Section 2 Flashcards

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1
Q

What are the 2 screening methods which can identify a target for drug discovery?

A

Target-based screening: Choose a novel genetically encoded target, identify drugs which interact with it, then look for a disease where drugs may have therapeutic utility.

Phenotypic screening: Find a model of the disease phenotype, find drugs which interfere with the phenotype, then identify the specific protein target or targets involved.

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2
Q

What is the difference between in vitro and in vivo phenotypic screens?

A

In vitro phenotypic screens involve monitoring the effect of a drug on an isolated organ or body part. For example, monitoring HR on a perfused heart or pH of the luminal contents of a perfused stomach.

In vivo phenotypic screens allow monitoring of parameters on an anaesthetised animal. In this case, the target, its gene sequence, and its protein structure are unknown.

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3
Q

How was in vitro phenotypic screening used to determine the mechanism of action of Cimetidine?

A

An isolated rat stomach was perfused with saline solution and the pH of the luminal contents was measured as it left the stomach in the presence of nothing, histamine alone, and histamine in combination with cimetidine.

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4
Q

How did M3-knockin mice have an effect on the effects of carbachol?

A

In normal mice, as the concentration of the muscarinic agonist carbachol increased, the bronchial lumen narrowed.

In the M3-knockin mice, the M3-mACHr gene was modified to express a muscarinic M3 receptor which had its intracellular phosphorylation sites changed from serine/threonine to alanine, thus preventing phosphorylation.
In these mice, the bronchial lumen was much less sensitive and constriction only occurred at very high concentrations.

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5
Q

What are molecular-based target screens?

A

A chemical library of millions of compounds is screened against a particular protein to identify a ligand with agonistic or antagonistic effects.

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6
Q

What is high throughput screening?

A

The use of automated equipment/robots to generate multiwell plates and rapidly test thousands to millions of samples for biological activity.
Usually done after screening of a diverse compound library to identify a smaller subset of potent compounds.

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7
Q

What is FLIPR?

A

FLIPR is a fluorometric imaging plate reader which monitors intracellular calcium changes.
A calcium sensitive dye (fluo4) emits a fluorescent signal upon calcium binding which can be monitored in real time. This measures intracellular calcium-reliant signalling and can monitor GQ coupled responses

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8
Q

How could FLIPR be used to investigate histamine H1 receptor antagonists?

A

When histamine activates a histamine H1 receptor (G-protein coupled recceptor) there is hydrolysis of membrane phospholipids and generation of inositol triphosphates. This binds to intracellular receptors on the ER and leads to release of calcium which activate aspects of the cell (e.g., contraction of a smooth muscle cell).

FLIPR will simultaneously deliver histamine to 256 well plates containing the ,cell. In the absence of an antagonist, histamine will bind to the H1 receptor and there will be a release of intracellular calcium, which will be bound by the fluorescent calcium-sensitive dye, fluo4. This fluorescence will be monitored. However, in the presence of antagonist, H1 receptor activation by histamine will be inhibited, thus preventing calcium release and fluo4 binding. This results in a lower fluorescent response.

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9
Q

What is NanoBRET?

A

A bioluminescence energy transfer assay which monitors ligand binding. This is done using a fluorophore attached to the ligand. This becomes fluorescent upon excitation at 630nm by the luminescent protein nanoluciferase bound to the N-terminus of the target receptor. Thus when the fluorescent ligand binds to receptor, it becomes excited and the fluoresence can be detected.

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10
Q

How do reporter genes indicate cell signalling?

A

Reporter genes are genes which encode a detectable protein (via its luminescence, fluorescence, or colour). These genes can be encoded into cells downstream of a promoter that responds to a particular signal. If this signal occurs, the promoter will respond by encoding the necessary genes, including the reporter gene. The successful cell signalling can be measured using the luminescence, fluorescence, or colour given off.

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11
Q

How does label-free technology work?

A

It measures changes in the local refractive index resulting from ligand-induced mass redistribution (DMR) within the bottom region of a cell monolayer. It is measured as a shift in wavelength.

