03 Charts

Question 1

What feature is shown on the chart at position N5351 W00917?

Answer 1

Castlebar aerodrome

Question 2

A direct Mercator graticule is based on a projection that is:

Answer 2

cylindrical

Question 3

On a Direct Mercator chart at latitude 15°S, a certain length represents a distance of 120 NM on the earth. The same length on the chart will represent on the earth, at latitude 10°N, a distance of:

Answer 3

122.3 NM
………………………..
Scale A x cos lat B = Scale B x cos lat A

120 nm x cos 10º = Scale B x cos 15º
(120 nm x cos 10º) ÷ cos 15º = Scale B
Scale B (or distance at N10) = 122.35 nm

Question 4

Which aeronautical chart symbol indicates an exceptionally high unlighted obstacle?

Answer 4

12 nolu sembol

Question 5

A VOR is situated at position (N55°26’, W005°42’). The variation at the VOR is 9°W. The position of the aircraft is (N60°00’N, W010°00’). The variation at the aircraft-position is 11°W. The initial TT-angle of the great circle from the aircraft position to the VOR is 101.5°.

Which radial is the aircraft on?

Answer 5

294
…………..
VOR

Question 6

How does the scale vary in a Direct Mercator chart?

Answer 6

The scale increases with increasing distance from the Equator.

Question 7

Given:

SHA VOR N5243.3 W00853.1, CRK VOR N5150.4 W00829.7. Aircraft position N5230 W00930

Which of the following lists two radials that are applicable to the aircraft position?

Answer 7

SHA 248° CRK 325°
………………………………..
SHA VOR için radial tüm şıklar çift ise en büyük olan seçilir

Question 8

SHA VOR (N5243.3 W00853.1) radial 129°, CRK VOR (N5150.4 W00829.7) radial 047°. What is the aircraft position?

Answer 8

N5220 W00750
………………
150 ye en yakın tamamlayan şık
sonuç mutlaka sıfır olacak

Question 9

Given:

SHA VOR (N5243.3 W00853.1) DME 41 NM, CRK VOR (N5150.4 W00829.7) DME 30 NM, Aircraft heading 270°(M), Both DME distances decreasing. What is the aircraft position?

Answer 9

N5215 W00805
……………………………
eğer dme 41 birinci sırada ise 805 alınır

Question 10

What is the average track (°M) and distance between KER NDB (N5210.9 W00931.5) and CRN NDB (N5318.1 W00856.5)?

Answer 10

025° - 70 NM
………….
KER NDB 25 sayı

Question 11

An NDB is located at position (N55°26’, W005°42’). The variation at the NDB is 9°W. The position of the aircraft is (56°00’N, 010°00’W). The variation at the aircraft-position is 11°W. The initial TT- of the great circle from the aircraft position to the NDB position, is 101.5°.

What is the Magnetic Bearing of the NDB from the aircraft?

Answer 11

112.5°
…………..
NDB

Question 12

What is the radial and DME distance from SHA VOR/DME (N5243.3 W00853.1) to position N5310 W00830?

Answer 12

035° - 30 NM
.........................
Bu tür sorularda SHA VOR için
30, 33, 35, 37, 72
sadece 72 için küçük diğerlari için büyük olan değer

Question 13

A Lambert’s conical conformal chart has standard parallels at 63°N and 41°N.

What is the constant of the cone?

Answer 13

0.788

Question 14

The standard parallels of a Lambert’s conical orthomorphic projection are 07°40’N and 38°20’ N. The constant of the cone for this chart is:

Answer 14

0.39

Question 15

Given:

SHA VOR/DME (N5243.3 W00853.1) radial 120°/35 NM. What is the aircraft position?

Answer 15

N5230 W00800
…………………………..
eğer radial dme den büyüks e N koordinat sonu herzaman sıfırla biter (radial dme arasındaki sayılardan)

Question 16

A straight line on a chart 4.89 cm long represents 185 NM. The scale of this chart is approximately:

Answer 16

1: 7 000 000

Question 17

Given:

Northern Hemisphere
Grid heading 299°
Grid convergency 55° W
Magnetic variation 90° W
What is the corresponding magnetic heading?

Answer 17

084°

Question 18

Given: Direct Mercator chart with a scale of 1: 200 000 at equator; Chart length from ‘A’ to ‘B’, in the vicinity of the equator, 11 cm. What is the approximate distance from ‘A’ to ‘B’?

Answer 18

12 NM

Question 19

What is the average track (°T) and distance between BAL VOR (N5318.0 W00626.9) and CRN NDB (N5318.1 W00856.5)?

Answer 19

270° - 90 NM
………………………..
BAL VOR
16, 26, 27, 270

Question 20

What feature is shown on the chart at position N5311 W00637?

Answer 20

Punchestown aerodrome

Question 21

What is the average track (°M) and distance between CRN NDB (N5318.1 W00856.5) and WTD NDB (N5211.3 W00705.0)?

Answer 21

142° - 95 NM
………………….
W koordinat sonu

5-5 0-0 küçük tercihler

Question 22

What is the radial and DME distance from CON VOR/DME (N5354.8 W00849.1) to position N5330 W00930?

Answer 22

233° - 35 NM
……………
23, 29 veya 35, 36 (36 öncelikli)

Question 23

A great circle track crosses the equator at 30°W has an initial track of 035°T. It’s highest or lowest North/South point is:

Answer 23

55°N 060°E
………………….
Any Great Circle Track crossing the equator will cross the equator again at the exact opposite side of the earth, i.e. if it crosses at the Greenwich Meridian it will cross again at the Greenwich Ante-Meridian. The longitudes of both crossing points will have opposite signs, i.e. one will be West and the other East and they will add up to 180°.

Therefore, if it crosses at 030°W it will cross again at 180° - 030° = 150° and in the opposite hemisphere = 150°E.

This is a Great Circle Track which is subject to convergency and which starts at 035°T (in a north-EASTERLY direction) where it crosses the equator at 030°W. At 150°E the GCT will have changed from a north-easterly track to a south easterly track over 180° of longitude.

