Chemistry (Separating Mixtures and Water Treatment) Flashcards
(76 cards)
The 3 Separation Techniques
1) Filtration
2) Evaporation
3) Crystallisation
The Filtration Separation Technique
Filtration separates an INSOLUBLE SOLID from a liquid (e.g. salt dissolved in water and sand). The liquid FILTRATE passes through the filter paper, the undissolved solid RESIDUE stays on the paper.
Decantation is another way of separating a liquid from an undissolved solid. When a liquid is decanted it is poured very slowly leaving the solid behind.
What Equipment is used in the Filtration Separation Technique?
- Beaker
- Salt solution and sand
- Filter funnel
- Filter paper
- Conical flask
The Evaporation Separation Technique
Evaporation is used to separate a SOLUBLE SOLID form a solution (e.g. salt in water).
The solution is heated, the solvent evaporates leaving the solid solute behind. Unfortunately this method is only useful when trying to collect the solid.
What Equipment is used in the Evaporation Separation Technique?
- Evaporating Basin
- Gauze
- Tripod
- Bunsen Burner
The Crystallisation Separation Technique
Crystallisation is another way of separating a soluble solid from a solution. It is often used when making crystals from a solution where the solvent is water.
Instead of heating the mixture strongly and getting rid of all the water, the solution is put in a warm place and left to evaporate slowly.
When the solution becomes saturated, the crystals will form as more water evaporates. The crystals can be separated from any remaining solution by filtration.
The crystals formed are said to be hydrated and contain water in their structure. If strong heating was used this was would be evaporated away resulting in an anhydrous powder.
What Equipment is used in the Crystallisation Separation Technique?
- Evaporating Basin
- Gauze
- Tripod
- Bunsen Burner
Homogeneous Mixture
(Definition)
A combination of two or more substances where the components are evenly dispersed and do not separate over time. The mixture appears uniform throughout, and you cannot visually distinguish the individual components.
E.g. Coffee, Air, Blood
Heterogeneous Mixture
(Definition)
When the components of the mixture are not in the same phase or the composition of the mixture is UNEVEN throughout
E.g. Sandwich, Pizza, Chocolate-Chip Cookies
Residue
(Definition)
A substance that remains after the main part has gone or been taken or used, maybe after a process such as combustion or evaporation
Filtrate
(Definition)
A fluid that has been passed through a filter
Hydrous
(Definition)
Containing water as a constituent
Anhydrous
(Definition)
Free from water and especially water that is chemically combined in a crystalline substance
Solute
(Definition)
A dissolved substance
Solvent
(Definition)
The liquid in which a solute is dissolved to form a solution
Soluble
(Definition)
Able to be dissolved in a liquid
Insoluble
(Definition)
Incapable of being dissolved
Separating copper sulphate and sand
Method
Part 1: Filtration-
* Add sand, copper sulphate and distilled water to a beaker
* Stir until the copper sulphate has dissolved
* Filter the mixture into another beaker with a filter funnel and filter paper
Part 2: Evaporation-
* Pour half the contents into an evaporating basin
* Put the evaporating basin on a tripod and gauze and heat strongly with a Bunsen Burner
* When the water has evaporated, stop heating and examine the copper sulphate
Part 3: Crystallisation-
* Pour the remaining half of the solution into a crystallising dish and put it on the windowsill or in a tray so that it can be left undisturbed for a few days for the water to evaporate slowly
What was the colour of the filtrate?
(Separating copper sulphate and sand Experiment)
It was bright blue but lighter than the crystals.
This was because copper is a Transition metal, and transition metals are bright coloured solutions.
After the water had been evaporated, copper sulphate was left in the evaporating basin. Describe the appearance of the copper sulphate.
(Separating copper sulphate and sand Experiment)
It was a fine, white powder.
It was white as there was no water left because it had all been evaporated off.
It was a powder as it was heated quickly and aggressively - crystals form over time, so it turned into a powder.
Describe the appearance of the copper sulphate that had been formed by slow evaporation of the solution. Is there a difference between how this looks and the copper sulphate made by evaporation?
(Separating copper sulphate and sand Experiment)
They were larger, blue and crystalline.
The blue shows it was hydrated, meaning there was still some water left.
Conclusion of Separating copper sulphate and sand Experiment
When copper sulphate is obtained by quick evaporation by strong heating of the solution, white anhydrous copper sulphate is formed. This is a powder and is not crystalline. When the solution is allowed to evaporate more slowly, hydrated copper sulphate crystals are formed which are blue. The hydrated copper sulphate contains more water as part of the solid structure which is needed to form the crystal structure.
Distillation
Separates a SOLVENT from a solution
Apparatus for Distillation
- Thermometer
- Round-Bottomed Flask
- Solution
- Condenser
- Delivery Tube
- Beaker
- Distillate
- Solution
- Bunsen Burner
- Tripod
- Gauze