9.9.3 The Use of Pedigree Charts to Determine Possible Genotypes Flashcards
pedigree charts to determine possible genotypes
• A pedigree chart shows the family history of traits, such as heritable disorders.
• An autosome is a chromosome that is not directly involved in sex determination. In humans there are 22 pairs of chromosomes. Defects in autosomal alleles can be categorized in various ways:
· In a heterozygote, the autosomal dominant allele causes the disorder and masks the normal allele.
· An autosomal recessive condition is expressed in the homozygous condition.
• Sex-linked genes are located on the sex chromosomes, which are involved in sex determination. These genes are categorized in different ways:
· X-linked dominant: In males or females, one abnormal allele on the X-chromosome causes the disorder.
· X-linked recessive: Males with one abnormal allele express the trait, only homozygous females show the trait.
· Y-linked: One abnormal allele on the Y chromosome causes the disorder.
note
- The pedigree on the left shows the occurrence of a heritable disorder among family members. Shaded blocks indicate presence of the disorder.
- Review: Squares represent males and circles represent
females. - Based on the pattern of inheritance, a number of mechanisms could explain the disorder. To determine what types of inheritance are possible, look at each type in turn and determine whether or not conflicting evidence is present.
- Autosomal dominant: If the trait was inherited in this
manner, the dominant “H” allele would cause the disorder and the normal phenotype would occur in a homozygous “hh” condition. The F1 male has the disease, but neither of the parents does. This pattern of inheritance is inconsistent with an autosomal dominant type of inheritance. - Autosomal recessive: If the disease was inherited in this manner, the homozygous condition “hh” would cause the disorder and “H-” individuals would be normal. No information conflicts with this mode of inheritance; therefore it is considered a possibility.
- X-linked dominant: Individuals that are XH would have the disorder whereas Xh individuals are normal. The male in F1 shows the disorder and so should the mother in the P generation. This mode of inheritance is ruled out.
- X-linked recessive: The disease will be present in the
hemizygous condition in males (XhY) and homozygous
females (XhXh). There is no information that is inconsistent with this type of inheritance; therefore, it is considered a possibility. - Y-linked: The disease should occur in all related males.
The male in F1 has the disorder, but his father doesn’t. This possibility is ruled out.
Which statement best describes the pattern of inheritance of an autosomal dominant disorder?
- An autosomal dominant disorder is expressed in the heterozygous and homozygous conditions and is coded for on a non-sex chromosome.
A son has a mother who is heterozygous for the sex-linked recessive trait of Duchenne muscular dystrophy. His father is phenotypically normal. What probability does the son have of contracting the disease?
- 1/2
Analyze the pedigree chart. What mechanisms of inheritance could describe the disorder?
- X linked recessive or autosomal recessive
A trait referred to as “widow’s peak” is inherited as an autosomal dominant allele. Looking at the pedigree chart, if F1-4 and his wife F1-5 have a baby girl with the trait, what is the probability that their next child will be a son with the widow’s peak trait?
- 1/4
The disease galactosemia occurs from a defect in the enzyme responsible for breaking down the sugar galactose. The deficiency is present at birth and may be fatal to infants. The frequency in the human population is 1/500 people. A normal couple has a child with galactosemia. What is the probability that their next two children will be affected with galactosemia?
- 1/16
Which of the following is not true?
- This pedigree proves the trait is a sex-linked recessive