Q

Commutation (Comm)

A

p & q ⁘ q & p
p v q ⁘ q v p

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7
Q

Association (Assoc)

A

p & (q & r) ⁘ (p & q) & r
p v (q v r) ⁘ (p v q) v r

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8
Q

DeMorgan (DeM)

A

~(p & q) ⁘ ~p v ~q
~(p v q) ⁘ ~p & ~q

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9
Q

p & (q v r) ⁘ (p & q) v (p & r)
p v (q & r) ⁘ (p v q) & (p v r)

A

Distribution (Distr)

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10
Q

Distribution (Distr)

A

p & (q v r) ⁘ (p & q) v (p & r)
p v (q & r) ⁘ (p v q) & (p v r)

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11
Q

p → q ⁘ ~p v r

A

Implication (Impl)

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12
Q

Implication (Impl)

A

p → q ⁘ ~p v q

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13
Q

p → q ⁘ ~q → ~p

A

Transportation (Trans)

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14
Q

Transportation (Trans)

A

p → q ⁘ ~q → ~p

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15
Q

(p & q) → r ⁘ p → (q → r)

A

Exportation

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16
Q

Exportation

A

(p & q) → r ⁘ p → (q → r)

17
Q

p ≡ q ⁘ (p → q) & (q → p)
p ≡ q ⁘ (p & q) v (~p & ~q)

A

Equivalence (Equiv)

18
Q

Equivalence (Equiv)

A

p ≡ q ⁘ (p → q) & (q → p)
p ≡ q ⁘ (p & q) v (~p & ~q)