Cells are grown on a surface containing a waveguide substrate which allows light to pass along the bottom of cell and gives of a reflected light of a particular wavelength.
In response to stimulation (e.g., an agonist), the positioning of organelles can change (aka mass distribution). If this occurs near the coverslip (within 150nm), it will be detected and there will be a local change in refractive index. The light from the broadband source will pass through the waveguide and be reflected at a different wavelength dependent on the change in refractive index. This appears as a change in colour of the reflected light.

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12
Q

What is the main difference between target-based and phenotypic screening?

A

The location of the target ID in the drug discovery cascade.
Target-based: target identified/decided on straight after disease selection.
Phenotypic: target is identified after a lead is decided on (work out what your lead drug actually works on).

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13
Q

What are the advantages and disadvantages of target-based screening?

A

Advantages:
Molecular target known.
Mechanism of action is known at outset.

Disadvantages:
Assay used may be less disease relevant.
Drug target may not be disease relevant; risk of lack of efficacy in clinical trials.

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14
Q

What are the advantages and disadvantages of phenotypic screening?

A

Advantages:
Don’t necessarily need to know the molecular target.
Multiple targets and signalling pathways can be targeted.
Screening is disease relevant.

Disadvantages:
Could be more expensive as screening is more complex.
Mechanism of action is unknown at outset.
Target identification may be required for confirmation of lead compound.

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15
Q

Give an example of a drug which was repurposed for use in new diseases?

A

Chlorcyclizine, an antihistamine, was found to exhibit activity against Hep C virus during a screen of a chemical library.

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16
Q

What screen was used to identify chlorcyclizines activity against the hepatitis C virus?

A

The screen involved a cell which contained a CAG promoter and luciferase reporter gene. Between this was a sequence containing a stop codon, which if expressed, would prevent luciferase being expressed. This sequence was bordered by a CRE recombinase LoxP site either side, which, if activated by CRE (encoded in the virus), would remove the sequence, allowing expression of the luciferase.

So, if a drug such as Chlorcyclizine was effective, the CRE would not be able to enter the cells, so the CRE recombinase wouldn’t be activated, so the sequence wouldn’t be removed, and the luciferase wouldn’t be expressed.

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17
Q

How does Chlorcyclizine work against the Hepatitis C virus?

A

Usually:
1. Hepatitis virus cell surface protein envelope glycoprotein E2 interacts with receptor on human cells.
2. Virus undergoes endocytosis and becomes sequestered in the cell.
3. Hepatitis virus uses glycoprotein E1 to fuse with endosome to release genetic material and continue infectious process.
Chlorcyclizine interferes with glycoprotein E1 and its fusion with the endosome, preventing release of viral RNA into the cytosol.

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18
Q

What are orphan receptors?

A

Receptors for which we don’t what their ligand is.

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19
Q

What type of receptors are OX1 and OX2?

A

G-protein coupled receptors.

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20
Q

What is the pathophysiology of narcolepsy?

A

Normally, orexin neuronal activity oscillates and is high during normal walking and falls during normal sleep.
Narcolepsy is a neurodegenerative disease where the orexin-producing cells in the hypothalamus become degenerated, causing patients to suddenly fall asleep and have disrupted sleeping patterns.

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21
Q

What did the discovery of the orexin system and OX receptors mean for potential drug discovery?

A

Orexin antagonists for the treatment of insomnia.
OX receptor agonists/orexin mimetics for treatment of narcolepsy.

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22
Q

Name 2 current orphan receptors and their use as therapeutic targets.

A

GPR35 - high levels of expression in spleen and peripheral leukocytes, as well as expression in inflammatory cells could indicate a good target for allergy or asthma.
GPR55 - expression in bone, CNS, and cancer cells so could be used to treat obesity, osteoporosis, cancer.

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23
Q

What are the 2 binding sites present on GPCRs?

A

Orthosteric site - binding site of endogenous ligand.

Allosteric site - distant site on receptor where other ligands can bind and impose allosteric/conformational changes which lead to differences in signalling or ligand binding.