The point where the track is either due East or due West is also the point where the track reaches its highest latitude, which also happens to be at the mid-point, i.e. Change of Longitude to the mid-point = 90°

030°W + 90° (Easterly) = 060°E

Question 24

A polar stereographic chart is used for navigation. A straight line between A (75°S 166°E) and B (78°S 154°E) is drawn on the chart. The true track angle of the rhumb line is 223°.

Calculate the direction (°T) of the straight line at position B.

Answer 24

229°

Question 25

A straight line is drawn on a Lambert's conical conformal chart between two positions of different longitude. The angular difference between the initial true track and the final true track of the line is equal to:

Answer 25

chart convergency.

Question 26

A Lambert conformal conic chart has a constant of the cone of 0.75. The initial course of a straight line track drawn on this chart from A (40°N 050°W) to B is 043°(T) at A; course at B is 055°(T). What is the longitude of B?

Answer 26

34°W

Question 27

On a Direct Mercator, rhumb lines are:

Answer 27

straight lines

Question 28

Which one of the following describes the appearance of rhumb lines, except meridians, on a Polar Stereographic chart?

Answer 28

Curves concave to the Pole

Question 29

Assume a North polar stereographic chart whose grid is aligned with the Greenwich meridian. An aircraft flies from the geographic North pole for a distance of 900 NM along the W090° meridian, then follows a grid track of 150°G for a distance of 480 NM. Its position is now approximately:

Answer 29

N77° W060°

Question 30

Which statement is correct about the scale of a Polar Stereographic projection of the Northern polar area?

Answer 30

The scale reaches its minimum value at the North pole.

Question 31

At 60° N the scale of a direct Mercator chart is 1: 3 000 000. What is the scale at the equator?

Answer 31

1: 6 000 000

Question 32

On a Polar Stereographic chart, the initial great circle course from A 70°N 060°W to B 70°N 060°E is approximately:

Answer 32

030° (T)

Question 33

In a navigation chart a distance of 49 NM is equal to 7 cm. The scale of the chart is approximately:

Answer 33

1: 1 300 000

Question 34

What is the radial and DME distance from SHA VOR/DME (N5243.3 W00853.1) to position N5220 W00810?

Answer 34

``` 139° - 35 NM ......... SHA VOR 30, 33, 35, 37, 72 sadece 72 için küçük diğerlari için büyük olan değer ```

Question 35

What is the radial and DME distance from SHA VOR/DME (N5243.3 W00853.1) to position N5300 W00940?

Answer 35

``` 309° - 33 NM ........................ SHA VOR 30, 33, 35, 37, 72 sadece 72 için küçük diğerlari için büyük olan değer ```

Question 36

An aeronautical chart is conformal when:

Answer 36

At any point the scale over a short distance in the direction of the parallel is equal to the scale in the direction of the meridian and the meridians are perpendicular to the parallels.

Question 37

What is the average track (°T) and distance between BAL VOR (N5318.0 W00626.9) and CFN NDB (N5502.6 W00820.4)?

Answer 37

``` 327° - 124 NM .................. BAL VOR derecenin son iki rakamında 16,26,27 veya 270 aranı ```

Question 38

At latitude 60°N the scale of a Mercator projection is 1: 5 000 000. The length on the chart between 'C' N60° E008° and 'D' N60° W008° is:

Answer 38

17.8 cm .................. Two stage process, first departure then chart distance. Ch long E008 to W008 = 16º Departure = Ch long x cos lat x 60 nm/º Departure = 16º x cos 60º x 60 nm/º = 480 nm Converting 480 nm into cm for equal units: 480 nm x 185 200 cm/nm = 88 896 000 cm Scale at N60 = 1 : 5 000 000 Chart distance = Earth distance ÷ scale Chart distance = 88 896 000 cm ÷ 5 000 000 = 17.78 cm

Question 39

A Lambert conformal conic chart has a constant of the cone of 0.80. A straight line course drawn on this chart from A (53°N 004°W) to B is 080° at A; course at B is 092°(T). What is the longitude of B?

Answer 39

011°E .................. Change in track = convergency = 12º Convergency = Ch.long. x constant of the cone (n) Ch.long. = Convergency = 12º = 15º from 004ºW to East = 011ºE n 0.8

Question 40

Which of the following lists all the aeronautical chart symbols shown at position N5211 W00705?

Answer 40

civil airport: NDB

Question 41

What is the radial and DME distance from CRK VOR/DME (N5150.4 W00829.7) to position N5230 W00750?

Answer 41

``` 039° - 48 NM .................. CRK VOR W 7 İSE 7-3 7-8 veya 7-9 (8 tercih sebebi, büyük tercihler) ```

Question 42

Parallels of latitude on a Direct Mercator chart are:

Answer 42

parallel straight lines unequally spaced

Question 43

Assume a North polar stereographic chart whose grid is aligned with the W/E 180° Meridian. An aircraft flies from the geographic North pole for a distance of 600 NM along the W090° meridian, then follows a grid track of 252° for a distance of 330 NM. Its position is now approximately:

Answer 43

N85° W110°

Question 44

What is the radial and DME distance from CON VOR/DME (N5354.8 W00849.1) to position N5340 W00820?

Answer 44

140° - 23 NM ....................... CON VOR 23,29 VEYA 35,36 36 tercih sebebi

Question 45

A straight line from A (75ºN, 120ºE) to B (75ºN, 160ºE) is drawn on a Polar Stereographic chart. When passing the meridian 155ºE, the True Track is:

Answer 45

105º

Question 46

What is the radial and DME distance from SHA VOR/DME (N5243.3 W00853.1) to position N5210 W00920?

