Week 22: Hardy-Weinberg Flashcards
Question on page 5
Question on page 7
Population:
a group of individuals of the same species living in the same (arbitrarily defined) area.
Members of a population are more likely to breed with each other than with members of another population
Gene pool:
all the alleles of all the genes in all individuals of a
population
Fixed allele:
when all individuals in a population are homozygous for one allele. No other alleles for that locus exist in the population.
Question on page 11
The frequency of a phenotype (i.e., a trait) =
Number of individuals with the phenotype / total number of all individuals
Question on page 13
Question on page 15
The frequency of an allele in a population =
Equation:
page 17 for visuals*
its proportion in a population
number of copies of allele / total number of all copies of all alleles for that gene
Question on page 18
If a population’s expected frequencies match its observed frequencies, and this does not change, then the population is at ______________
equilibrium
The Hardy-Weinberg assumes what is not occuring
- Natural selection
- Genetic drift
- Gene flow
- Non-random mating
- Mutation
The Hardy Weinberg equation:
Let p = frequency (proportion) of the dominant allele
Let q = frequency (proportion) of the recessive allele
p + q = 1
therefore
p^2 + 2pq + q^2 = 1
Question on page 23
The Rule of Multiplication
Explanation on page 25
There are TWO WAYS an individual could inherit one dominant and one recessive allele:
- A sperm carrying a dominant allele (frequency = p) could fertilize an ovum carrying a recessive allele (frequency = q); odds = p*q (Aa)
- A sperm carrying a recessive allele (frequency = q) could fertilize an ovum carrying a dominant allele (frequency = p); odds = q*p (aA) = Aa
The Rule of Addition:
The probability of an event that can occur in two or more different ways is equal to the sum of the individual probabilities of each way
Odds of being a heterozygote are therefore
(p * q) + (q * p) = 2pq
The HW equation only applies to populations that are ……
NOT evolving
Question on page 32
Question on page 34
c) 0.04
q^2= aa
0.2 x 0.2 = 0.04
Question on page 36
e) 96%
p^2 + 2pq = AA
(0.8)^2 + 2(0.8)(0.2) = 0.96
0.96 x 100 = 96%
Causes of evolution:
- Natural selection
- Genetic drift
- Gene flow
- Non-random mating
- Mutation
why does the Hardy weinberg equation no longer predict genotype frequencies accurately when natural selection acts against a trait
When natural selection acts against a particular trait, it disrupts the balance described by the Hardy-Weinberg equilibrium. Natural selection favors certain alleles over others, leading to changes in allele frequencies within the population.
If a trait is under negative selection (disadvantageous), individuals with the corresponding genotype will have reduced fitness and are less likely to survive and reproduce. As a result, the frequency of that genotype will decrease over time, disrupting the equilibrium predicted by the Hardy-Weinberg equation.