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24
Q

What is the principle of biased signalling?

A

G-protein coupled receptors have 2 binding sites - an orthosteric and allosteric. Binding of a ligand to either site can cause conformational changes in the receptor which affect subsequent binding at the other site.
Since G-proteins bind at the allosteric binding site, binding of a particular ligand to the orthosteric site could induce conformational changes in the receptor which favours coupling to G proteins or G protein independent signalling proteins e.g., beta-arrestin.

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25
Q

What is beta-arrestin?

A

A G-protein independent signalling protein which interfere with G-protein binding and block G-protein mediated signalling, thus desensitizing GPCR signalling.

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26
Q

What is the calcium sensing receptor (CaSR)?

A

A class C GPCR which maintains calcium homeostasis by acting as negative feedback. Upon binding of calcium to the orthosteric binding site, a conformational change in the receptor occurs causing coupling of G proteins. This signals intracellularly to inhibit parathyroid hormone synthesis and release, therefore inhibiting calcium reabsorption in the kidney and controlling bone reabsorption and mineralisation.

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27
Q

How do calcimimetics work?

A

Cinaclet binds to calcium sensing receptor at orthosteric binding site to inhibit parathyroid hormone release and therefore reduce calcium reabsorption in the kidneys. Used in patients with hyperparathyroidism or CKD.

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28
Q

Give an example of a virus-encoded GPCR.

A

Human cytomegalovirus causes overexpression of viral GPCR US28 on the cell surface. This GPCR responds to endogenous human chemokines and initiates signalling which leads to increased activity of transcription factors involved in cell proliferation, therefore can lead to cancer.

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29
Q

What is the difference between an agonist, an antagonist and an inverse agonist.

A

Agonists - increase receptor signalling
Antagonists - do not change basal signalling but prevent increased receptor sigalling by an agonist.
Inverse agonist - has the opposite effect of an agonist i.e., activity inhibited below basal signalling.

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30
Q

How are EGFR and HER receptors involved in cancer progression?

A
  1. Binding of agonist causes conformational change which exposes dimerisation domain.
  2. Receptor dimerises which causes a conformation change leading to phosphorylation of tyrosine residues on the intracellular side of the receptor by tyrosine kinase.
  3. Intiation of cascade of intracellular signalling, particularly via MAPK and PI3K-Akt pathways.
  4. Activation of cell proliferation and migration.
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31
Q

How does HER2 play a role in breast cancers?

A

Unlike other EGFR receptors, HER2 doesn’t have any known agonists, it is always in an “activated” conformation with its dimerisation domain exposed.
HER2 is overexpressed in 15% of all breast cancers and results in a more aggressive phenotype and poor prognosis.

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32
Q

How do anti-HER2 agents work?

A

Trastuzumab and Pertuzumab - recombinant humanised monoclonal antibodies which bind extracellularly and prevent dimerisation with HER3 and other EGFRs.
Lapatinib and Afatinib - type 2 tyrosine kinase inhibitors which bind irreversibly to inactive kinase allosterically.

33
Q

What is FRET?

A

Fluorescence resonance energy transfer is a process by which radiationless transfer of energy occurs from an excited state fluorophore (donor) to a second fluorophore in close proximity (acceptor), which then emits light at a different wavelength. If these are attached to proteins, they can indicate protein binding.

34
Q

What is BRET?

A

Bioluminescence resonance energy transfer is a process by which radiationless transfer of energy occurs from a bioluminescent enzyme such as luciferase (donor) to a fluorophore in close proximity (acceptor), which then emits light at a different wavelength. If these are attached to proteins, they can indicate protein binding.

35
Q

What is TR-FRET?

A

Time resolved fluorescence resonance energy transfer. Radiationless transfer of energy occurs from an excited state fluorophore (donor) to a second fluorophore in close proximity (acceptor), which then emits light at a different wavelength. Since short-lasting natural fluorophore emissions can occur from some nucleotides in DNA, this FRET assay doesn’t measure the flourescence immediately. It has a time delay to wait for the short-lasting natural emissions to die down to leave a much cleaner signal to measure the acceptor and donor fluorophore.

