Thermochemistry Properties Flashcards

(46 cards)

1
Q

Bent (4 ED)

A

Tetrahedral arrangement:
- 4 ED
- 2 B
- 2 NB
- 109.5°

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2
Q

Trigonal Pyramid

A

Tetrahedral arrangement:
- 4 ED
- 3 B
- 1 NB
- 109.5°

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3
Q

Tetrahedral

A

Tetrahedral arrangement:
- 4 ED
- 4 B
- 0 NB
- 109.5°

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4
Q

Bent (3 ED)

A

Trigonal Planar arrangement:
- 3 ED
- 2 B
- 1 NB
- 120°

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5
Q

Linear

A

Linear arrangement:
- 2 ED
- 2 B
- 0 NB
- 180°

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6
Q

Trigonal Planar

A

Trigonal Planar arrangement:
- 3 ED
- 3 B
- 0 NB
- 120°

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7
Q

Molecular structure

A

Type of solid: Molecular

Particle: Molecules

Force: Weak intermolecular forces

Strength: Weak

Molecular substances are made up of discrete molecules held together with weak intermolecular forces. These molecules are not charged.

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8
Q

Metal structure

A

Type of solid: Metal

Particle: Atoms

Force: Metallic bonds

Strength: Strong

Metals are made up of a 3D lattice with strong non-directional electrostatic attractions between the positively charged metal nuclei and the sea of delocalised valence electrons called metallic bonding.

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9
Q

Ionic structure

A

Type of solid: Ionic

Particle: Ions - cations and anions

Force: Ionic bonds

Strength: Strong

Ionic substances are made up of a 3D lattice with alternating positive and negative ions held together with strong directional ionic bonds. The ions are fixed in place.

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10
Q

Diamond structure

A

Type of solid: Covalent network

Particle: Atoms

Force: Covalent bonds

Strength: Strong

Diamond is a large 3-D network of atoms bonded together by strong covalent bonds. Each carbon atom is covalently bonded to 4 other carbon atoms forming a strong 3-D covalent network lattice with no free electrons.

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11
Q

Silica structure

A

Type of solid: Covalent network

Particle: Atoms

Force: Covalent bonds

Strength: Strong

Silica is a large 3-D network of atoms bonded together by strong covalent bonds. Each silicon atom is covalently bonded to 4 oxygen atoms and each oxygen atom is covalently bonded to two silicon atoms in a 3-D covalent network lattice with no free electrons.

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12
Q

Graphite structure

A

Type of solid: Covalent network

Particle: Atoms

Force: Covalent bonds

Strength: Strong

Graphite is a large 3-D network of atoms bonded together by strong covalent bonds. Each C atom in graphite is covalently bonded to 3 other carbon atoms resulting in hexagonal rings which are arranged in layers. Each C atom, therefore, has a delocalised valence electron. There are weak inter-layer bonds formed between the delocalised electrons of two consecutive layers.

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13
Q

Molecular solids properties

A

> Hardness:
Molecular solids are softer than ionic, metallic, and covalent network solids due to weak intermolecular forces.

> Forces:
London dispersion forces (weakest), dipole-dipole interactions, and hydrogen bonds hold molecules together.

> Brittleness:
- Molecules held by weak forces (e.g., van der Waals, dipole-dipole) make molecular solids brittle.
- Lack of delocalized electrons prevents easy rearrangement, so molecular solids break under stress.

> Density:
- Molecular solids have lower densities due to weaker intermolecular forces that prevent tight packing of molecules.

> Melting & Boiling Points:
- Molecular solids have low melting and boiling points because of weak intermolecular forces.
- Larger molecules with stronger forces (e.g., hydrogen bonding) have higher melting and boiling points.

> Conductivity:
- Molecular solids are poor conductors. - Electrons are localized, preventing electrical and thermal conductivity in molecular solids.

> Solubility:
- Polar molecular solids dissolve in water due to dipole-dipole interactions; non-polar solids generally do not.
- Substances with hydrogen bonds (e.g., alcohols) dissolve well in water.

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14
Q

Ionic solids properties

A

> Hardness:
- Ionic solids are generally harder than molecular solids due to strong electrostatic attraction between oppositely charged ions.
- Ionic bonds require significant energy to break, contributing to their hardness.
- Softer than covalent network solids (e.g., diamond).

> Brittleness:
- Rigid lattice structure of alternating positive and negative ions.
- Stress shifts ions, aligning like charges, leading to repulsion and cracks (brittle, not malleable).

> Density:
- High density due to close packing in the lattice and the mass of the ions.
- Denser than molecular solids, but comparable to metallic and covalent network solids.

> Melting/Boiling Points:
- High due to strong ionic bonds, requiring significant energy to break.
- Higher than molecular solids, comparable to metals and covalent network solids.

> Electrical Conductivity:
- Non-conductive in solid form (ions fixed in place).
- Conductive when molten or dissolved (ions free to move).

> Solubility:
Soluble in water! water molecules surround and separate ions (hydration).

