Chapter #7 Flashcards

(22 cards)

1
Q

Identify the alpha carbon

A

adjacent to the carbonyl carbon

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2
Q

why is it easy to deprotonate the alpha hydrogen

A

the oxygen in the carbonyl bond pulls electron density away from these C-H bonds which weakens them

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3
Q

why is an enolate formed via the loss of an alpha hydrogen so stable

A

resonance stabilization in the structure.

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4
Q

carbanion

A

a molecule with a negatively charged carbon atom

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5
Q

compare the acidity of the alpha hydrogen in ketone vs. aldehyde

A

more acidic in aldehyde because the ketone has extra alkyl groups to donate electron density which destabilizes the carbanion.

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6
Q

does nucleophilic attack of aldehydes or ketones have a higher energy intermediate?

A

ketones, more steric hindrance, requires more energy to accomplish successful reaction.

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7
Q

how does the enol form get its name

A

en- : double bond between carbons

-ol : alcohol

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8
Q

are there more keto or enol isomers in solution?

A

more keto

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9
Q

are tautomers resonance structures?

A

no, because they differ in their connectivity

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10
Q

what are some common strong bases?

A

KH, OH, LDA

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11
Q

Michael addition

A

carbanion formed via strong base attacks an alpha,beta-unsaturated carbonyl compound

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12
Q

alpha,beta-unsaturated carbonyl compound

A

multiple bond between the alpha and beta carbons

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13
Q

compare the thermodynamic and kinetic enolate formation

A

thermodynamic: more substituted carbon, more stable, slower, favored in reactions with higher temperatures, slow, reversible and weaker, smaller bases.
kinetic: less substituted carbon, less stable, faster, favored in reactions that are rapid, irreversible, at lower temperatures, and with a strong, sterically hindered base.

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14
Q

is the imine or enamine form more prominent in solution

A

imine

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15
Q

what is special about the aldol condensation reaction?

A

the carbonyl containing compound is acting as both the nucleophile and the electrophile.

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16
Q

aldol

A

contains both an aldehyde and alcohol functional group (named after the aldehyde due to priority)

17
Q

describe steps 1 and 2 of aldol condensation

A

step 1: formation of the aldol

step 2: dehydration of water molecule

18
Q

in retro aldol reaction, where does the bond breakage occur?

A

between the alpha and beta carbons of the carbonyl

19
Q

what reagents are needed for the retro-aldol reaction?

A

aqueous base and heat

20
Q

what describes the product of aldol condensaton

A

alpha beta unsaturated carbonyl

21
Q

why is the keto form more stable than the enol form?

A

the keto form puts more electron density around the electronegative oxygen than the enol form.

22
Q

how do you stop the aldol condensation reaction at the aldol rather than following through to the alpha beta unsaturated carbonyl?

A

add acid instead of base