36
Q

Give an example of when nanoBRET has been used to measure dimerisation.

A

Measuring VEGFR2 dimerisation in the presence and absence of an agonist.
A halo tag was added to the n-terminus of VEGFR2 to allow attachment of a green fluorophore on one and nanoluciferase to another. Dimerisation resulted in a green light being emitted.

37
Q

How does Rapamycin work?

A

Immunosuppressant used for kidney transplantation.
Binds to immunophilin FK506 binding protein-12 (involved in regulating immune response) forming a complex which inhibits activation of the serine/threonine kinases of mTOR complex 1 and 2. This leads to decreased protein synthesis and G1 cell-cycle arrest.

38
Q

What is the principle of alpha screening assays?

A

When a donor bead is excited by a particular colour laser, it releases a singlet oxygen O2 which, if in close proximity, will excite an acceptor bead. These beads can be attached to specific antibodies which only interact with specific molecules, so can detect particular things.

39
Q

Give 2 examples of uses of alpha screening assays.

A
  1. MAP kinase phosphorylation - donor bead attached to antibody which only interacts with MAP kinase, while acceptor bead attached to antibody which only interacts with phosphorylated tyrosine residues. If tyrosine residue of MAPk is phosphorylated, then it can bind to both antibodies and bring the beads into close proximity for transfer of the singlet oxygen and emission from the acceptor bead.
  2. cAMP detection - donor bead attached to something that binds biotinylated cAMP, acceptor bead attached to antibody which binds to cAMP. Binding of biotinylated camp to both antibodies will bring the beads into close proximity for transfer of the singlet oxygen and emission from the acceptor bead. However, if endogenous cAMP is present, it will displace the biotinylated cAMP but only bind to the acceptor, so there will be no oxygen transfer and no emission from the acceptor bead. This could be used to make a response curve which could be used to measure the concentration of endogenous cAMP in cells based on emission.
40
Q

What are the 2 key properties of an successful agonist?

A

Affinity (ability to bind) - high affinity = high binding at low concentrations
Efficacy (ability to activate) - high efficacy = high activation at low binding

41
Q

What is EC50?

A

The concentration of agonist required to achieve 50%/half maximal response. A low EC50 means a lower concentration is required for a given level of response, so is more potent.

42
Q

What is Kd (in pharmacology)?

A

Kd is the equilibrium dissociation constant and represents the affinity of a ligand to its binding site. It is the concentration of ligand at which 50% of the receptors are bound. A low Kd means a lower concentration is required, so there is a high affinity.
Kd can be described as a ratio of the off-rate constant (koff) over on-rate constant (kon)

43
Q

What is the relationship between Kd (affinity) and EC50 (potency) of an agonist?

A

The difference between these is the efficacy of a drug.

When Kd=EC50, 50% receptor binding achieves 50% of the maximum response.

When Kd is more than EC50, for example if 10% binding achieves 50% of the maximum response, the agonist is more efficacious.

44
Q

What is the Gaddum equation and what does it measure?

A

Concentration of agonist producing 50% response in presence of antagonist / Concentration of agonist producing 50% response in absence of antagonist = 1 + (antagonist concentration/antagonist dissociation constant)

The dissociation constant of competitive antagonists.

45
Q

In what experiment is the Gaddum equation used?

A

One which measures a response against increasing concentrations of agonists. This is done once with agonist alone (control curve) and once in the presence of a fixed concentration of antagonist.

46
Q

What is a Schild plot?

A

A logarithmic plot of the Gaddum equation:
y=mx +c
Log (CR-1) = log[B]-logKb

Where:
y axis = log (concentration ratio-1)
x axis = log (molar concentration of antagonist)
y intercept (c) = -logKb = pA2
x intercept = logKb = -pA2
m (gradient) = 1

(pA2 is antagonist concentration required to shift the dose response curve 2 values compared to the control)

47
Q

How do the responses of an increasing concentration of agonist with a competitive vs a non-competitive inhibitor differ?