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15
Q

Metallic solids properties

A

> Hardness:
- Metals are generally hard due to strong metallic bonds, but hardness varies depending on the specific metal and its atomic arrangement.
- Unlike brittle ionic and covalent solids, metallic bonds allow ions to move without breaking.

> Malleability and Ductility:
Metals are malleable (can be hammered) and ductile (can be drawn into wires) because delocalised electrons enable metal atoms to slide past each other.

> Density:
Metallic solids typically have high densities due to the closely packed lattice structure of metal atoms.

> Melting and Boiling Points:
Metals have high melting and boiling points due to the strong attraction between metal ions and delocalised electrons, requiring large amounts of energy to break.

> Conductivity:
Metals are excellent conductors of electricity and heat because of the free movement of delocalised electrons.

> Solubility:
Most metals are not soluble in water because the strong metallic bonds cannot be overcome by water’s polar molecules.

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16
Q

Covalent network: diamond properties

A

> Hardness:
The rigid, continuous network of covalent bonds throughout the structure makes diamond extremely hard, as breaking these bonds requires a lot of energy.

> Melting Point:
The strong covalent bonds between carbon atoms throughout the lattice result in an extremely high melting point, as significant energy is needed to break all the bonds.

> Conductivity:
Diamond does not conduct electricity because all electrons are involved in covalent bonding, leaving no free electrons to carry charge.

> Brittleness:
Despite its hardness, diamond is brittle; applying force breaks the covalent bonds rather than allowing the structure to deform.

> Insolubility:
Diamond is insoluble in water because the strong covalent bonds cannot be broken by water molecules, preventing it from dissolving.

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17
Q

Covalent network: silica properties

A

> Hardness:
Silicon is hard because of its strong covalent bonds, although not as hard as diamond due to differences in atomic structure and bond strength.

> Melting Point:
Silicon has a very high melting point because breaking the covalent bonds throughout the lattice requires a large amount of energy.

> Conductivity:
- Silicon is a poor conductor of electricity at room temperature because, like diamond, it lacks free electrons.
- However, when heated, some electrons gain enough energy to move, making it a semiconductor.

> Brittleness:
Silicon is brittle as its rigid structure causes the covalent bonds to break under stress, rather than allowing deformation.

> Insolubility:
Silicon is insoluble in water, as the covalent bonds in the lattice structure cannot be broken by interactions with water molecules.

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18
Q

Covalent network: graphite properties

A

> Hardness:
Graphite is soft because the weak Van der Waals forces between layers allow them to slide over each other easily, making it slippery and soft compared to diamond.

> Melting Point:
Strong covalent bonds within the layers require a high amount of energy to break, resulting in a high melting point.

> Conductivity:
Graphite conducts electricity because each carbon atom has one free electron that can move between layers, allowing for the flow of charge.

> Brittleness:
Graphite is brittle when force is applied perpendicular to the layers, as this disrupts the weak Van der Waals forces between the layers.

> Insolubility:
Graphite is insoluble in water because water molecules cannot break the strong covalent bonds within the layers.

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19
Q

M

A

= molar mass (m/n)

20
Q

n

A

= number of moles (m/M)

21
Q

m

22
Q

One mole

A

=6.022 × 10²³

23
Q

Comparing Polarities

A

There are _____ ______ _____ bonds because the _____ atom is more electronegative than the ______ atom. Due to the _______ shape, the ________ bonds are ________ arranged around the central _____ atom. Therefore the bond dipoles ______ cancel each other out and thus _____ is a __________ molecule.

24
Q

Comparing Molecules

A

There are ____ areas of electron density around the central ___ atom. The electrons repel each other with maximum separation and minimal repulsion, forming a _______ arrangement. There are ______ areas of bonded electrons and ____ lone pairs making a ______ shape. This means a bond angle of ________°.