Answer 46

``` 214° - 37 NM ....................... SHA VOR 30, 33, 35, 37, 72 sadece 72 için küçük diğerlari için büyük olan değer ```

Question 47

Assume a North polar stereographic chart whose grid is aligned with the W/E 180° Meridian. An aircraft flies from the geographic North pole for a distance of 600 NM along the E090° meridian, then follows a grid track of 252° for a distance of 300 NM. Its position is now approximately:

Answer 47

N75° E093

Question 48

The two standard parallels of a conical Lambert projection are at N10°40'N and N41°20'. The cone constant of this chart is approximatively:

Answer 48

0.44 ....................... Constant of the cone = sin parallel of origin Parallel of origin may be assumed to be mid between the two standard parallels. Mean latitude of N10º40' and N41º20': Mean latitude = (N10º40' + N41º20') ÷ 2 = N26º Parallel of origin is at N26 Constant of the cone = sin parallel of origin Constant of the cone = sin 26º = 0.438

Question 49

Correct statement about a polar stereographic chart is:

Answer 49

The closer the pole the higher straight line chart approximates the great circle.

Question 50

A Mercator chart has a scale at the equator = 1: 3 704 000. What is the scale at latitude 60° S?

Answer 50

1: 1 852 000

Question 51

Which statement is true regarding a compass when directly overhead the north magnetic pole?

Answer 51

the compass tip will point directly down

Question 52

Using a Lambert's conical conformal chart on which Chart Convergency = Earth Convergency at latitude 42°, a straight line is drawn from position A (48°? 155°E) to position B (36°? ?°E). The true course of the straight line track at position A is 060°T and at position B is 46°T. The hemisphere in which the track is drawn and the final longitude at B are:

Answer 52

Southern Hemisphere, 176°E

Question 53

SHA VOR/DME (N5243.3 W00853.1) radial 232°/32 NM. What is the aircraft position?

Answer 53

N5220 W00930 ................................ eğer radial dme den büyüks e N koordinat sonu herzaman sıfırla biter (radial dme arasındaki sayılardan)

Question 54

SHA VOR (N5243.3 W00853.1) radial 205°, CRK VOR (N5150.4 W00829.7) radial 317°. What is the aircraft position?

Answer 54

N5210 W00910 ...................... radial 200 lü sorularda 1. sıradaki radiali alıyoruz N koordinatın son 3 rakamı kendisi hariç en yakın alt veya üst rakamı alıyoruz

Question 55

Position A = 30°00.0'N, 175°23.2'W Position B = 30°00.0'N, 173°48.1'E For the route from A to B the:

Answer 55

rhumb line distance is 578NM.

Question 56

A straight line on a Lambert Conformal Projection chart for normal flight planning purposes:

Answer 56

is approximately a Great Circle

Question 57

Two positions plotted on a polar stereographic chart, A (80°N 000°) and B (70°N 102°W) are joined by a straight line whose highest latitude is reached at 035°W. At point B, the true course is:

Answer 57

203° ...................... A Great Circle Track going from East to West in the Northern Hemisphere will always decrease in value (and West to East will increase in value). The reverse is true of the Southern Hemsiphere. However, we don't recommend that you try to learn these facts but rather to draw a diagram (free hand - no need for super accurate drawings!) and to estimate the value of the track angles from the drawing, i.e. estimate whether A is greater than B or vice versa. Here the track angle at 035°W, being the meridian where the track reaches the highest latitude, will be either 090°T or 270°T. As the aircraft is travelling West it will obviously be 270°T. Look at the track angle at B and it can clearly be seen that the track angle at B is > 180°T but < 270°T.

Question 58

On a Direct Mercator projection a particular chart length is measured at 30°N. What earth distance will the same chart length be if measured at 60°N?

Answer 58

A smaller distance.

Question 59

Given: Lambert conformal conical projection, scale 1: 1 234 000. Standard parallels 36°N and 60°N.. A (53°N, 010°W), B (53°N, 020°W). The distance on the map between position A and position B measured along the rhumb line:

Answer 59

is less than 54.19 cm

Question 60

Which statement is true?

Answer 60

A small scale map shows more area represented with less detail.

Question 61

On a chart a straight line is drawn between two points and has a length of 4.63 cm. What is the chart scale if the line represents 150 NM?

Answer 61

1: 6 000 000

Question 62

The composition of a Mercator chart is based on the following:

Answer 62

A cylindrical projection made using straight lines which are tangent to the equator.

Question 63

Which one of the following statements is correct concerning the appearance of great circles, with the exception of meridians, on a Polar Stereographic chart whose tangency is at the pole ?

Answer 63

The higher the latitude the closer they approximate to a straight line

Question 64

SHA VOR (N5243.3 W00853.1) radial 143°, CRK VOR (N5150.4 W00829.7) radial 050°. What is the aircraft position?

Answer 64

N5210 W00800 ...................... radial 100 lü sorularda 1. sıradaki radiali sayısını 150 ye tamamlayan N koordinat son iki rakamı

Question 65

On a direct Mercator projection, at latitude 45° North, a certain length represents 70 NM. At latitude 30° North, the same length represents approximately:

Answer 65

86 NM ...................... Since the meridians on a direct Mercator are straight, parallel lines equidistant apart, the chart distance between two meridians will be the same at any latitude on the chart. The Earth distance between the same two meridians will decrease with increasing latitude. This change will be the same as the change in scale on the chart so the following formula can be used for this type of question: Scale A x cos lat B = Scale B x cos lat A Which position is labelled A or B is of no importance as long as they are not mixed up. 70 nm x cos 30º = Scale B x cos 45º (70 nm x cos 30º) ÷ cos 45º = Scale B Scale B (or distance at N30) = 85.7 nm

Question 66

Which one of the following, concerning great circles on a Direct Mercator chart, is correct?

Answer 66

With the exception of meridians and the equator, they are curves concave to the equator

Question 67

A rhumb line on a Direct Mercator chart appears as a:

Answer 67

straight line.

Question 68

From Rakovnik (50° 05.9' N, 013° 41.5' E) to Frankfurt FFM (50° 05.9' N, 008° 38.3' E) the True Track of departure along the straight line is 272.0°. The constant of the cone of this Lambert conformal projection is:

Answer 68

0.79

Question 69

How does the chart convergency change with latitude in a Lambert Conformal projection?

Answer 69

It is constant and does not change with latitude.

Question 70

On a Mercator chart, at latitude 60°N, the distance measured between W002° and E008° is 20 cm. The scale of this chart at latitude 60°N is approximately:

Answer 70

1: 2 780 000

Question 71

The constant of the cone in a Lambert chart is 0.8666500. The angle between the north directions of the meridian in position A (65°00'N, 018°00'W) and the meridian of position B (75°00'N, 023°00'W) on the chart is:

Answer 71

4.3° This is a standard convergence question. As it is on a Lambert chart and the constant of the cone is given, latitude of the positions is irrelevant as the convergence is constant all over the chart. Refer to the convergence formula: Convergence = Ch long x sin lat On a Lambert chart, “sin lat” = “sin parallel of origin” = constant of the cone. Ch long W018 to W023 = 5º Convergence = Ch long x sin lat Convergence = 5º x 0.86665 = 4.33º

Question 72

CON VOR/DME (N5354.8 W00849.1), Abbey Shrule aerodrome (N5335 W00739), What is the CON radial and DME distance when overhead Abbey Shrule aerodrome?

Answer 72

123° - 46 NM ...................... ABBEY 123

Question 73

What is the average track (°T) and distance between SHA VOR (N5243.3 W00853.1) and CON VOR (N5354.8 W00849.1)?

Answer 73