A

Competitive: As the concentration of an agonist increases, it will outcompete the antagonist for the binding site and produce a 100% response.

Non-competitive: Since it is not competing for the same binding site, as the concentration of an agonist increases, it will occupy all of its binding sites but this will never outcompete the antagonist as there is no competition. Therefore, it will never produce a 100% response.

48
Q

What is the law of mass action?

A

L + R <-> LR
The rate of a reaction is proportional to the product of the concentrations of each reactant.
At equilibrium, the rate of formation of new receptor-ligand complexes (kon) is equal to the rate of dissociation (koff).

49
Q

What does the Hill equation represent?

A

Relates the fraction of receptors bound to the concentration of ligand and the equilibrium dissociation constant (affinity).

50
Q

What are the 4 types of labels that can be used to measure ligand binding?

A
  1. Radio-labelled ligands - when radioligand binds to receptor, scintillant beads on the receptor give of flashes of light.
  2. Fluorescent ligands - fluorophore added to ligand which excites acceptor fluorophore on receptor can be detected with microscopy.
  3. Fluorescent polarisation - if free in solution fluoro-ligand will spin around and emit light in various directions. If bound to receptor light will be more polarised.
  4. Bioluminescent ligands - fluorophore added to ligand which excites bioluminescent protein on receptor which can be detected with microscopy.
51
Q

How can specific (target) binding be isolated from non-specific (off-target) binding during a ligand-binding experiment?

A
  1. Allow fixed concentration of radioligand to bind to all sites, specific and non-specific, and record binding.
  2. Repeat experiment in the presence of a saturating compound of unlabelled ligand to bind to the specific receptors. This means all your target receptors are occupied so the radioligand can only bind to non-specific sites. Record binding.
  3. Calculate the difference between these 2 values to find the specific radioligand binding to the target receptors.

Make sure the unlabelled drug has a higher affinity, a dissimilar structure, and a high concentration (2-3x more).

52
Q

What does an off rate constant (koff) of 0.01/min mean?

A

1% of bound ligand will dissociate in a minute.

53
Q

What is the residence time in relation to koff?

A

Its the reciprocal (1/koff)

54
Q

What is the residence time if an off rate (koff) is 0.01/minute?

A

1/0.01 = 100 minutes.

55
Q

How would you measure the equilibrium dissociation rate constant (koff)?

A
  1. Allow a radio/fluorescent ligand to associate/dissociate with the receptor and allow it to reach equilibrium.
  2. Prevent any further association, either by washing away the free ligand or by adding a high concentration of an unlabelled competitor.
  3. Measure the concentration of bound radioligand.
  4. Plot the binding against time. This will be a hyperbolic curbe where the minimum level of binding is defined by the level of non-sepcific binding at that point.
    koff = 0.693 / dissociation half-life

t1/2 (dissociation half-life) is the time at which half of the ligand has dissociated.

56
Q

What are allosteric modulators?

A

Substances that bind to a receptor to change that receptor’s response to stimuli.

57
Q

What is the effect of positive and negative allosteric modulators on residence time and off-rate constants?

A

Positive allosteric modulators cause a conformational change which increases retention of the ligand in the orthosteric binding site. This increases residence time, which means an increase in dissociation half life and a decrease in the off-rate constant.

Negative allosteric modulators cause a conformational change which increases dissociation of the ligand in the orthosteric binding site. This decreases residence time, which means a decrease in dissociation half life and an increase in the off-rate constant.

58
Q

Why is the on-rate constant harder to measure than the off-rate constant?

A

The off-rate constant is not dependent on the concentration, while the on-rate is, so this has to be considered.

59
Q

How would you calculate the association rate constant measured (kon) from a graph?

A

Calculate observed on rate (kobs) = 0.693/t1/2

kon = (kobs-koff)/concentration of radioligand

60
Q

What is competition binding?

A

A method used to assess the binding of an unlabelled compound.

The fraction of specific binding of a constant concentration of radioligand to a receptor is measured in the presence of different concentrations of a competitive unlabelled compound.