25
Calculating the number of neutrons
mass number - number or protons
26
Lewis structure exceptions to octet rule
- Hydrogen never goes in the middle - Elements more than atom 14 can have more than 8 electrons - Hydrogen is happy with just 2e- - Beryllium is happy with just 4e- - Boron is happy with just 6e- - Every other element needs 8e-
27
describe and explain the shapes of molecules with up to 6 areas of negative charge around the central atom
Shapes of Molecules (VSEPR – up to 6 negative areas) 2 regions: Linear, 180° 3 regions: Trigonal planar, 120° 4 regions: Tetrahedral, 109.5° 5 regions: Trigonal bipyramidal, 90° & 120° 6 regions: Octahedral, 90° Lone pairs adjust the shape (e.g., bent, trigonal pyramidal).
28
state the bond angles in molecules with up to 6 areas of negative charge around the central atom
Bond Angles (VSEPR - up to 6 negative areas) Linear: 180° Trigonal Planar: 120° Tetrahedral: 109.5° Trigonal Bipyramidal: 90°, 120° Octahedral: 90°
29
equation for first ionisation energy of an element
Example (sodium): Na(g) → Na⁺(g) + e⁻
30
equation for standard enthalpy of fusion, Δ fusH°
Example (ice to water): H₂O(s) → H₂O(l)
31
equation for standard enthalpy of vaporisation, Δ vapH°
Example (water): H₂O(l) → H₂O(g)
32
equation for standard enthalpy of sublimation, Δ subH°
Example (iodine): I₂(s) → I₂(g)
33
equation for standard enthalpy of combustion, Δ cH°
Example (methane): CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)
34
equation for standard enthalpy of formation, ΔfH°
Example (carbon dioxide): C(s) + O₂(g) → CO₂(g)
35
Calculating bond energy
ΔH= bond breaking - bond making
36
Calculating RAM (relative atomic mass - showed by the periodic table) of elements
To find the RAM of a specific element: 1. Find all the isotopes of said element. 2. Find the weighted averages of each isotope individually: This is the isotope elements mass number (A) x its NA percentage. 4. Take this result, along with (if applicable) the result for any other isotopes, and add them together. (Add the weighted averages found from each isotope of the element together. 5. Equal RAM of that element Example: Find the RAM of Cl2 gas. Cl2 gas is a mixture of two isotopes: Chlorine-35 & Chlorine-37 ~ Cl-35 Mass number (A) = 35 NA = 75.77% (75%) ~ Cl-37 Mass number (A) = 37 NA = 24.23% (25%) RAM for Cl = (NA% x A) + (NA% + A) = ! (0.75 x 35) + (0.25 x 37) = 35.50 Relative atomic mass of Cl2 = 35.50 Note: Length of equation depends on number of isotopes, chlorine has two. Thus, two weighted averages are added together.
37
Four atomic sublevels:
low energy < high energy Es < Ep < Ed < Ef - Each sublevel holds a different max number of electrons: S = 2 electrons p = 6 electrons d = 10 electrons f = 14 electrons "Stop pretending donkeys fly!"
38
Principle energy levels
Each principle energy level (PEL) contains a different number of sublevels. PEL 1 = 1s = 2 e- max PEL 2 = 2s, 2p = 8 e- max PEL 3 = 3s, 3p, 3d = 18 e- max PEL 4 = 4s, 4p, 4d, 4f = 32 e- max Formula to calculate max no. electrons? 2n² NOTE: n= principle energy level no.
39
Electron orbital aspects
Each energy sublevel has one or more orbitals, each of which can contain a maximum of two electrons. Sub-level "s" = 1 orbital = 2 e- max (1 x 2) Sub-level "p" = 3 orbitals = 6 e- max (3 x 2) Sub-level "d" = 5 orbitals = 10 e- max (5 x 2) Sub-level "f" = 7 orbitals = 14 e- max (7 x 2)
40
Shape of 's' orbitals
* s - One spherical in shape orbital. - spherically symmetric. - able to hold a maximum of 2 electrons with opposite spins. * Three things happen to 's' orbitals as "n" increases: 1. They become larger, extending farther from the nucleus. 2. They contain more nodes. This is similar to a standing wave that has regions of significant amplitude separated by nodes, points with zero amplitude. 3. For a given atom, the s orbitals also become higher in energy as n increases because of their increased distance from the nucleus.
41
Shape of 'p' orbitals
* px, py, pz - Three dumbbell shaped orbitals. - aligned along perpendicular axes. - each orbital able to hold a maximum of 2 electrons (total of 6 electrons).
42
Shape of 'd' orbitals
* dxy, dyz, dxz, dx²-y², and dz² - Five daisy-like or four leaf clover shaped orbitals, with the exception of one, the dz² orbital, which looks like the donut with a lobe above and below. - each orbital able to hold a maximum of 2 electrons (total of 10 electrons).
43
Shape of 'f' orbitals
*fz³, fyz², fxz², fxyz, fz(x²-y²), fy(3x²-y²), fx(x²-3y²). - Seven ?? shaped orbitals - Each f orbital has three nodal surfaces, so their shapes are complex. - each orbital able to hold a maximum of 2 electrons (total of 14 electrons).
44
Transition metal ions and colours
- If 3d orbitals of a transition metal cation are PARTIALLY FILLED, then the ion will exhibit COLOUR. [ 3d 1-9 = partially filled ] E.g. * Cu2+ ions are blue: Cu2+[Ar]3d9 - If the 3d orbitals of a transition metal cation are EMPTY or COMPLETELY FILLED, then the ion will exhibit NO COLOUR, and the solid compound is white. [ 3d10 = full no 3d = empty ] E.g. * Cu+ ions are c/l (Cu+[Ar]3d10) = compound is white * Sc3+ ions are c/l (Sc3+ [Ar]) = compound is white * Zn2+ ions are c/l (Zn2+[Ar]3d10) = compound is white
45
Determining the effective nuclear charge (Zeff)
Zeff = atomic number (z) - the no. of inner electrons. - Effective nuclear charge increases across a period and stays the same down a group.
46
Atomic radius
Atomic radius is measured by halving the distance between the nuclei of neighbouring metallic atoms or two identical non-metal atoms in a diatomic covalent molecule. Size of atom depends on: 1. number of occupied energy levels. 2. number of protons in the nucleus. 3. sheilding of the outermost valence electrons by the inner energy levels from the positive nucleus. This reduces the attraction between the valence electrons and the nucleus. 4. Electron repulsion