SUMMARY QUESTIONS Flashcards

1
Q

State the overall function of the cell-surface membrane

A

To control the movement of substances in and out the cell

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2
Q

State which end of the phospholipid molecules lies towards the inside of the cell-surface membrane

A

Hydrophobic tail

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3
Q

State through which molecules in the CSM each of the following are likely to pass in order to get in or out of a cell
A: a molecule that is soluble in lipids
B: a mineral ion

A

A: phospholipid
B: protein (carrier or channel)

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4
Q

From your knowledge of the CSM, suggest 2 properties that a drug should possess if its to enter a cell rapidly

A
  • lipid-soluble
  • small in size
  • have no electrical charge (or if it does = charge should be opposite to that on the protein channel)
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5
Q

State factors that affect the rate of diffusion

A
  • concentration gradient
  • surface area over which diffusion takes place
  • thickness of exchange surface
  • temperature
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6
Q

Contrast facilitated diffusion and diffusion

A

Facilitated diffusion only occurs at channels on the membranes where there are special protein carrier molecules

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7
Q

Explain why facilitated diffusion is a passive process

A
  • there is no ATP from respiration use din the process
  • the only energy is the in-built (kinetic) energy of the molecules themselves
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8
Q

Glucose molecules are transported into cells through the pores in the proteins that span the phospholipid bilayer. Explain why they don’t pass easily through the phospholipid bilayer

A
  • Only lipid-soluble substances diffuse across
  • water-soluble soluble substances like glucose diffuse only very slowly
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9
Q

List 2 changes to the structure of CSMs that would increase the rate at which glucose is transported into a cell

A
  • increase its surface area with microvilli
  • more proteins with pores that span the phospholipid bilayer
  • (note that thickness of CSM membrane doesn’t vary to any degree)
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10
Q

Oxygen is required by cells for respiration. This diffuses into the blood through the epithelial layers of the alveoli and blood capillaries. Calculate by how much each of the following changes would increase or decrease the rate of diffusion of oxygen:
A - the SA of the alveoli is doubled
B - the SA of the alveoli is halved and the oxygen concentration gradient is doubled
C - the oxygen concentration gradient is halved and the total thickness of the epithelial layers is doubled
D - The oxygen concentration of the blood is halved and the carbon dioxide concentration of the alveoli is doubled

A

A - x2
B - no change
C - 1/4
D - x2 (the CO2 concentration is irrelevant)

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11
Q

Explain what is meant by a selectively permeable membrane

A

A membrane that is permeable to water molecules (and a few other small molecules) but not to larger molecules

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12
Q

Under standard conditions of pressure and temperature, what is the water potential of pure water

A

0

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13
Q

Four cells have the following water potentials:
Cell A = -200 kPa
Cell B = -250 kPa
Cell C = -100 kPa
Cell D = -150 kPa
Determine the order in which the cells have to be placed for water to pass from one cell to the next if they are arranged in a line

A

C, D, A, B

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14
Q

Explain why an animal cell placed in pure water bursts while a plant cell placed in pure water doesn’t

A
  • Both cells have a lower water potential than pure water and so water enters them by mitosis
  • the animal cell is surrounded only by a thin CSM and so it swells until it bursts
  • the plant cell is surrounded by a rigid cellulose cell wall
  • Assuming the cell is turgid, water cannot enter as the cellulose cell wall prevents the cell expanding and hence it bursting
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15
Q

Plant cells that have a water potential of -600 kPa are placed in solutions of different water potentials. Determine in each of the following cases whether, after 10 mins, the cells would be turgid, plasmolysed or at incipient plasmolysis
A - Solution A = -400 kPa
B - Solution B = -600 kPa
C - solution C = -900 kPa
D - Solution D = pure water

A

A = turgid
B = incipient plasmolysis
C = plasmolysed
D = turgid

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16
Q

A - Solution A = -400 kPa
B - Solution B = -600 kPa
C - solution C = -900 kPa
D - Solution D = pure water
—> an animal cell with a water potential of -700 kPa was placed in each of the solutions. deduce in which solutions the cell is likely to burst

A

All solutions except C

17
Q

State 1 similarity and 1 difference between active transport and facilitated diffusion

A
  • Similarity: both use carrier proteins in the plasma membrane
  • difference: active transport requires energy (ATP) / occurs against a concentration gradient
18
Q

The presence of many mitochondria is typical of cells that carry out active transport. Explain why

A
  • Active transport requires energy in the form of ATP
  • Mitochondria supply ATP in cells and therefore they are numerous in cells carrying out active transport
19
Q

In the production of urine, glucose is initially lost from the blood but is then reabsorbed into the blood by cells in the kidneys. Explain why it is important that this reabsorption occurs by active transport rather than by diffusion

A
  • Diffusion, at best, can only reabsorb 50% of the glucose lost from the blood
  • the other 50% will be lost from the body
  • Active transport can absorb all the glucose, leaving none to be lost from the body
20
Q

State 3 ways in which the rate of movement across membranes can be increased

A
  • by increasing the concentration gradient either side of it
  • by increasing the SA
  • by increasing the density of protein channels (carrier proteins)
21
Q

Explain why the term ‘co-transport’ is used to describe the transport of glucose into cells

A

Because glucose molecules and sodium ions move into the cells coupled together

22
Q

In each of the following events in the glucose co-transport system, state whether the movements are active or passive
A - sodium ions move out of the epithelial cell
B - sodium ions move into the epithelial cell
C - glucose molecules move into the epithelial cell

A

A = active
B = passive
C = passive