Blood Bank Makeup Exam Part 2 Flashcards

1
Q

A patient has anti-P1 that reacts only with ficin treated cells. What should be done to find four units of compatible red blood cells?

Test donor cells with compared anti-P1 until 4 units are found; then crossmatched at 37 degrees to AHG

No crossmatching beyond the immediate spin phase is necessary; therefore, find four units of the patient’s ABO/Rh type. Any units found compatible at the immediate spin phase can be transfused

Crossmatch ABO/Rh compatible cells at 37 C degrees to AHG. Any that are compatible can be transfused

Neutralize the serum with hydatid cyst fluid and perform crossmatches at 37 degrees to AHG. Anything compatible can be transfused

A

Crossmatch ABO/Rh compatible cells at 37 C degrees to AHG. Any that are compatible can be transfused

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2
Q

Which two blood group systems are similar in that the antigens are highly antigenic and any antibodies against these antigens are clinically significant, yet finding compatible red blood cells lacking the antigens is not difficult?

P and I blood group systems

Rh and K blood group antigens

Kidd and Duffy blood group systems

Lutheran and Lewis blood group systems

A

Rh and K blood group antigens

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3
Q

What is the most likely explanation when screen cells, panel cells, the auto control and all crossmatches are positive at 37 degrees, but negative after the addition of antihuman globulin?

A warm autoantibody

A mixture of warm autoantibodies and alloantibodies

Rouleaux

An alloantibody to a high incidence antigen

A

Rouleaux

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4
Q

Why is anti-IgG needed to detect IgG sensitized cells?

The IgG molecule attracts more than one cell and anti-IgG creates a spatially accurate distance between cells

The IgG molecule coating cells cannot span the distance between sensitized cells; therefore, anti-IgG links the Fc portions of the bound IgG molecules so that a lattice is formed, and agglutination is detected

The anti-IgG is specific for the variable region of all IgG antibodies; therefore, it is the ideal antibody to detect any specificity

The anti-IgG molecule can span the distance between cells and can attach to the antigen on red blood cells, pulling them together and causing visualization of agglutination

A

The IgG molecule coating cells cannot span the distance between sensitized cells; therefore, anti-IgG links the Fc portions of the bound IgG molecules so that a lattice is formed, and agglutination is detected

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5
Q

A patient is suspected of having paroxysmal cold hemoglobinuria (PCH). Which pattern of reactivity is characteristic of the Donath-Landsteiner antibody, which causes this condition?

The antibody attaches to red blood cells at 4 C and causes hemolysis at 37 C

The antibody attaches to red cells at 37 C and causes agglutination at the IAT phase of testing

The antibody attaches to red cells at 22 C and causes hemolysis at 37C

The antibody attaches to red cells and causes agglutination at the IAT phase of testing

A

The antibody attaches to red blood cells at 4 C and causes hemolysis at 37 C

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6
Q

A positive reaction is seen at 37 degrees between the patient’s serum and ficin treated cells (including the autologous cells that are ficin treated) and negative results are obtained after adding antihuman globulin. Check cells were positive. What does this mean?

The patient has an alloantibody to a high frequency antigen since all the cells yielded reactions after 37 degrees

The patient has an autoantibody since the auto control was positive after 37 degrees

The patient has a ficin panagglutinin since all cells that were ficin treated reacted at 37 degrees

The patient has an alloantibody to a low frequency since all the cells were negative after adding antihuman globulin

A

The patient has a ficin panagglutinin since all cells that were ficin treated reacted at 37 degrees

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7
Q

In a serial dilution, you obtained positive results in your lower dilutions, positive in the middle ranges, and negative in the higher dilutions. What should you do?

Repeat the test

Report test as inconclusive

Report the titer of the highest dilution with a positive test

Report the titer of lowest dilution with a positive

A

Report the titer of the highest dilution with a positive test

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8
Q

If a patient has an antibody to anti-Kp(b), what is the challenge in finding compatible blood?

There is no challenge, Kp(b-) blood is readily available

Anti-Kp(b) is a “crossmatch compatible” antibody; therefore, the patient’s serum would be crossmatched against cells until a compatible unit is found

The Kp(b) antigen is a high frequency antigen; therefore, it would be difficult to find compatible red blood cells. Possibly siblings would be compatible

Anti-Kp(b) is a clinically insignificant antibody; so there would be no need to find red blood cells that are Kp(b-)

A

The Kp(b) antigen is a high frequency antigen; therefore, it would be difficult to find compatible red blood cells. Possibly siblings would be compatible

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9
Q

A patient has no history of a clinically significant antibody and the antibody screen using LISS enhancement at 37 C on to the antihuman globulin phase was negative. Check cells were positive. Which of the following crossmatch procedures is recommended?

Immediate spin, room temp major crossmatch

37 C LISS to antihuman globulin major crossmatch

Ficin related donor cells at 37 C to antihuman globulin

No crossmatch necessary

A

Immediate spin, room temp major crossmatch

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10
Q

In antibody detection procedures, a positive auto control after the addition of AHG is usually indicative of:

Inadequate washing
Positive DAT
Positive IAT
Rouleaux

A

Positive DAT

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11
Q

Why is rouleaux not found in the AHG phase of antibody screens?