``` 002° - 72 NM ....................... SHA VOR 30, 33, 35, 37, 72 sadece 72 için küçük diğerlari için büyük olan değer ```

Question 74

The convergence factor of a Lambert conformal conic chart is quoted as 0.78535. At what latitude on the chart is earth convergency correctly represented?

Answer 74

51°45' ........................ The convergence factor is the sine of the parallel of origin and that is the parallel of latitude where convergency on the chart is the same as Earth convergency 0.78535 is the sine of 51º45’.

Question 75

Approximately how many nautical miles correspond to 12 cm on a map with a scale of 1: 2 000 000?

Answer 75

130

Question 76

The chart distance between meridians 10° apart at latitude 65° North is 9.5 cm. The chart scale at this latitude approximates:

Answer 76

1: 5 000 000 ........................ Two stage process, first departure then scale. Departure = Ch long x cos lat x 60 nm/º Departure = 10º x cos 65º x 60 nm/º = 253.57 nm Scale = 9.5 cm : 253.57 nm Converting 253.57 nm into cm for equal units: 253.57 nm x 185 200 cm/nm = 46 961 341 cm Scale = 9.5 cm ÷ 9.5 cm : 46 961 341 cm ÷ 9.5 cm Scale = 1 : 4 943 299

Question 77

Which of the following lists all the aeronautical chart symbols shown at position N5318.0 W00626.9?

Answer 77

military airport: VOR: DME

Question 78

What is the constant of the cone for a Lambert conic projection whose standard parallels are at 50°N and 70°N?

Answer 78

0.866

Question 79

What is the chart distance between longitudes 179°E and 175°W on a direct Mercator chart with a scale of 1: 5 000 000 at the equator?

Answer 79

133 mm .......................... Scale = CD/ED ED = 6º Ch.long. = 6 x 60 = 360nm at the Equator. 360nm = 667.3km = 667,300,000mm Scale = CD/667,300,000 = 1/5,000,000 So: CD = 667,300,000/5,000,000 = 667.3/5 = 133mm

Question 80

Given: Magnetic heading 311°, Drift angle 10° left, Relative bearing of NDB 270°. What is the magnetic bearing of the NDB measured from the aircraft?

Answer 80

``` 221° .......................... Heading 311ºM Bearing +270º Relative Bearing 581ºM - 360º Bearing 221ºM to the NDB from the aircraft. ```

Question 81

SHA VOR (N5243.3 W00853.1) radial 120°, CRK VOR (N5150.4 W00829.7) radial 033°. What is the aircraft position?

Answer 81

N5230 W00800 .......................... 120 ARTI 30 150 YE TAMAMLA

Question 82

An aircraft is in the position (86°N, 020°E). When following a rhumb line track of 085°(T) it will:

Answer 82

fly via a spiral to the North Pole.

Question 83

What feature is shown on the chart at position N5211 W00931?

Answer 83

KERRY/Farranfore aerodrome

Question 84

The standard parallels of a Lambert chart are 26°N and 48°N and the stated scale is 1:2 500 000. Which statement is correct?

Answer 84

The scale at 28°N is smaller than the scale at 24°N.

Question 85

What feature is shown on the chart at position N5212 W00612?

Answer 85

TUSKAR ROCK LT.H. NDB

Question 86

The nominal scale of a Lambert conformal conic chart is the:

Answer 86

scale at the standard parallels

Question 87

The scale on a Lambert conformal conic chart:

Answer 87

is constant along a parallel of latitude

Question 88

A course of 120°(T) is drawn between 'X' (61°30'N) and 'Y' (58°30'N) on a Lambert Conformal conic chart with a scale of 1: 1 000 000 at 60°N. The chart distance between 'X' and 'Y' is:

Answer 88

66.7 cm ................... Consider the triangle made up of: A: 61°30'N on first meridian B: 58°30'N on second meridian C: 58°30'N on first meridian The track AB at A is 120°T so the angle in the triangle at A = 180° - 120° = 60° The angle in the triangle at C = 90° Side AC = 3° latitude = 180nm AB = hypotenuse (h) and AC = adjacent (a) to angle A CosA = a/h therefore h = a/cosA = 180nm/cos60° = 360nm = 667.3km Scale = CD/ED = CD/667.3km = 1/1,000,000 Therefore CD = 667.3km/1,000,000 = 66,730,000cm/1,000,000 = 66.73cm

Question 89

A straight line from A (53ºN, 155ºW) to B (53ºN, 170ºE) is drawn on a Lambert Conformal conical chart with standard parallels at 50ºN and 56ºN. When passing the meridian 175ºE, the True Track is:

Answer 89

260.0º

Question 90

Assume a North polar stereographic chart whose grid is aligned with the Greenwich meridian. An aircraft flies from the geographic North pole for a distance of 600 NM along the E090° meridian, then follows a grid track of 052° for a distance of 660 NM. Its position is now approximately:

Answer 90

N70° E110°

Question 91

On a Lambert Conformal Conic chart great circles that are not meridians are:

Answer 91

curves concave to the parallel of origin ...................... Meridians (which are great circles) are straight lines. All other great circles are almost straight lines but curved concave to the parallel of origin.

Question 92

On a Lambert Conformal chart the distance between meridians 5° apart along latitude 37° North is 9 cm. The scale of the chart at that parallel approximates:

Answer 92

1: 5 000 000 ............................ Scale = (Chart distance)/(Earth distance) or CD/ED CD = 9 cm ED = 5 x 60 x cos37º = 300 x 0.799 = 239.7nm = 444.32km = 44,432,000 cm Scale = CD/ED = 9/44,432,000 = 1/4,936,910.5 as good as 1/5,000,000

Question 93

Given: CRK VOR/DME (N5150.4 W00829.7) Kerry aerodrome (N5210.9 W00931.4). What is the CRK radial and DME distance when overhead Kerry aerodrome?

Answer 93

307° - 43 NM

Question 94

On a Lambert conformal conic chart, the distance between parallels of latitude spaced the same number of degrees apart:

Answer 94

is smaller between the standard parallels than outside them

Question 95

A straight line drawn on a chart measures 4.63 cm and represents 150 NM. The chart scale is:

Answer 95

1: 6 000 000

Question 96

What feature is shown on the chart at position N5417 W01005?

Answer 96

EAGLE ISLAND LT.H. NDB

Question 97

SHA VOR N5243.3 W00853.1, CON VOR N5354.8 W00849.1. Aircraft position N5320 W00950 Which of the following lists two radials that are applicable to the aircraft position?

Answer 97

SHA 325° CON 235°

Question 98

Given: SHA VOR (N5243.3 W00853.1) radial 223°, CRK VOR (N5150.4 W00829.7) radial 322°. What is the aircraft position?

Answer 98

N5220 W00920

Question 99

A Lambert conformal conic projection, with two standard parallels:

Answer 99

the scale is only correct along the standard parallels .............................. Great circles on a Lamberts chart are curves (concave to the parallel of origin), convergency is correct at the parallel of origin, meridians are straight converging lines and scale is correct at the standard parallels.

Question 100

Given: SHA VOR N5243.3 W00853.1, CON VOR N5354.8 W00849.1, Aircraft position N5330 W00800 Which of the following lists two radials that are applicable to the aircraft position?

Answer 100

