Test 3 Flashcards

(7 cards)

1
Q

Disproportionation

A

Occurs when the standard potential on the right is higher than the left.
A redox rxn where 1 species converts to 2 with a higher and lower oxidation number

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2
Q

Comproportionation

A

Occurs when the standard potential on the left is higher than the right.
A redox rxn where 2 species of a high and low oxidation number converts to 1 with a oxidation number in between those two.

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3
Q

Applications of X-ray diffraction

A

ID unknown materials
Determine sample purity
Determine crystal sizes
Determine structure
Monitor phase changes

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4
Q

Nuclear Magnetic Resonance (NMR)

A

Determination of molecular structures in solutions and pure liquids
Provides better info abt shape and symmetry
Can be used to follow reactions
Cannot provide detailed bond distance and angle info like x-ray

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5
Q

Atomic Absorption

A

Absorbing species are free atoms or ions
See sharp lines instead or broader bands
Absorption Spectroscopic methods vary by how the analyte/ions are converted to free/ unbound ions

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6
Q

Review Latimer diagrams

A

You have to fill it out

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7
Q

Review Frost diagrams

A

The most stable oxidation state is the point that lies the lowest.
Larger slope = higher standard potential, and vice versa
Com will occur when the species is below the straight line
Dis will occur when the species is above the straight line

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