High protein molecules are not reactive at 37 C

Patient cells are washed away before adding AHG

Patient serum is washed away before adding AHG

None of the above

A

Patient serum is washed away before adding AHG

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12
Q

An antibody screen and crossmatch for six units of red blood cells was performed. All units were 4+ incompatible at immediate spin, 3+ incompatible after adding antihuman globulin. The antibody screen was negative and there was no ABO discrepancy between the patient’s cells and serum. What is the most probable explanation for this?

The units of blood have been incorrectly ABO typed

The patient has an antibody to a high frequency antigen

The patient has an antibody to a low frequency antigen

The patients serum is not ABO compatible with the donor cells

A

The units of blood have been incorrectly ABO typed

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13
Q

What is the possible explanation for a nonreactive eluate?

Hemolytic disease of the newborn (HDN)

Positive DAT due to drugs

A warm autoantibody

All of the above

A

Positive DAT due to drugs

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14
Q

After the serum and cells were incubated for the appropriate time at 37 degrees, a tech washed the tubes by filling each tube one-third full of saline, centrifuging, decanting and repeating the procedure two additional times. AHG was added after a dry cell button was prepared. All results were negative; therefore check cells were added. All results were negative after the addition of the check cells. Choose the correct answer from below.

The results are most probably correct, and a “negative” result can be reported

The check cells are negative because the cells in the tubes were not properly washed.

Repeat the test exactly as done above but use a new bottle of check cells.

Add one more drop of check cells and re centrifuged

A

The check cells are negative because the cells in the tubes were not properly washed.

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15
Q

One drop of Coombs control cells was added to a negative antibody screen. No agglutination was observed after centrifugation. What course of action should be taken?

Report negative result

Report inconclusive result

Repeat the test

Add one more drop of check cells and re centrifuged

A

Repeat the test

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16
Q

A woman of childbearing age who was group AB negative was in need of whole blood. Since none was available, which of the following could be used?

Group AB positive whole blood

Group O negative packed cells

Group A negative whole blood

Group A positive packed cells

A

Group O negative packed cells

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17
Q

Why might some blood banking facilities prefer the use of monospecific IgG over Poly specific antihuman globulin (AHG) in their antibody screens?

Interference from naturally occurring warm antibodies in patient sera is reduced

Interference from naturally occurring cold antibodies in patient sera is reduced

There is more IgG in monospecific antisera than Poly specific reagents

Monospecific, IgG has been standardized

A

Interference from naturally occurring cold antibodies in patient sera is reduced

18
Q

A tech treated all sixteen cells on a panel with DTT. What blood group system was destroyed?

Kidd system
Kell system
Lewis system
MNS system

A

Kell system

19
Q

A patient has the Lewis phenotype Le(a-b-). An antibody panel reveals the presence of anti-Le(a). Another patient with the phenotype Le(a-b+) has a positive antibody screen; however, a panel reveals no conclusive antibody. Should anti-Le(a) be considered as possibility for the patient with the Le)a-b+) phenotype?

Anti-Le(a) should be considered as a possible antibody for this patient

Anti-Le(a) may be a possible antibody, but further studies are needed

Anti-Le(a) is not a likely antibody because even Le(b+) individuals secrete some Le(a)

Anti-Le(a) may not be found in the saliva, but the antibody is not detectable in the serum

A

Anti-Le(a) is not a likely antibody because even Le(b+) individuals secrete some Le(a)

20
Q

A test to detect in vivo sensitized red blood cells is

An IAT
The addition of check cells
A DAT
An immediate spin crossmatch

A

A DAT

21
Q

A group O, Rh negative man, aged 79 years with a negative antibody screen, was critically injured in a motor vehicle accident. The doctor wanted fresh whole blood, but whole blood was not available. Also, there was no group O, Rh negative blood in blood bank. What is the next best choice?

Group O Rh positive leukoreduced red blood cells and Group AB, Rh positive FFP

Group A, Rh negative leukoreduced red blood cells and group AB, Rh negative FFP

Group B, Rh negative leukoreduced RBCs and Group O, Rh negative FFP

Group AB, Rh negative leukoreduced RBCs and Group O, Rh negative FFP

A

Group O Rh positive leukoreduced red blood cells and Group AB, Rh positive FFP

22
Q

Anti-S was identified in absorbed serum of a patient with warm autoimmune hemolytic anemia. If a RBC phenotype was performed on neat cells using an indirect antiglobulin test to ensure that the patient is negative for the S antigen, what would the technologists find?