``` SHA 042° CON 138° .............................. TEK TEK TEK ÇİFT ```

Question 101

Which of the following lists all the aeronautical chart symbols shown at position N5318.1 W00856.5?

Answer 101

civil airport: NDB: DME: non-compulsory reporting point

Question 102

What is the radial and DME distance from BEL VOR/DME (N5439.7 W00613.8) to position N5410 W00710?

Answer 102

``` 236° - 44 NM .............................. 8-4 1-1 5-8 küçük tercihler ```

Question 103

An aircraft is flying from SALCO to BERRY HEAD on Magnetic Track 007º, TAS 445 kt. The wind is 050º(T)/40 kt. Variation 5ºW, deviation +2º At 1000 UTC the RB of locator PY is 311º. At 1003 UTC the RB of locator PY is 266º. Calculate the True bearing of locator PY at 1003 UTC from the aircraft.

Answer 103

272º (T)

Question 104

Assume a North polar stereographic chart whose grid is aligned with the Greenwich meridian. An aircraft flies from the geographic North pole for a distance of 480 NM along the 110°E meridian, then follows a grid track of 154° for a distance of 300 NM. Its position is now approximately:

Answer 104

80°00'N 080°E

Question 105

What is the average track (°T) and distance between CON VOR (N5354.8 W00849.1) and BEL VOR (N5439.7 W00613.8)?

Answer 105

063° - 101 NM

Question 106

The constant of the cone, on a Lambert chart where the convergence angle between longitudes 010°E and 030°W is 30°, is:

Answer 106

0.75 ........................... So chart conv = change of long * constant 30 = 40*constant constant = 30/40

Question 107

Given: CRN VOR (N5318.1 W00856.5) DME 34 NM, SHA VOR (N5243.3 W00853.1) DME 26 NM, Aircraft heading 090°(M), Both DME distances increasing. What is the aircraft position?

Answer 107

N5255 W00815

Question 108

A straight line from A (75ºS, 120ºE) to B (75ºS, 160ºE) is drawn on a Polar Stereographic chart. When passing the meridian 155ºE, the True Track is:

Answer 108

075º

Question 109

Given: CON VOR (N5354.8 W00849.1) DME 30 NM, CRN VOR (N5318.1 W00856.5) DME 25 NM, Aircraft heading 270°(M), Both DME distances decreasing. What is the aircraft position?

Answer 109

N5330 W00820

Question 110

What is the average track (°T) and distance between SLG NDB (N5416.7 W00836.0) and CFN NDB (N5502.6 W00820.4)?

Answer 110

011° - 47 NM ........................ 11 sayı

Question 111

At reference. Magnetic heading of an aircraft is 040 degrees. On the airborne weather radar (AWR) display the relative bearing of the distance to the must southerly part of Lands End, (approximate position: 50 03 N 005 40 W) are 030 degrees R and 80 NM. What is the position of the aircraft based on these observations? The slant range correction and the map convergency between aircraft position and Lands End may be neglected.

Answer 111

(49 25 N 007 30 W)

Question 112

Given: Position NDB (55°10´N, 012°55´E) DR Position (54°53´N, 009°58´E) NDB on the RMI reads 090° Magnetic variation = 10°W The position line has to be plotted on a Lamberts conformal chart with standard parallels at 40°N and 48°N. Calculate the direction (T) of the bearing to be plotted from the NDB.

Answer 112

262°

Question 113

On a Lambert Conformal Conic chart earth convergency is most accurately represented at the:

Answer 113

parallel of origin

Question 114

What is the radial and DME distance from BEL VOR/DME (N5439.7 W00613.8) to position N5440 W00730?

Answer 114

``` 278° - 44 NM .............................. 8-4 1-1 5-8 küçük tercihler ```

Question 115

A straight line is drawn on a Lambert conformal conic chart, on which Chart Convergency = Earth Convergency at latitude 42°, from A (48° 155°E) to B (36° x°E). The true course of the straight line track at A is 060°T and at B is 046°T. The hemisphere in which the track is drawn and the final longitude at B are:

Answer 115

Southern Hemisphere - 176°E

Question 116

The total length of the 53°N parallel of latitude on a direct Mercator chart is 133 cm. What is the approximate scale of the chart at latitude 30°S?

