9.9.3 The Use of Pedigree Charts to Determine Possible Genotypes Flashcards

1
Q

pedigree charts to determine possible genotypes

A

• A pedigree chart shows the family history of traits, such as heritable disorders.
• An autosome is a chromosome that is not directly involved in sex determination. In humans there are 22 pairs of chromosomes. Defects in autosomal alleles can be categorized in various ways:
· In a heterozygote, the autosomal dominant allele causes the disorder and masks the normal allele.
· An autosomal recessive condition is expressed in the homozygous condition.
• Sex-linked genes are located on the sex chromosomes, which are involved in sex determination. These genes are categorized in different ways:
· X-linked dominant: In males or females, one abnormal allele on the X-chromosome causes the disorder.
· X-linked recessive: Males with one abnormal allele express the trait, only homozygous females show the trait.
· Y-linked: One abnormal allele on the Y chromosome causes the disorder.

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2
Q

note

A
  • The pedigree on the left shows the occurrence of a heritable disorder among family members. Shaded blocks indicate presence of the disorder.
  • Review: Squares represent males and circles represent
    females.
  • Based on the pattern of inheritance, a number of mechanisms could explain the disorder. To determine what types of inheritance are possible, look at each type in turn and determine whether or not conflicting evidence is present.
  • Autosomal dominant: If the trait was inherited in this
    manner, the dominant “H” allele would cause the disorder and the normal phenotype would occur in a homozygous “hh” condition. The F1 male has the disease, but neither of the parents does. This pattern of inheritance is inconsistent with an autosomal dominant type of inheritance.
  • Autosomal recessive: If the disease was inherited in this manner, the homozygous condition “hh” would cause the disorder and “H-” individuals would be normal. No information conflicts with this mode of inheritance; therefore it is considered a possibility.
  • X-linked dominant: Individuals that are XH would have the disorder whereas Xh individuals are normal. The male in F1 shows the disorder and so should the mother in the P generation. This mode of inheritance is ruled out.
  • X-linked recessive: The disease will be present in the
    hemizygous condition in males (XhY) and homozygous
    females (XhXh). There is no information that is inconsistent with this type of inheritance; therefore, it is considered a possibility.
  • Y-linked: The disease should occur in all related males.
    The male in F1 has the disorder, but his father doesn’t. This possibility is ruled out.
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3
Q

Which statement best describes the pattern of inheritance of an autosomal dominant disorder?

A
  • An autosomal dominant disorder is expressed in the heterozygous and homozygous conditions and is coded for on a non-sex chromosome.
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4
Q

A son has a mother who is heterozygous for the sex-linked recessive trait of Duchenne muscular dystrophy. His father is phenotypically normal. What probability does the son have of contracting the disease?

A
  • 1/2
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5
Q

Analyze the pedigree chart. What mechanisms of inheritance could describe the disorder?

A
  • X linked recessive or autosomal recessive
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6
Q

A trait referred to as “widow’s peak” is inherited as an autosomal dominant allele. Looking at the pedigree chart, if F1-4 and his wife F1-5 have a baby girl with the trait, what is the probability that their next child will be a son with the widow’s peak trait?

A
  • 1/4
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7
Q

The disease galactosemia occurs from a defect in the enzyme responsible for breaking down the sugar galactose. The deficiency is present at birth and may be fatal to infants. The frequency in the human population is 1/500 people. A normal couple has a child with galactosemia. What is the probability that their next two children will be affected with galactosemia?

A
  • 1/16
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8
Q

Which of the following is not true?

A
  • This pedigree proves the trait is a sex-linked recessive
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