IR plastics Flashcards

(40 cards)

1
Q

Why does C-O have a higher wavenumber than C-Cl?

A

C-Cl has a larger mass, and mass is inversely proportional to wavenumber. Therefore the large mass = low wavenumber

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2
Q

Why does C=O have a larger wavenumber than C-O?

A

Higher bond order means higher energy, energy is proportional to wavenumber

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3
Q

Wavenumber is proportional to

A

Energy, frequency, dipole moment

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4
Q

Wavenumber is inversely proportional to

A

wavelength and mass

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5
Q

All materials are

A

different in their atomic, molecular, and bonding compositions

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6
Q

What are polymers

A

macromolecules (large molecules) made up of monomers

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7
Q

what are monomers?

A

repeating units

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8
Q

what does n mean?

A

the number of monomers in a polymer

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9
Q

PETE

A

Polyethylene Terephthalate

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10
Q

HDPE

A

High Density Polyethylene

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11
Q

PVC/V

A

Polyvinyl chloride

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12
Q

LDPE

A

Low Density Polyethylene

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13
Q

PP

A

Polypropylene

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14
Q

PS

A

Polystyrene

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15
Q

Types of molecular vibrations

A

Stretches and bends

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16
Q

Types of stretches

A

Asymmetric and Symmetric

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17
Q

Types of bends

A

In or out of plane and scissor

18
Q

Mixture of different polymers

A

Polymer blend

19
Q

X-Ray Photoelectron Spectroscopy (XPS)

A

identifies the surface chemistry of different plastics including colour and width.

ie. a black plastic would be indecipherable in IR

20
Q

Infrared Spectroscopy (IR)

A

identifies the functional groups of polymers, meaning it can differentiate between plastics of the same family (Polyethylene)

21
Q

If a peak is found at a higher wavenumber what does that mean?

A

that it represents a higher energy dipole bond

22
Q

What does the wavenumber of absorbed light depend on?

A

the atom’s bonding environment (dipoles, bond order, vibration, type of atoms etc)

23
Q

IR light detects what?

A

wavelengths that are absorbed and or transmitted

24
Q

Region left of the peak

A

the functional group region, useful to analyzing specific bonds in unknown structures

25
Region right of the peak
the fingerprint region, unique to every molecule
26
sp², C-H stretch
3000-3100
27
sp³, C-H stretch
2840-3000
28
CH3 Bend
1350-1475
29
CH2 bend
1450-1475
30
C=O stretch
1650-1770
30
C=C ring pair stretch
1400-1500 and 1585-1600
31
C-O stretch
1200-1310
32
C-Cl stretch
550-850
33
O-H stretch
3000 - 3300 usually very broad and weak
34
Type of IR used during this experiment
ATR-IR
35
How do you calculate the amount of light absorbed
measuring intensity of light entering crystal and intensity of light reaching the detector
36
Why does a sp³ occur at lower wavenumbers than sp²?
The double bond of the sigma framework of sp2 requires more energy to break/vibrate bc it has more s character which leads to shorter and stronger bonds.
37
Why does the acetate ion only have a peak at 1400?
Because of the C-H bend that is there (sp^3), because the acetate ion looses the H ion that allows it to vibrate so it vibrates less and the C-O bond is completely eliminated
38
Can IR distinguish well between LDPE and HDPE?
To a certain extent bc one certain peak, but there are other ways that do it better differential scanning calorimetry (DCS) works better because they use physical properties
39
Difference between LDPE and HDPE
LDPE has an "R" group, limiting its bonds with other monomers, leading to a linear structure that is flexible HDPE is a long branching chain of monomers that can pack together, making it firmer and rigid.