Biochemistry Class 1 Flashcards
(182 cards)
substrate binds to what type of macromolecule
enzyme
an enzyme is said to be saturated when _______ (2 facts)
- so much substrate is attached to all active sites that they are continuously occupied
- adding more substrate does not increase the reaction rate
enzyme saturation is denoted by what symbol?
Vmax
how do we know the Vmax of each enzyme?
Vmax is a property of each enzyme at a particular concentration of enzyme.
reaction rate for enzyme kinetics is ______ (def + fact)
- amount of product formed per unit time in mole per second (mol/s).
- determined by concentration of substrate and enzyme
allosteric regulation (2 facts)
- binding of small non-substrate molecules to particular sites on enzyme other than the active site
- alters the conformation of the active site of the enzyme in such a way that the catalysis is increased or decreased binding is reversible and non-covalent
What does the V vs [S] graph (enzyme kinetics) show and what does each letter mean
how the reaction rate varies according to substrate concentration V= velocity (Rate of reaction) where Vmax is upper limit [S] = substrate concentration
what is Km in enzyme kinematics
a constant for a given enzyme/substrate combo that is the measure of substrate concentration at 1/2 Vmax.
low Km means: ____low/high?_____ affinity of enzyme for the particular substrate
high
<em>MCAT trick!</em>
T/F: Vmax is constant for a given enzyme/substrate pairing
True
competitive inhibitor binds at ________site
active
in enzyme kinetics, the sigmoidal curve represents__________.
What’s an example?
positive cooperative binding
Oxy-hemoglobin dissociation curve
What is positive cooperative binding? (2 facts)
- When the binding of substrate to one subunit increases the affinity of other subunits for substrate.
- conformation of enzyme is said to be tense at low concentration of [S] → low affinity and relaxed at high concentrations → high affinity
T/F: You cannot get to Vmax with presence of competitive inhibitor
False: You can, it just takes longer and requires more substrate
presence of a competitive inhibitor ____increases/decreases?_____ Km
increases


what effect on Km does non-competitive inhibitor have
it does not change it because binding of an inhibitor at allosteric site does not increase or decrease affinity, which alters Km
[S]surroundings + [S]system = [S]universe
is [S] greater or less than zero
[S]surroundings + [S]system = [S]universe >0
If ΔH and T constant…
then when ΔS is positive, what is ΔG?
ΔG is negative
ΔS positive means that the entropy of the universe [S]final increased as a result of the reaction, and the 2nd law of thermodynamics states that this occurs in spontaneous reactions, which is denoted by -ΔG
T/F We can transform endergonic reactions to exergonic reactions by increasing the concentration of reactants
True
When ΔG = 0, the reaction is _______
at equilibrium
What is the gas constant, R
8.314 J/mol · K
how do you convert C° to K
add 273 to your temp in C°
What are 2 mathematical ways to determine whether the reaction will favor products or reactants and to what extent?
- Look at ΔG: if -ΔG then reaction favors products and the magnitude of the value is proportional to the magnitude of the drive to make products
- Look at whether Q (conc. of products/reactants) is > or < Keq. If Q<k>eq then reaction is drive to the right (towards products) in an effor to reestablish equilibrium. Again, the extent to which Q<k>eq indicates how much drive it has</k></k>














