61
Q

Describe the use of CRISPR/Cas 9 to insert nanoluciferase for CXCR4 visualisation in cancer cells.

A

Activation of CXCR4 receptor is involved in cell proliferation and migration, therefore overexpression is associated with cancer development.

  1. crRNA and tracrRNA base pair to form a single guide RNA.
  2. CRISPR complex is added to HEK293 cells or HeLa cancer cells.
  3. The target-specific crRNA region base pairs to the target CXCR4 gene, guiding Cas9 to it.
  4. Cas9 endonuclease recognises PAM (protospacer adjacent motif), a sequence (usually NGG) on the gene a few bases down from the cut site. This allows Cas9 to cut both strands of DNA at a particular point.
  5. Homology directed repair is used to insert a coding sequence for nanoluciferase and repair the DNA.
  6. When the gene is expressed, nanoluciferase is expressed on the N-terminus of CXCR4.
  7. Upon binding of a fluorescent ligand, the location of CXCR4 can be visualised in real time using NanoBRET.
61
Q

What is an issue with using CRISPR/Cas 9 to insert nanoluciferase into CXCR4 gene? How can this be overcome?

A

Nanoluciferase is a big protein of 17 kilodaltans. Inserting something that large onto the front of the CXCR4 genome sequence can compromise its expression.

Instead of inserting the whole nanoluciferase sequence, just insert that of HiBiT. HiBiT is a smaller tag of only 11 amino acids and is a crucial sequence in the nanooluciferase structure. Upon complementation with added LgBiT subunit (the rest of the nanoluciferase structure), the complex has luciferase activity upon ligand binding. Binding of the ligand furimazine to the complex leads to CXCR4 visualisation using NanoBRET.

62
Q

What is a CRELoxP mouse?

A

Mouse which has cre-recombinase gene encoded downstream of a cell type specific promoter, meaning Cre-recombinase (a topoisomerase) is only expressed in certain cell types.

Also has LoxP recognition sites placed at the front and end of a target gene to be removed. A stop codon is placed at the end of the gene so that when its expressed it runs through and only expresses that gene. Downstream, a reporter gene encodes a green fluorescent protein.

Cre-recombinase is expressed in certain cells. It recognises the LoxP sites and removes the gene in between. When the section is removed, the reporter gene is expressed and the green fluorescent protein can be detected. If it not removed, the stop codon prevents expression of the reporter gene.

63
Q

What is phage display?

A

A method of displaying particular proteins on the surface of phages (viruses which infect and replicate in bacteria).

64
Q

How is phage display used to develop antibodies?

A

Screens antibody libraries to find high affinity antibodies for a specific antigen of interest.

  1. DNA from human B cells (produce antibodies) is isolated.
  2. The DNA is cloned and is inserted into Gene 3 region of the bacterial phagemid (region which determines proteins displayed on phage surface). These phagemids are a library of all the genes potentially encoding for antibodies of interest.
  3. Screening plates are created with target antigen on surface.
  4. Phage library is run across the plates and incubated. Some antibodies displayed on the phage will bind to the antigen and stick to the plate.
  5. The plate is washed to remove any other unstuck phages/antibodies.
  6. Phages which remain are eluted (removed with a solvent).
  7. Bacteria is infected with these phages, so phagemids (plasmid DNA from phages) amplify the antibodies.
65
Q

Give 4 examples of therapeutic antibodies developed using phage display, and what they target.

A

Ranibuzimab - VEGF-A (wet AMD)

Ganitumab - IGF-R1 (cancer)

Adalimumab - TNF-alpha (autoimmune conditions)

Ramucirumab -VEGFR2 (gastric cancer)

66
Q

What is the difference between a conventional antibody, a fab fragment, a heavy chain antibody, and a nanobody?

A

Conventional antibody - 2 light chains + 2 heavy chain, each with constant and variable regions.

Fab fragments - essentially just an “arm” of an antibody. Composed of one constant and one variable region from a light chain and a heavy chain.

