Unit 5 - chatgpt Flashcards

(55 cards)

1
Q

What are the two main stages of photosynthesis?

A

Light-dependent reaction (LDR) and Light-independent reaction (Calvin Cycle).

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2
Q

Where does the light-dependent reaction take place?

A

In the thylakoid membranes of the chloroplast.

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3
Q

What are the main products of the LDR?

A

ATP, reduced NADP (NADPH), and O2 (as a byproduct).

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4
Q

How is ATP produced in the LDR?

A

Through chemiosmosis:
electrons move through the electron transport chain,
releasing energy used to pump protons by active transpot into the thylakoid space from stroma.
Protons diffuse into stroma through ATP synthase,
synthesizing ATP from ADP and Pi.

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5
Q

What happens to water in the LDR?

A

It undergoes photolysis to produce electrons (for ETC), protons (for NADP reduction), and O2 (waste).

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6
Q

Where does the light-independent reaction occur?

A

In the stroma of the chloroplast.

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7
Q

What molecule does CO2 combine with in the Calvin cycle?

A

RuBP (Ribulose bisphosphate), catalysed by Rubisco.

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8
Q

What are the products of the Calvin Cycle used for?

A

TP (triose phosphate) is used to form glucose and regenerate RuBP.

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9
Q

What limits the rate of photosynthesis?

A

Light intensity, CO2 concentration, and temperature.

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10
Q

Where does glycolysis occur?

A

In the cytoplasm.

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11
Q

What are the products of glycolysis?

A

2 pyruvate, 2 ATP (net), and 2 NADH.

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12
Q

What happens in the link reaction?

A

Pyruvate is decarboxylated and oxidised to form acetate, which combines with CoA to form acetyl-CoA. NAD+ is reduced to NADH.

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13
Q

Where does the link reaction occur?

A

In the mitochondrial matrix.

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14
Q

What are the key stages of the Krebs Cycle?

A

Acetyl-CoA combines with oxaloacetate to form citrate (a 6-carbon molecule).
Citrate undergoes dehydrogenation (producing NADH) and decarboxylation (releasing CO2) to form a 5-carbon intermediate.
This intermediate undergoes another decarboxylation and dehydrogenation, producing NADH and releasing CO2, forming a 4-carbon intermediate.
The 4-carbon intermediate is converted back to oxaloacetate, completing the cycle and regenerating oxaloacetate.
This oxidation produces NADH and FADH2 and ATP

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15
Q

When does substrate-level phosphorylation occur in respiration?

A

In the Krebs cycle when a 4-carbon intermediate is converted to another 4-carbon compound.
Glycolysis - TP oxidised to pyruvate

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16
Q

Where does oxidative phosphorylation occur?

A

In the inner mitochondrial membrane.

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17
Q

How is ATP produced during oxidative phosphorylation?

A

Enzymes remove the hydrogen from reduced NAD/FAD and split it into H+ (proton) and a high energy e-.
e- flow through the ETC of carriers (oxidation-reduction reactions) releasing energy at each lower energy level.
Energy released actively transports H+ across inner membrane into inter membrane space.
H+ diffuse down an electrochemical gradient back into the matrix through ATP synthase synthesising ATP from ADP and Pi by chemiosmosis.
Reduced NAD powers 3 pumps, reduced FAD powers 2 pumps.
O2 acts as the final H+ and e- acceptor forming H2O which maintains the flow of electrons.

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18
Q

What acts as the final electron acceptor in the ETC?

A

Oxygen. It combines with electrons and protons to form water.

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19
Q

What happens under anaerobic conditions in animals?

A

Pyruvate is reduced to lactate by accepting H from NADH, regenerating NAD+ so glycolysis can continue.

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20
Q

What happens under anaerobic conditions in yeast/plants?

A

Pyruvate is decarboxylated to ethanal, then reduced to ethanol using NADH, regenerating NAD+.

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21
Q

How are lipids used in respiration?

A

Lipids are hydrolysed into glycerol (converted to TP) and fatty acids (converted to acetyl-CoA).

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22
Q

How are proteins used in respiration?

A

Proteins are deaminated. The remaining keto acids enter glycolysis or the Krebs cycle depending on their structure.

