01 Basic of Navigation Flashcards
ATPL GEN-NAV (256 cards)
A ‘Kilometre’ is a unit of measurement equal to:
a 1/10,000 part of the meridian length from equator to pole.
Position “Elephant Point” is situated at (58°00’N, 135°30’W). Standard time for this location is listed in the Air Almanac as UTC -8. If sunset occurs at 00:57 UTC on 21st January, what is the time of Sunset in LMT?
15:55 on January 20th.
……………………………………….
Sunrise and Sunset times are in Local Mean Time.
Arc to Time Conversion for 135°30’W
= 135.5 x 4 minutes
= 542 minutes
= 9 hours 2 minutes
Conversion is from East to West therefore subtract:
00:57 UTC on 21st January
09:02
15:55 LMT on 20th January
Which statement is correct about the apparent solar day?
The apparent solar day is the period between two successive transits of the true Sun through the same meridian.
The angle between Magnetic North and Compass North is called:
compass deviation
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Magnetic/Compass = deviation. True/Magnetic = variation.
An aircraft is in the position (86ºN, 020ºE). When following a rhumb line track of 085º(T) it will:
fly via a spiral to the North Pole.
Given:
Waypoint 1: 60°S 030°W
Waypoint 2: 60°S 020°W
What will be the approximate latitude shown on the display unit of an inertial navigation system at longitude 025°W?
060°06’S
A nautical mile is equivalent to:
1852 metres
The first law of Kepler states:
Planets move in elliptic orbits with the sun in one of the foci.
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Kepler’s Laws of Planetary motion:
First: The orbit of each planet is an ellipse with the sun at one of the foci.
Second: The line joining the planet to the Sun, known as the radius vector, sweeps out equal area in equal time.
Third: The square of the time the planet takes to go around the Sun (its ‘year’) is proportional to the cube of its mean distance from the Sun.
‘Apparent time’ is:
based on the time of transit of the apparent (or true) Sun.
Isogrivs are lines that connect positions that have:
Isogrivs are lines that connect positions that have:
The duration of civil twilight is the time:
between sunset and when the centre of the sun is 6° below the celestial horizon.
The great circle distance between position A (59°34.1’N 008°08.4’E) and B (30°25.9’N 171°51.6’W) is:
5400 NM
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Note that there is no common longitude, meaning the question can not be a simple change of latitude problem.
There is also no common latitude, meaning the question can not be a simple change of longitude either.
The next check will be the two longitudes. If these add up to 180° and they are in opposite hemispheres (East and West) then they are directly opposite each other.
Provided the two positions are also in the same Northern (or Southern) Hemisphere then the shortest route between the two points will be over the relevant Pole.
Flying north along one meridian to the North Pole and then south along another meridian is a ‘polar transit’.
The simplest method of calculating ‘polar transit’ distances is to:
- Add the two latitudes
- Subtract the sum of the two latitudes from 180°
- Multiply the solution (in degrees) by 60 (minutes) to convert to minutes along a meridian of longitude, and thus into nautical miles
N 59°34.1’ + N 30°25.9’ = 90°
180° - 90° = 90°
90° x 60’ = 5,400’ = 5,400 nm
When proceeding, on a given date, along a parallel towards the East, the moment of sunrise will occur one hour earlier every 15° difference in longitude when it is expressed in:
UTC
A great circle track joins positions A (59°S 141°W) and B (61°S 148°W). How does the great circle track change when flying from A to B?
It increases by 6°.
……………………….
Calculate Earth convergence using the equation Convergence = Chlongº x sine mean lat.
Apply the Earth convergence using the memory aid below:
trackin west tracking east
- / +
—————————- Equator
+ / -
Earth convergence = 7 x sine 60º = 6º
Southern hemisphere and tracking East (westerly longitude decreasing) = Increasing track direction.
The great circle track will increase by 6º.
The time difference in Local Mean Time between sunset at positions A (50°N, 120°E) and B (50°S, 120°E) on the 21st of November is:
some hours and the Sun rises earlier in B than in A.
An aircraft at latitude 02°20’N tracks 360°(T) for 685 km. On completion of the flight the latitude will be:
08°29’N
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A change of latitude of 1° = 60 NM, 1 minute of latitude = 1 NM.
Firstly, convert the ground distance from km into NM.
685 k m ÷ 1.852 = 370 NM (rounded up)
Convert this into minutes of arc.
370 NM = 370’
Convert this into degrees and minutes.
Change of Latitude = 370’ ÷ 60’ = 6°10’
The change of latitude is in a northerly direction (360°T) from a northerly latitude (N02°20’). Therefore, add the change of latitude from the original, known latitude to calculate the new, unknown latitude.
New Latitude = N02°20’ + 6°10’ = 08º30’
New Latitude = N08º29’ closest answer
The north and south magnetic poles are the only positions on the earth’s surface where:
a freely suspended compass needle would stand vertical
What is the change in longitude from point A (N45° E165°30’) to point B (N45° W155°40’)?
38°50’E
An aircraft at position 00°00’N/S 163°27’W flies a track of 225°(T) for 70 NM. What is its new position?
00°49’S 164°16’W
……………………….
The new position is S 00°49’ W 164°16’.
Background Information
There are several of this type of question in the question bank.
There are no calculations required, merely common sense and a process of elimination.
You are staring at the Equator at W 163°27’ and proceeding on a track of 225T, which is a westerly track.
Therefore, the final position must be SOUTH and WEST of the start point.
The two answers stating positions at N 00°49’ can be discarded.
Next, the position must be to the West of W 163°27’; therefore, W 162°38’, the position to the East of W 163°27’ can also be discarded.
This only leaves S 00°49’ W 164°16’.
Exam statistics
Assuming the Earth to be a perfect sphere:
a 1 minute arc of a great circle measured on the surface of the Earth will be of equal length wherever it is measured.
Given: The coordinates of the heliport at Issy les Moulineaux are N48°50’ E002°16.5’. What are the coordinates of the position directly on the opposite side of the earth?
S48°50’ W177°43.5’
………………………………
The latitude will be the same but South instead of North. The longitude will be 180º away: 002º16.5’E + 180º = 182º16.5’ so longitude = 360º - 182º16.5’ = 177º43.5W
The GMT of Morning Civil Twilight at (66º48’N, 095º26’W) on 27th of January is?
1436 GMT
Standard time for some areas is listed in the Air Almanac as UTC +13 instead of UTC -11. The reason for this is:
to keep the same date as the political and/or economical entity to which they belong.
Near the magnetic pole
the horizontal component of the earth’s magnetic field is too small to permit the use of a magnetic compass.