Effect of substrate concentration on enezyme activity

Question 1

What is the substrate in this experiment?

Answer 1

-thing being broken down
-hydrogen peroxide

Question 2

What is the enzyme in this experiment?

Answer 2

-thing breaking down
-catalase

Question 3

Where is catalase found?

Answer 3

in raw potatoes

Question 4

What is the IV?

Answer 4

hydrogen peroxide/substrate concentration

Question 5

What is the DV?

Answer 5

time taken from disc hitting surface to floating up again

Question 6

What are some control variables?

Answer 6

-volume of hydrogen peroxide
-size and type of potato
-paper disc size
-volume of distilled water in paste

Question 7

Describe the concentrations and volume of hydrogen peroxide

Answer 7

-total volume of 10cm3
-concentrations of 2vol, 4 vol, 6vol, 8vol and 10 vol
-eg 2vol: 2cm3 hydrogen peroxide and 8cm3 distilled water

Question 8

Describe the procedure

Answer 8

-grind 3cm piece of potato with 5cm3 distilled water to make enzyme paste
-place 10cm3 of hydrogen peroxide solution into test tube
-use forceps to dip filter paper disk into enzyme suspension, tap off excess
-drop paper disc into hydrogen peroxide solution and measure time from striking surface to floating back up
-remove disco and repeat for next concentration

Question 9

How does this procedure link to the question?

Answer 9

-the catalase enzyme speeds up breakdown of hydrogen peroxide substrate
-time how long it takes for enzymic disc to resurface, meaning reaction is over

Question 10

What kind of results would you expect to see?

Answer 10

as substrate concentration increases, reaction time increases