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23
Q

Why do lipids release more energy than carbohydrates?

A

They have more C-H bonds, so more ATP is generated from oxidative phosphorylation.

24
Q

Define gross primary production (GPP).

A

The total quantity of chemical energy stored in plant biomass per unit area per unit time.

25
Define net primary production (NPP).
NPP = GPP - respiratory losses (R).
26
Why is most of the energy lost between trophic levels?
Not all biomass is consumed, some is egested, energy lost as heat via respiration, and as excretory products.
27
How can farmers increase energy transfer efficiency?
Reduce respiratory losses by restricting movement, keeping animals warm, selective breeding, controlled diet.
28
What is a food chain?
A sequence of energy transfer between trophic levels.
29
What is biomass?
The total mass of living material in a specific area at a given time.
30
How is biomass measured?
Dry mass per given area, per unit time (e.g., kg m^-2 year^-1).
31
What are saprobiotic organisms?
Microorganisms that feed on dead/decaying matter and release nutrients back into the soil.
32
What is ammonification?
Saprobiotes convert organic nitrogen compounds into ammonia.
33
What is nitrification?
Nitrifying bacteria convert ammonium to nitrites (NO2-) then to nitrates (NO3-).
34
What is nitrogen fixation?
Nitrogen-fixing bacteria (e.g., Rhizobium) convert atmospheric nitrogen (N2) into ammonia.
35
What is denitrification?
Denitrifying bacteria convert nitrates into nitrogen gas under anaerobic conditions.
36
Outline the phosphorus cycle.
Phosphate ions in rocks are released by weathering, absorbed by plants, transferred through the food chain, returned via decay and excretion, and re-deposited in sediments.
37
Explain how reduced NAD and FAD contribute to ATP production in oxidative phosphorylation.
NADH and FADH2 donate electrons to ETC. Energy from electrons pumps H+ across membrane. H+ diffuses back via ATP synthase, driving ATP synthesis.
38
Describe the role of oxygen in aerobic respiration.
Final electron acceptor. Combines with electrons and protons to form water.
39
Explain how farming practices increase productivity.
Fertilisers increase nutrient availability; pesticides reduce losses to pests; selective breeding increases yield.
40
How does deforestation affect the carbon and nitrogen cycle?
Reduces CO2 uptake; less nitrogen returned via decomposition; increases leaching.
41
42
What is the advantage of calculating RF values?
RF values can be compared to known values to identify compounds.
43
Why is the middle of the spot used when calculating the RF value?
It allows a comparison as it standardises readings.
44
Why does the student mark the origin using a pencil rather than ink?
Ink and (leaf) pigments would mix.
45
Why must the solvent front be marked before the paper chromatography dries?
To measure the RF value, the solvent front must be marked before it dries and becomes invisible.
46
What is the purpose of the control tube(s)?
(see above)
47
Why must all solutions be ice cold?
To slow the activity of the enzymes which could damage the chloroplasts.
48
Why must the isolation medium be isotonic?
It has the same water potential as the chloroplasts and therefore prevents the chloroplasts from bursting/shrivelling.
49
Why are leaves blended?
To release chloroplasts by breaking open cells.
50
Why are the blended leaves filtered?
To remove large pieces of cell debris.
51
Why is ammonium hydroxide used as a weedkiller?
It is an electron acceptor, leading to less ATP, less reduced NADP, less light independent reactions, less reduction of GP to TP, less organic products (e.g., glucose), and less respiration.
52
Why is the respirometer apparatus left open for 10 minutes?
Allows apparatus to equilibrate, respiration rate to stabilise, and the organism (e.g., maggot) to get used to the environment.
53
What temperature range would be suitable for respiration and why?
20-40 °C – optimum for respiratory enzymes.
54
Explain why the fluid moves in the respirometer.
Oxygen is taken up by the organism, reducing volume and pressure in the tube, so the fluid moves towards the respirometer.
55
What readings are needed to calculate the volume of oxygen used per hour?
Measure the distance the fluid moves in a set time, the diameter of the capillary tube, and the time taken. Use these to calculate volume per unit time, then scale to per hour.