exam 2 Flashcards
What feature of DNA allows it to store information?
a. the 5’ to 3’ direction of the strands
b. the base sequence
c. the relative locations of the major and minor groove
d. the spiral structure
b. the base sequence
Chargaff’s results suggest that (in DNA),
a. the amount of G = C and A = T.
b. the amount of G = A = C = T.
c. the amount of G = T and A = C.
d. all of the above.
a. the amount of G = C and A = T.
Which of the following could be the components of a single nucleotide found within an RNA strand?
a. deoxyribose, thymine, and phosphate
b. deoxyribose, guanine, and three phosphates
c. ribose, thymine, and phosphate
d. ribose, uracil, and phosphate
d. ribose, uracil, and phosphate
Which component(s) of a nucleotide is/are found along the DNA backbone?
a. bases only
b. deoxyribose and bases
c. phosphate only
d. deoxyribose and phosphate
d. deoxyribose and phosphate
Which of the following is/are ways that a retroelement (retrotransposon) can proliferate?
a. Using reverse transcriptase and integrase
b. Using transposase
c. Target-site primed reverse transcription
d. Both a and c
d. Both a and c
Which of the following is found in a eukaryotic chromosome but not in a bacterial chromosome?
a. Many genes
b. One centromere
c. Some repetitive sequences
d. One or more origins of replication
b. One centromere
A region in a cell nucleus that is occupied by a single chromosome is a
a. nucleosome.
b. radial loop domain.
c. chromosome territory.
d. euchromatic region.
c. chromosome territory.
With regard to chromosome structure, the loop extrusion model proposes that __________ promote loop formation and ___________ stablize the loop.
a. CTCFs, histones
b. SMC proteins, histones
c. CTCFs, SMC proteins
d. SMC proteins, CTCFs
d. SMC proteins, CTCFs
The reason for using chromosome conformation capture (3C) methods is to
a. determine if a gene is transcriptionally active.
b. distinguish interphase chromosomes from metaphase chromosomes.
c. detect changes in chromosome structure.
d. identify DNA segments that are close to together in three-dimensional space.
d. identify DNA segments that are close to together in three-dimensional space.
Protein complexes known as ______________ are responsible for forming ___________ in ___________.
a. condensins, euchromatin, interphase chromosomes
b. cohesins, radial loop arrays, interphase chromosomes
c. condensins, radial loop arrays, metaphase chromosomes
d. cohesins, radial loop arrays, metaphase chromosomes
c. condensins, radial loop arrays, metaphase chromosomes
From a structural point of view, DNA can be replicated to produce two double helices with the identical base sequences because
a. of the AT/GC rule.
b. the strands are antiparallel.
c. of base stacking.
d. DNA polymerase can make DNA only in the 5’ to 3’ direction.
a. of the AT/GC rule.
What are the expected results for the Meselson and Stahl experiment after 4 generations (i.e, 4 rounds of DNA replication in the presence of light nitrogen)? Note: during generation zero, the DNA is all heavy, and subsequent generations only make light DNA.
a. 1/4 half heavy, 3/4 light
b. 1/8 half heavy, 7/8 light
c. 1/16 half-heavy, 15/16 light
d. 1/32 half-heavy, 31/32 light
b. 1/8 half heavy, 7/8 light
At the E. coli origin of replication, the DNA begins to unwind at the
a. DnaA boxes
b. AT-rich region
c. GATC methylation sites
d. None of the above
b. AT-rich region
How many replication forks are formed at an origin of replication?
a. One
b. Two
c. four
d. many
b. two
Primase is needed during DNA replication because DNA polymerase is not able to
a. synthesize DNA in the 5’ to 3’ direction.
b. synthesize DNA in the 3’ to 5’ direction.
c. begin synthesis on a bare template strand.
d. proofread the DNA.
c. begin synthesis on a bare template strand.
How is a new DNA strand made in the leading strand?
a. DNA is made in the direction toward the replication fork and is made as one continuous strand.
b. DNA is made in the direction away from the replication fork and is made as one continuous strand.
c. DNA is made in the direction toward the replication fork and is made as Okazaki fragments.
d. DNA is made in the direction away from the replication fork and is made as Okazaki fragments.
a. DNA is made in the direction toward the replication fork and is made as one continuous strand.
Which of the following is not found in a replisome?
a. two DNA polymerases
b. helicase
c. primase
d. All of the above are found in a replisome.
d. All of the above are found in a replisome.
The proofreading function of DNA polymerase involves the recognition of a ________ and the removal of a short segment of DNA in the __________ direction.
a. missing base, 5’ to 3’
b. base mismatch, 5’ to 3’
c. missing base, 3’ to 5’
d. base mismatch, 3’ to 5’
d. base mismatch, 3’ to 5’
Below is a DNA molecule, with the ends labeled A, B, C and D. Which ends would get shorter during DNA replication if telomerase did not function?
A 5’———————————————–3’ B
C 3’———————————————–5’ D
a. A and C
b. A and D
c. B and D
d. B and C
d. B and C
A small effector molecule that enhances transcription binds to a regulatory protein and causes it to not bind to the DNA. The regulatory protein
a. is a repressor.
b. is an activator.
c. could be a repressor or an activator.
d. s neither a repressor or an activator.
a. is a repressor.
During diauxic growth involving glucose and lactose, bacterial cells
a. use up lactose first, then they metabolize glucose.
b. use up glucose first, then they metabolize lactose.
c. metabolize both sugars at maximal rates at the same time.
d. None of the above
b. use up glucose first, then they metabolize lactose.
Let’s suppose you have isolated a mutant strain of E. coli in which the lac operon is constitutively expressed. You create a merozygote in which the mutant strain also contains an F’ factor with a normal lac operon and a normal lacI gene. You then compare the mutant strain and the merozygote with regard to their β-galactosidase activities in the presence and absence of lactose. You obtain the following results:
Strain Addition of lactose (no glucose) Amount β-Galactosidase
Normal Yes 100
Mutant No 100
Mutant Yes 100
Merozygote No 1
Merozygote Yes 200
Which of the following is consistent with these data?
a. The mutation is in the lacI gene and results in a lac repressor that cannot bind to the operator.
b. The mutation is in the lac operator and prevents the lac repressor from binding to the operator.
c. The mutation is in the lacI gene and results in a lac repressor that cannot bind allolactose.
d. All of the above.
a. The mutation is in the lacI gene and results in a lac repressor that cannot bind to the operator.
For a riboswitch that controls transcription, the binding of a small molecule such as TPP controls whether the RNA
a. has an antiterminator or terminator stem-loop.
b. has a Shine-Dalgarno antisequestor or the Shine-Dalgarno sequence in a stem-loop.
c. is degraded from its 5’ end.
d. has both a and b.
a. has an antiterminator or terminator stem-loop.
What is the role of mediator with regard to eukaryotic gene regulation?
a. Mediator controls the switch to the elongation phase of transcription.
b. Mediator controls whether or not RNA polymerase can bind to the core promoter.
c. Mediator causes histones to be displaced from the core promoter.
d. Mediator controls whether or not TFIID can bind to the core promoter.
a. Mediator controls the switch to the elongation phase of transcription.