Heavy chain antibody - an antibody not found in humans which consists of just 2 heavy chains, with its variable region functioning like that of the antigen binding region in humans (made up of variable region of both light and heavy chains).

Nanobody - the variable region of a heavy chain nanobody, independent of the constant region.

67
Q

What species are heavy chain antibodies present in?

A

Camelids - camels, llamas, alpacas.
Sharks.

68
Q

How can nanobodies for a particular antigen be isolated?

A
  1. Immunise llama with antigen of interest.
  2. Heavy chain antibodies against the antigen will be raised in llama.
  3. Blood is drawn from the llaama, and DNA encoding the heavy chain antibodies is isolated from llama B-cells.
  4. Use phage display to identify the particular nanobodies which bind the antigen of interest and amplify them in E. coli.
69
Q

Give an example of a nanobdy which binds to CXCR4. How can binding be detected?

A

VUN400.

The sequence for HiBiT can be added between a Myc tag and a His tag on its C terminus.
If CRCX4 is encoded to express LgBiT on its N terminus, binding of this nanobody to loop 2 of CRCX4 allows the 2 subregions recomplement and form nanoluciferase. A luminescence signal can be detected upon binding of furimazine to the complex, indicating binding of VUN400 to CXCR4.

70
Q

What is useful about detection of binding of VUN400-HiBiT to CXCR4?

A

Binding of VUN400-HiBiT is inhibited by orthosteric and allosteric binding to CXCR4. Therefore, the absence of luminescence can indicate CXCR4 ligand binding.

71
Q

What is the main advantage of nanobodies over antibodies?

A

Smaller in size (15kDa vs 150 kDa) so can penetrate samples better so can reach antigens in weakly vascularised or poorly accessible regions.

72
Q

What is P2Y12 (aka P2T) and what does it do (3 things)?

A

A Gi coupled receptor in platelets.

When stimulated by ADP, its amplifies signals of other receptors such as P2Y1.

It reduces adenylyl cyclase activity thus reducing cAMP production and subsequently protein kinase A activation.

It stimulates PI3 kinase, Rap proteins, and phosphorylation by AKt.

73
Q

What is P2Y1 and what does it do?

A

A GQ coupled receptor, which, upon stimulation by ADP, mobilises intracellular calcium within the platelet. This causes changes in platelet shape, platelet aggregation and platelet secretion.

74
Q

What is the effect of ATP and ADP on P2Y1 and P2Y12?

A

ADP is an agonist at both.
ATP antagonises P2Y12 but acts as a partial agonist as P2Y1.

75
Q

Why is P2Y12 a good target for preventing thrombosis?

A

P2Y12 activation increases platelet activity (clotting), so antagonists could be used for antithrombotic treatment.

Lack of P2Y12R (either in KO mice or in humans with a deficiency disorder) result in excessive bleeding, so must play a key role in thrombosis regulation.

It is predominantly expressed in platelets, which minimises off-target side effects.

76
Q

What role do platelets play in tumour metastasis?

A
  1. Tumour cell binds to platelets in blood stream.
  2. ATP is released from tumour-bound platelets.
  3. ATP acts on P2Y2 receptors on endothelial cells, causing the barrier between adjacent endothelial cells to open up and allow the tumour cells to leave the vessel lumen and infilitrate surrounding tissues.
77
Q

How does apyrase prevent platelet dependent facilitation of tumour cell transmigration?

A

Apyrase catalyses the hydrolysis of ATP to ADP (and ADP to AMP). This reduces the release of ATP from platelets and the subsequent facilitation of tumour infiltration into tissue.

78
Q

Describe 2 way knockout mice were used to support the theory of P2Y2’s role in metastasis.

A
  1. Knockout of Munc13-4 (exocytosis priming protein). This prevented exocytosis of ATP from platelets and therefore activation of endothelial P2Y2 receptors. This resulted in no enhancement of tumour transmigration across endothelial cells by platelets.
  2. Knockout of P2Y2 (and other similar endothelial receptors). Tumour cell metastasis was reduced in P2Y2 KO mice, but not in mice with knockout of other similar endothelial receptors.