Carbonyls and Carboxylic Acids Flashcards
(130 cards)
Where is the C=O situated in an aldehyde?
At the end of carbon chain
What is the number of the carbon with the =O in an aldehyde?
1
where is the C=O situated in a ketone?
Somewhere along the carbon chain
BUT NEVER AT THE END
What number should the C=O have in a ketone?
The lowest number
What are primary alcohols oxidised to?
Aldehydes
Carboxylic acids
What are secondary alcohols oxidised to?
Ketones
How do you oxidise a primary alcohol to a aldehyde?
Distillation
How do you oxidise a primary alcohol to a carboxylic acid?
Reflux
What are the two products of oxidising an alcohol?
Aldehyde/carboxylic acid/ketone + water
What are the conditions needed to oxidise a primary alcohol to an aldehyde?
Heat
Potassium dichromate
Excess of primary alcohol
Why do you need an excess of alcohol when oxidising a primary alcohol to a aldehyde?
So doesn’t further oxidise to a carboxylic acid
What colour does potassium dichromate turn when an alcohol has been oxidised?
Orange —-> green
What are the conditions needed to oxidise a primary alcohol to an carboxylic acid?
Heat
Excess [o] (potassium dichromate)
Primary alcohol
Why do you need an excess of [o] when oxidising a primary alcohol to a carboxylic acid?
To ensure the reaction is complete
What will not be produced if a carboxylic acid is produced via further oxidation?
Water
How can secondary alcohols be oxidised?
Distillation or reflux
What are the conditions needed for oxidising a secondary alcohol?
Heat
Excess [o]
Secondary alcohol
What can aldehydes be reduced to?
Primary alcohol
What is reducing agent is to reduce a ketone/aldehyde?
NaBH4/H2O
What is the name of NaBH4?
Sodium tetrahydrioborate
Why is the NaBH4 important?
Contains BH4 - which is the source of H- (hydride ion)
What are ketones and aldehydes reduced to?
Respective ion
What are the conditions needed for the reduction of ketones and aldehydes?
Warm it using ethanol or water as a solvent
What is the difference between an oxidising and reducing reaction?
Oxidising - [O]
Reducing =[H]