Week 6 Seepage Flashcards

(20 cards)

1
Q

How is total vertical stress (σ) at any depth (d) within soil calculated?

A

σ = γ × d, where γ is the unit weight of the soil and d is the depth of soil.

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2
Q

What does total stress (σ) in soil consist of?

A

It consists of stress distributed between the soil skeleton and the pore water in the voids.

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3
Q

What is the formula for total stress in soil considering effective stress and pore water pressure?

A

σ = σ’ + u, where σ’ is effective stress and u is pore water pressure.

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4
Q

When is pore water pressure (u) above zero in soil?

A

Only in saturated soils.

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5
Q

What happens to total stress (σ) if there are no external loads and soil unit weight and depth remain constant?

A

The total stress (σ) remains constant.

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6
Q

How does water flow (seepage) affect total stress (σ)?

A

Seepage changes pore water pressure (u) but not soil depth (d) or unit weight (γ), so total stress remains constant.

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7
Q

How are effective stress (σ’) and pore water pressure (u) related to maintaining total stress (σ)?

A

Any change in pore water pressure (u) must cause a change in effective stress (σ’) to keep total stress constant.

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8
Q

Why is effective stress (σ’) important for soil stability?

A

It governs the stress acting along potential failure surfaces and influences soil shear strength.

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9
Q

What is discharge velocity (v) in soil?

A

v = k × i, where k is the permeability of soil and i is the hydraulic gradient.

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10
Q

What do the Continuity and Laplace equations allow for in seepage analysis?

A

Mathematical determination of water flow through soils.

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11
Q

Why are flow nets constructed in seepage analysis?

A

To graphically determine the flow of water through soils.

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12
Q

What do flow nets represent?

A

Seepage flow in saturated soil only; they do not represent water flow in unsaturated soil or water-only regions.

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13
Q

What does a flow net diagram show?

A

Direction of water flow and head of water within saturated soil.

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14
Q

What is the head difference (h) between upstream and downstream water levels in the example?

A

2.50 m.

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15
Q

How many equipotential drops (Nd) are there in the flow net example?

A

12

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16
Q

How do you calculate the head of water (hP) at a specific point in a flow net?

A

hP = (nd / Nd) × h, where nd is the equipotential number at the point of interest.

17
Q

What is the value of hP at point ‘x’ located between equipotentials 8 and 9?

A

hP = 1.77 m, calculated as (8.5 / 12) × 2.5 m.

18
Q

How is total head (hT) at point ‘x’ calculated?

A

hT = hz + hP, where hz = 5.9 m and hP = 1.77 m. Therefore, hT = 7.67 m.

19
Q

What formula is used to determine pore water pressure (u) at point ‘x’?

A

u = hw × γw, where hw = 7.67 m and γw = 9.81 kN/m³.

20
Q

What is the calculated pore water pressure (u) at point ‘x’?

A

u = 75.24 kN/m².