Unit 10 thermodynamics Flashcards

1
Q

what are the steps to solve this problem: You have two identically prepared Styrofoam cups, each filled with the same volume of 20 ̊C water and a thermometer. (This arrangement is known as a“coffee cup calorimeter”.) Into cup #1, you drop 3.00 g of aluminum (c = 0.90 J/g∙K) that is heated to 80 ̊C. Into cup #2, you drop 3.00 g of iron (c = 0.45 J/g∙K)
that is heated to 80 ̊C. Which block (aluminum or iron) gives off more heat as it cools to the temperature of the water?

A
  1. Calculate amount of heat given off by the aluminum block using the Q=mcdelta T formula
  2. Calculate amount of heat given off by an iron using the Q=mcdelta T formula
  3. pick the element that is more negative
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1
Q

what are the steps to solve this problem: A layer of copper welded to the bottom of a skillet weighs 125 g.
How much heat is needed to raise the temperature of the
copper layer from 25°C to 300.°C? The specific heat capacity (c)
of Cu is 0.385 J/g∙K

A
  1. Convert grams to kg
  2. Find the change in temperature in kelvin
  3. Use the formula for heat transfer Q=mcdeltaT isolated for Q. plug in the numbers and find the q value
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2
Q

what are the steps to solve this problem:The temperature of the water in cup #1 increases from 20.0 ̊C to a final temperature of 28.2 ̊C as the aluminum cools?

A
  1. simply subtract the final temperature from the initial temperature
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3
Q

what is the purpose of calorimetry?

A

Measure the Heat of a Chemical or Physical Change

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4
Q

how is heat measured in calorimetry?

A

indirectly by a calorimeter

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5
Q

if a reaction produces heat, what happens to the temperature of its surroundings?

A

the temperature of the surroundings increases

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6
Q

if a reaction absorbs heat, what happens to the temperature of its surroundings?

A

the temperature of the surroundings decreases

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7
Q

what does coffee cup calorimetry mean?

A

used to measure enthalpy changes in chemical processes

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8
Q

what are reactions and physical transformation like in calorimetry mean?

A

in an insulated container at constant pressure in a bath (usually water) of known heat capacity

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9
Q

what is the significance of heat capacity?

A

provides a link between changes in temperature and heat gained
or lost, from which you can determine the enthalpy change of the system.

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10
Q

what is the formula for finding heat capacity?

A

heat capacity=qcal/deltaTcal
where q cal is the amount of heat that must be added to the object to its temperature by delta T

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11
Q

what are the steps to solve this problem: You heat up 22.05 g of a solid to 100.00 °C and add it to a “coffee cup” calorimeter which
contains 50.00 g water. The water temperature changes from 25.10 °C to 28.49 °C. Find the specific heat capacity of the solid.

A
  1. Calculate heat gained by water using the formula Q=mcdeltaT and solving for q
    q=(50g4.184J/gC)(28.49-25.10)=710.7J
  2. Calculate the heat lost by the solid which is equal to the heat gained by water qsolic=-qwater
    -710.7J
  3. Calculate the change in temperature of the solid
    deltaT=100-28.49=71.51
  4. Calculate the specific heat capacity
    c=-710.7J/22.05g71.51C)=0.449J/gC
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12
Q

what are the two major types of calorimetry?

A
  1. Constant Pressure or “Coffee Cup” Calorimetry
  2. Constant Volume or “Bomb” Calorimetry:
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13
Q

what is the formula for Constant Pressure or “Coffee Cup” Calorimetry?

A

qp = deltaE + PdeltaV

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14
Q

what is the formula for Constant volume or “Coffee Cup” Calorimetry?

A

qv = deltaE + PdeltaV=deltaE

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15
Q

which types of reactions are Bomb calorimeters are commonly used to
measure?

A

heat combustion reactions

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16
Q

how is the heat flown into
the calorimeter and the heat of the reaction related?

A

qrxm=-qcalorimeter
they are them same of the qcalorimeter is negative

17
Q

what are the steps to solve this problem: When 0.500 g of ethanol, C2H6O, is burned in a bomb
calorimeter, the temperature of both the water and the calorimeter rise by 9.15oC. Assuming that the bath
contains 250.0 g of water and that the heat capacity for the calorimeter is 575 J/oC, calculate how much heat is created in this reaction?

A
  1. Calculate heat absorbed by water
    Qwater in calorimeters=(mass of waterdeltaT)(cwater)
    qwater=(250g
    9.15C)(4.184L/g*K)=9571
  2. Calculate heat absorbed by calorimeter
    qrxn=qcalorimeter=-[9571+575L/gK9.15C]=-14832J=-14.8
    kJ
18
Q

how do you solve a problem where you need to calculate deltaH (in kJ) for this rxn using two reactions lined up under the other?

A
  1. cross out intermediates
  2. rewrite the equation with whatever is left
19
Q

what happens to delta H when you reverse a reaction?

A

it turns negative

20
Q

what happens to delta H when you half a reaction?

A

you must also half delta H

21
Q

how to find the delta H for the summed of two reactions given their deltaH?

A

manipulate the two equations to get the desired equation while changing the delta H’s according. them add their delta H

22
Q

What is thermodynamics?

A

The study of energy and its conversion from one form to another

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