Answer 116

1: 25 000 000 .............................. The total length of the parallel of latitude is the circumference of the Earth at that latitude, all 360° of it, and that is calculated using “departure = change of longitude (minutes) x cosine of latitude”. The important thing to note is that you want to calculate the scale at S30°, and NOT N53°. You are thinking “But I have the chart distance at N53°. How do I find the chart distance at S30°?”. It is a DIRECT MERCATOR chart. Meridians are vertical, parallel, EQUALLY SPACED lines. So 133 cm at N53° is also 133 cm at S30°. Departure = 360° x 60’ x cos 30° = 18,706 nm Convert to centimetres – 18,706 nm x 1.852 (km) x 1000 (m) x 100 (cm) = 3,464,378,743 cm Divide earth distance in cm by chart distance in cm = 3,464,378,743 cm ÷ 133 cm = 26,047,960 Closest answer = 1:25,000,000

Question 117

Two places are situated on the same parallel in the Southern Hemisphere. The great circle, rhumb line and the straight line between these places are drawn on a Polar Stereographic Projection. Which statement is correct?

Answer 117

The great circle is situated between the parallel and the straight line, because the concave side of the great circle is always pointed towards the pole.

Question 118

On a Mercator's projection a straight line is drawn between (40°N, 050°W) and (50°N, 060°W). Calculate the angle between the straight line and the great circle in position A.

Answer 118

3.5° Since the question is purely about the difference between a rhumb line (straight line on direct Mercator) and a great circle track (i.e. the conversion angle), there is no issue with the two positions being at different latitude without any track given. Mean lat = (N40º + N50º) ÷ 2 = N45º Ch long from W050 to W060 = 10º Convergence = Ch long x sin lat Convergence = 10º x sin 45 = 7.07º Conversion angle = convergence ÷ 2 Conversion angle = 7.07º ÷ 2 = 3.54º

Question 119

What is the radial and DME distance from CON VOR/DME (N5354.8 W00849.1) to position N5430 W00900?

Answer 119

358° - 36 NM ............... 23, 29 veya 35, 36 (36 öncelikli)

Question 120

What is the average track (°M) and distance between CRN NDB (N5318.1 W00856.5) and BEL VOR (N5439.7 W00613.8)?

Answer 120

058° - 128 NM

Question 121

Parallels of latitude, except the equator, are:

Answer 121

Rhumb lines

Question 122

On a Mercator's projection the distance between (17°N, 035°E) and (17°N, 040°E) is 5 cm. The scale at 57°N is approximately:

Answer 122

1 : 6 052 030

Question 123

Which of the following lists all the aeronautical chart symbols shown at position N5416.7 W00836.0?

Answer 123

civil airport: NDB: DME: compulsory reporting point

Question 124

What is the radial and DME distance from CRK VOR/DME (N5150.4 W00829.7) to position N5140 W00730?

Answer 124

113° - 38 NM

Question 125

Calculate the constant of the cone on a Lambert Chart given chart convergency between 010°E and 030°W as being 30°

Answer 125

0.75 ............... Refer to the convergence formula: Convergence = Ch long x sin lat O n a Lambert chart, “sin lat” = “sin parallel of origin” = constant of the cone. Ch long E010 to W030 = 40º Convergence = Ch long x sin lat 30º = 40º x constant of the cone 30º ÷ 40º = constant of the cone Constant of the cone = 0.75

Question 126

What is the average track (°T) and distance between WTD NDB (N5211.3 W00705.0) and SLG NDB (N5416.7 W00836.0)?