The cells would have to be treated with ficin and then tested for the S antigen

Neat cells and commercial anti-S would yield a positive result due to IgM coating the neat cells

The patients neat cells would type negative for the S antigen

Neat cells and commercial anti-S would yield a positive result due to IgG coating the neat cells

A

Neat cells and commercial anti-S would yield a positive result due to IgG coating the neat cells

23
Q

What characteristics are true of all three of the following antibodies? Anti-Fy(b), anti-S, and anti-M

All are detected with enzyme-treated cells

Require IAT technique for detection; usually not responsible for causing HDFN

May show dosage effect, all enhanced by acid

All may be detected at the AHG phase; all may cause HDN and transfusion reactions

A

May show dosage effect, all enhanced by acid

24
Q

A sample appears to have anti-K; however, many other antigens must be ruled out. The tech can’t find enough k negative cells that are homozygous positive for the antigens not yet ruled out. What can be done to cells to remove the k antigen?

Treat the cells with AET
Treat the cells with papain
Treat the cells with ficin
Treat the cells with liquid nitrogen

A

Treat the cells with AET

25
Q

How can cold autoantibody interference with ABO grouping be avoided?

Washing cells with normal saline cooled to 4C

Washing cells with normal saline warmed to 37C

Treating red cells with ficin prior to testing

Washing cells with normal saline at room temperature

A

Washing cells with normal salinewarmed to 37

26
Q

Which cells are employed to remove autoantibody from the serum of a patient who had been transfused last month?

Coombs control red blood cells

Allogeneic cells with known antigens

Patient red blood cells

Panel red blood cells

A

Patient red blood cells

27
Q

Light is generated when nucleotides are added to a growing strand of DNA in the process of:

Pyrosequencing
Ligase chain reaction
Strand displacement amplification
Branched DNA amplification

A

Pyrosequencing

28
Q

An immunoassay is performed in the following manner to look for an antigen (Ag) in the patient serum: Patient serum + labeled Ag + known antibody (Ab) are added together and incubated. Unbound material is washed off. The amount of labeled Ag is then measured. What assay is performed?

Homogenous
Competitive
Capture
ELISA

A

Competitive

29
Q

Extremely high analyte concentrations can cause false-negative results (hook effect) in which type of assay?

Homogenous competitive

Heterogenous competitive

Homogenous noncompetitive

Heterogenous noncompetitive

A

Homogenous noncompetitive

30
Q

Use of microarrays consisting of either DNA or RNA to identify an unknown nucleic acid best describes:

In situ hybridization
DNA Chip Technology

A

DNA Chip Technology

31
Q

… compound would be an appropriate label in a chemiluminescent assay?

Horseradish peroxidase
Ruthenium derivative

A

Ruthenium derivative

32
Q

The production of insoluble complexes that absorb or scatter light but are too small to see directly is called:

Precipitation
Agglutination
Equivalence
Sensitization

A

Precipitation

33
Q

To prepare 70 mL of 10% solution of acetic acid, how much acetic acid is needed?

0.7mL
7mL
10ml
1.4mL

A

7mL

34
Q

In which of the following testing situations is there a direct relationship between the amount of bound label and the amount of patient antigen present?

Competitive radioimmunoassay using labeled antigen

Competitive enzyme immunoassay using labeled antigen

Noncompetitive enzyme immunoassay using a second labeled antibody

Any of the above

A

Noncompetitive enzyme immunoassay using a second labeled antibody

35
Q

Which antibody has the highest avidity for an antigen?

IgG containing Fab that each have an affinity of xx10^-8/M

Secretory IgA containing Fab that each have an affinity of 4x10^-8/M

IgM containing Fab that each have affinity of 1x10^-8/M

IgE containing Fab that each have an affinity of 1x10^-9/<

A

IgM containing Fab that each have affinity of 1x10^-8/M

36
Q

Serology is the study of:

WBCs

RBCs

Platelets

The liquid components of the blood. Especially antibodies

A

The liquid components of the blood. Especially antibodies

37
Q

A 5 year old boy suffering from measels complained of back pain, chills, and stomach pain. his doctor revealed hemoglobinuria, bilirubinemia and hemoglobinemia. The child’s hemoglobin was 6. A donath landsteiner test was performed and showed the following:

Ctr sample: neg hemolysis
test sample: hemolysis
The results are consistent with what disorder

a. warm auto
b. cold auto
c. paroxysmal nocturnal hemoglobinuria
d. paroxysmal cold hemoglobinuria

A

d. paroxysmal cold hemoglobinuria

38
Q

What is the purpose of coombs control cells aka check cells

Ensure AHG was not inactivated

To ensure that washing removed all unbound ab

To ensure AHG was no emitted

All of them

A

All of them

39
Q

In a patient who has been recently transfused, a pos DAT may be due to:

Allo coating patient cell

Allo coating transfused cells

Ab to drug coated donor cells

None

A

Allo coating transfused cells

40
Q

What can be concluded in a patient who has anti-K identified in his serum but phenotypes pos for the K antigen

a. Kell antisera omitted
b. Patient transfused with K pos blood
c. anti-K mis- ID
d. B and C

A

B and C

41
Q

What is the pH of an acid eluate

A

3

42
Q

Women need blood and she is B neg but the bank ran out of B neg blood with anti-C, D and E (oh nooo) what blood can you use instead so that she doesnt DIE BOOO

O rr
B R2R2
A rr
AB R1R1

A

O rr