# Test 2 Flashcards Preview

## Game Theory > Test 2 > Flashcards

Flashcards in Test 2 Deck (14)
0
Q

SFGWT

A

Rules of a TFGWT except axiom 5 May or may not be satisfied

1
Q

TFGWT rules

A

1- there are two players, I and II, who alternate
2- no random mechanisms
3- whenever a play ends exactly one winner exists
4- each play ends after finitely many moves
5- in any moment, in any play, there are finitely many options for a next legal play

2
Q

Solution and value

A

Row has a pure or mixed strategy S giving Row an expected value of V or more regardless of Col’s response.

• same situation except for Col
• then we say (S,T,V) is a solution of the game
3
Q

Rules for Supergame

A

1-on first move, I chooses a TFGWT
2- player 2 goes first in a play of the subgame G
3- they continue to play the subgame G with II playing I’s role and vice versa
4- whoever wins the play of the subgame wins the play of Supergame

4
Q

Rules of Hypergame

A

Same as Supergame except they name a SFGWT on first move

5
Q

A

A strategy profile in a 0 sum game in which neither player can better their payoff by unilaterally switching profiles

6
Q

Minimax Theorem

A

Every 0 sum game has a solution

7
Q

Mani ax method

A

Maximin- the maximum of Row’s minimum

Minimax- the minimum of Col’s maximum

8
Q

Expected value

A

P(E1)(a2)+p(E2)(a2)

9
Q

Konig’s Infinityy Lemma

A

No tree T can satisfy all 3 properties
1- every fork in T is finite in length
2- every branch in T is finite in length
3- T has infinitely many nodes
Variant 1- every tree satisfying both 1 and 2 violates 3
Variant 2- every tree satisfying 1 and 3 violates 2

10
Q

Zermelo’s Theorem

A
• if G is any TFGWT then I has a W.S. For G or II does
Proof- by GTL, T has finitely many nodes
• label each terminal node with a * or \$ using ax 3
• moves labels up, step-by-step ax 1 and 2
• finitely many steps for backwards induction, GTL
• symbol assigned to top node of T has WS in game G
11
Q

Game Tree Lemma

A

For each TFGWT G, G’s game tree T has finitely many nodes
Proof- as TFGWT we know axiom 4
- we know plays of G correspond to branches finite (KIL II)
- we also know axiom 5
- option correspond to fork in T, finite (KIL I)
- T satisfies I and II of KIL, III fails- finite nodes altogether

12
Q

Hypergame theorem 1 positive

A

HG is a SFGWT

• rules A and B tell us they alternate 1st and 2nd moves, other moves are in SFGWT so alternate
• no random, rules A, subgame is SFGWT no ran
• end of subgame, a SFGWT, unique winner, winner of HG, rule D
• play of HG is a SFGWT preceded by a single game-naming move, play ends after finite moves, play is SG is 1 move longer 1+finite #= finite #
13
Q

Hypergame Theorem 2 negative

A

HG is not a SFGWT
HG does not satisfy axiom 4 because it is legal to say HG on 1st move because it is a SFGWT. For move two it can be named again because of the positive version proving it is a SFGWT. This pattern can go on forever failing axiom 4.