Answer 126

``` 336° - 137 NM ................ WTD NDB 0-0 0-1 0-7 0-0 VE 0-1 çıkarsa 0-1 tercih edilir büyükler iki 0-0 ve bir 0-1 varsa büyük olan 0-0 alınır ```

Question 127

What is the average track (°T) and distance between CRN NDB (N5318.1 W00856.5) and EKN NDB (N5423.6 W00738.7)?

Answer 127

035° - 80 NM ..................... 5-5 0-0

Question 128

On a Lambert conformal conic chart the convergence of the meridians:

Answer 128

is the same as earth convergency at the parallel of origin.

Question 129

What is the radial and DME distance from CRK VOR/DME (N5150.4 W00829.7) to position N5220 W00810?

Answer 129

030° - 33 NM

Question 130

What is the average track (°M) and distance between CRK VOR (N5150.4 W00829.7) and CRN NDB (N5318.1 W00856.5)?

Answer 130

357° - 89 NM

Question 131

Define the term 'scale':

Answer 131

The ratio of the chart length compared to the Earth's distance that it represents.

Question 132

On a direct Mercator projection, the distance measured between two meridians spaced 5° apart at latitude 60°N is 8 cm. The scale of this chart at latitude 60°N is approximately:

Answer 132

1: 3 500 000 Two stage process, first departure then scale. Departure = Ch long x cos lat x 60 nm/º Departure = 5º x cos 60º x 60 nm/º = 150 nm Scale = 8 cm : 150 nm Converting 150 nm into cm for equal units: 150 nm x 185 200 cm/nm = 27 780 000 cm Scale = 8 cm ÷ 8 cm : 27 780 000 cm ÷ 8 cm Scale = 1 : 3 472 500

Question 133

SHA VOR N5243.3 W00853.1, CRK VOR N5150.4 W00829.7. Aircraft position N5220 W00910 Which of the following lists two radials that are applicable to the aircraft position?

Answer 133

SHA 214° CRK 330°

Question 134

Which statement is correct about the scale of a Lambert projection?

Answer 134

The scale reaches its minimum value at the parallel of origin.

Question 135

At 47° North the chart distance between meridians 10° apart is 12.7 cm. The scale of the chart at 47° North approximates:

Answer 135

1: 6 000 000 Scale = CD/ED. CD = 12.7 cm. ED = 10º x 60 x cos47º = 409.2nm = 758.5km Scale = 12.7cm/75,850,000cm =1/5,972,441

Question 136

On a polar stereographic projection chart showing the South Pole, a straight line joins position A (70°S 065°E) to position B (70°S 025°W). The true course on departure from position A is approximately:

Answer 136

225°

Question 137

What is the radial and DME distance from CRK VOR/DME (N5150.4 W00829.7) to position N5210 W00920?

Answer 137

311° - 38 NM

Question 138

Given: SHA VOR/DME (N5243.3 W00853.1), Connemara aerodrome (N5314 W00928), What is the SHA radial and DME distance when overhead Connemara aerodrome?

Answer 138

333° - 37 NM

Question 139

What is the value of the convergence factor on a Polar Stereographic chart?

Answer 139

1.0 Convergency = Change of Longitude. n = 1.

Question 140

Given: CRN VOR (N5318.1 W00856.5) DME 18 NM, SHA VOR (N5243.3 W00853.1) DME 30 NM, Aircraft heading 270°(M), Both DME distances decreasing. What is the aircraft position?

Answer 140

N5310 W00830

Question 141

In a particular position the total strength of the terrestrial magnetic field is 5 nanotesia. The inclination is 55°. What is the horizontal component at this position?

Answer 141

2.87 nanotesia. ........................... The horizontal component at this position is 2.87 nanotesia. Background Information This question is contentious and should be appealed as it is considered to be outside the scope of the EASA syllabus. Teslas are a unit of the strength of a magnetic field, often measured in nanotesla, and the formula for calculating their value is as follows: Magnetic Force = Total Strength x Cosine of Dip Applying this to the problem provides: Magnetic Force = Total Strength x Cosine of Dip Magnetic Force = 5 x cos 55° Magnetic Force = 2.87 nanotesla

Question 142

Variation at an NDB is 9W. Variation at the aircraft is 11W. The true track of the great circle to the NDB from the aircraft, at the aircraft, is 101.5. The magnetic bearing of the NDB from the aircraft is:

Answer 142

112.5 ........................ Always use the variation at the aircraft position when calculating direction in relation to NDB bearings. Radio waves follow straight lines in space, i.e. great circle tracks such that the true great circle track from the aircraft to the NDB that is given is the same as the true bearing of the NDB from the aircraft. TB aircraft to NDB: 101.5º Var: W11 MB aircraft to NDB: 112.5º

Question 143

What is the radial and DME distance from CON VOR/DME (N5354.8 W00849.1) to position N5400 W00800?

Answer 143

088° - 29 NM

Question 144

On a Direct Mercator chart, meridians are:

Answer 144

parallel, equally spaced, vertical straight lines

Question 145

On which of the following chart projections is it NOT possible to represent the north or south poles?

Answer 145

Direct Mercator

Question 146

Given: CON VOR/DME (N5354.8 W00849.1), Castlebar aerodrome (N5351 W00917), What is the CON radial and DME distance when overhead Castlebar aerodrome?

Answer 146

265° - 17 NM

Question 147

What is the average track (°M) and distance between BAL VOR (N5318.0 W00626.9) and SLG NDB (N5416.7 W00836.0)?

Answer 147

316° - 96 NM

Question 148

Contour lines on aeronautical maps and charts connect points:

Answer 148

having the same elevation above sea level

Question 149

The initial straight track from A (75°N 60°E) to B (75°N 60°W) on a polar stereographic chart is:

Answer 149

``` 330° ............................ The initial straight track from A = 330° Background Information Draw a circle Draw the Greenwich Meridian from the bottom edge fo the circle, pointing in to the centre of the circle ``` Draw the two local meridians at A-E060° and B-W060°, each pointing in to the centre of the circle Draw a track line from A to B You now have a triangle with internal angles at A, B and at the North Pole (NP) The internal angle at NP is equal to the change of longitude form A to B = 120° The internal angles at A and B must add up to 180° - 120° = 60° As A and B are on the same latitude the distance from A-NP and B-NP must be equal, making this an 'isosceles triangle', and as such the internal angles at A and B are equal A and B = 60° ÷ 2 = 30° If the internal angle at A = 30°, the external angle at A = 360° - 30° = 330° The track at A is equal to the external angle at A = 330°

Question 150

Given: SHA VOR/DME (N5243.3 W00853.1) radial 025°/49 NM. What is the aircraft position?

Answer 150

N5330 W00830

Question 151

Given: SHA VOR/DME (N5243.3 W00853.1) radial 165°/36 NM. What is the aircraft position?

Answer 151

N5210 W00830

Question 152

Given: SHA VOR (N5243.3 W00853.1) DME 50 NM, CRK VOR (N5150.4 W00829.7) DME 41 NM, Aircraft heading 270°(M), Both DME distances increasing. What is the aircraft position?

Answer 152

N5200 W00935

Question 153

If the chart scale is 1: 500 000, what earth distance would be represented by 7 cm on the chart?

Answer 153

35 000 m ............... The Earth distance is 7 x 500,000 cm = 3,500,000 cm = 35,000m.

Question 154

A chart has the scale 1 : 1 000 000. From A to B on the chart measures 3.8 cm, the distance from A to B in NM is:

Answer 154

20.5

Question 155

Given: SHA VOR/DME (N5243.3 W00853.1), Birr aerodrome (N5304 W00754). What is the SHA radial and DME distance when overhead Birr aerodrome?

Answer 155

068° - 41 NM

Question 156

At 0020 UTC an aircraft is crossing the 310° radial at 40 NM of a VOR/DME station. At 0035 UTC the radial is 040° and DME distance is 40 NM. Magnetic variation is zero. The true track and ground speed are:

Answer 156

085° - 226 kt

Question 157

What is the average track (°M) and distance between WTD NDB (N5211.3 W00705.0) and KER NDB (N5210.9 W00931.5)?

