3.2. Common Results of Vertical Motion

Question 1

Finding time taken to reach maximum height by a projectile travelling in vertical motion

Answer 1

• v = u + at
• Let v = 0 and find t
• The time taken to go up and come back to original
  position would be double of this t

Question 2

Finding maximum height above a launch point use

Answer 2

• v^2 = u^2 − 2as
• Let v = 0 and find s

Question 3

Finding time interval for which a particle is above a given height

Answer 3

• Let the height be H and use
• s = ut + 0.5at^2
• Let s = H
• There will be a quadratic equation in
• Solve and find the difference between the 2 t’s to find the time interval