Answer 157

278° - 90 NM

Question 158

The constant of cone of a Lambert conformal conic chart is quoted as 0.3955. At what latitude on the chart is earth convergency correctly represented?

Answer 158

23°18' ............................. On a Lamberts Chart convergency is correct along the parallel of origin and the constant of the cone (or convergence factor) is the sine of the parallel of origin. 0.3955 is the sine of 23°18' so convergency is correct at that latitude.

Question 159

Given: SHA VOR N5243.3 W00853.1, CRK VOR N5150.4 W00829.7. Aircraft position N5230 W00820 Which of the following lists two radials that are applicable to the aircraft position?

Answer 159

SHA 131° CRK 017°

Question 160

What is the radial and DME distance from BEL VOR/DME (N5439.7 W00613.8) to position N5500 W00700?

Answer 160

315° - 34 NM .......................... 8-4

Question 161

On a Direct Mercator chart a great circle will be represented by a:

Answer 161

curve concave to the equator

Question 162

Given: An aircraft is flying a track of 255°(M), 2254 UTC, it crosses radial 360° from a VOR station, 2300 UTC, it crosses radial 330° from the same station. At 2300 UTC, the distance between the aircraft and the station is:

Answer 162

the same as it was at 2254 UTC

Question 163

Which of the following lists all the aeronautical chart symbols shown at position N5150.4 W00829.7?

Answer 163

civil airport: VOR: DME: compulsory reporting point

Question 164

A straight line from A (53ºS, 155ºE) to B (53ºS, 170ºW) is drawn on a Lambert Conformal conical chart with standard parallels at 50ºS and 56ºS. When passing 175ºW, the True Track is:

Answer 164

080.0º

Question 165

Assume a Mercator chart. The distance between positions A and B, located on the same parallel and 10° longitude apart, is 6 cm. The scale at the parallel is 1: 9 260 000. What is the latitude of A and B?

Answer 165

60° N or S

Question 166

Given: SHA VOR/DME (N5243.3 W00853.1) radial 048°/22 NM. What is the aircraft position?

Answer 166

N5300 W00830 ............................. radial dme den büyük N koordinat sonu hep sıfır

Question 167

Given: Chart scale is 1: 1 850 000. The chart distance between two points is 4 centimetres. Earth distance is approximately:

Answer 167

40 NM

Question 168

The positions A (30°00'N, 017°30'E) and B at longitude (30°00'N, 023°30'E) are plotted on a Lambert chart with a constant of the cone of 0.5. A and B are connected by a straight line. The True Track measured at A is 088.5°. What is the True Track measured at B?

Answer 168

091.5°

Question 169

What is the average track (°M) and distance between WTD NDB (N5211.3 W00705.0) and BAL VOR (N5318.0 W00626.9)?

Answer 169

026° - 71 NM

Question 170

What is the average track (°T) and distance between WTD NDB (N5211.3 W00705.0) and FOY NDB (N5234.0 W00911.7)?

Answer 170

286° - 81 NM

Question 171

What is the rhumb line distance, in nautical miles, between two positions on latitude 60°N, that are separated by 10° of longitude?

Answer 171

300 NM

Question 172

On a Direct Mercator chart at latitude 45°N, a certain chart length along 45°N represents a distance of 90nm on the surface of the earth. The same length on a chart along latitude 30°N will represent a distance on the earth of:

Answer 172

110 NM ................................. Since the meridians on a direct Mercator are straight, parallel lines equidistant apart, the chart distance between two meridians will be the same at any latitude on the chart. The Earth distance between the same two meridians will decrease with increasing latitude. This change will be the same as the change in scale on the chart so the following formula can be used for this type of question: Scale A x cos lat B = Scale B x cos lat A Which position is labelled A or B is of no importance as long as they are not mixed up. 90 nm x cos 30º = Scale B x cos 45º (90 nm x cos 30º) ÷ cos 45º = Scale B Scale B (or distance at N30) = 110.23 nm

Question 173

The distance measured between two points on a navigation map is 42 mm (millimetres). The scale of the chart is 1:1 600 000. The actual distance between these two point is approximately:

Answer 173

36.30 NM

Question 174

Which statement is true about the parallel of origin of a conformal chart?

Answer 174

The parallel of origin is the parallel at which the scale reaches its minimum value.

Question 175

The chart that is generally used for navigation in polar areas is based on a:

Answer 175

Stereographical projection

Question 176

On a navigation chart a distance of 69 NM is equal to 17 cm. The scale of the chart is approximately:

Answer 176

1 : 750 000 ................................... Scale = Chart Distance / Earth Distance Both units must be the same. The simplest method of calculating scale is to: 1. Convert Earth Distance into the same unit as Chart Distance 69 nm x 1.852 = 127.788 km 127.788 km x 1,000 = 127,788 km 127,788 m x 100 = 12,778,800 cm 2. Divide Earth Distance by Chart Distance 12,778,800 cm / 17 cm = 751,694.1176 Approximate scale = 1:750,000

Question 177

The parallels on a Lambert Conformal Conic chart are represented by:

Answer 177

arcs of concentric circles

Question 178

On a Lambert conformal conic chart, with two standard parallels, the quoted scale is correct:

Answer 178

along the two standard parallels

Question 179

On a Lambert chart (standard parallels 37°N and 65°N), with respect to the straight line drawn on the map between A ( N49° W030°) and B (N48° W040°), the:

Answer 179

great circle and rhumb line are to the south

Question 180

Where on a Direct Mercator projection is the chart convergency correct compared to the earth convergency?

Answer 180

At the equator.

Question 181

On a chart, the distance along a meridian between latitudes 45°N and 46°N is 6 cm. The scale of the chart is approximately:

Answer 181

1: 1 850 000 ................................... Scale = CD/ED = 6cm/60nm = 6cm/111.2km = 6cm/11,120,000cm = 1/1,853,333.3