LECTURE 11 - Quantitative Inheritance Flashcards

(46 cards)

1
Q

2 TYPES of GENETIC TRAITS

+ difference in terms of…

  • discrete or continuous?
  • described or measured by?
  • effect of environment
  • controlled by how many genes?
A
  1. Quantitative
    - continuous
    - described using measurable units
    - largely affected by the environment
    - controlled by multiple genes
  2. Qualitative
    - discrete (has this trait or not) / categorical
    - classified on either-or bases
    - less affected by environment
    - controlled by 1-2 genes
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2
Q

what do you call a pattern of inheritance where a single gene controls a trait?

what type of genetic trait is this expressed?

what is its opposite?

A

Mendelian Inheritance

or

Monogenic Inheritance

in QUALITATIVE GENETIC TRAITS

r
in quantitative genetic traits, it s called POLYGENIC INHERITANCE

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3
Q

3 TYPES of Quantitative Traits - Polygenic Inheritance

A
  1. Meristic Trait
    - discrete
    - counted as not measurable
    - controlled by many genes
  2. Threshold Trait
    - traits are either present or absent
    - controlled by many genes
  3. Continuous Trait
    - traits are measured (may decimal)
    - controlled by many genes
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4
Q

POLYGENIC INHERITANCE

  • how many genes affect a single trait?
  • each ____ will contribute _____ & ____ to the trait
A
  • multiple genes
  • allele
  • additively and equally

*more dark skin alleles will result n a darker shade

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5
Q

PHENOTYPIC VARIANCE

  • the variance observed across a ____ due to ___
  • denoted by ____
  • formulas (2)?
A
  • population
  • phenotype
  • Vp

1.) Vp = Vg + Ve + Vgxe

Vg - variance due to genotypic differences

Ve- variance due to environmental factors

Vgxe - variance due to interaction of genotype and environment

2.) variance formula so Vp of F1 = variance of all raw quantitative data of F1 phenotype

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6
Q

PHENOTYPIC VARIANCE

  • can this be estimated?
A

It is DIFFICULT TO ESTIMATE but can be assumed to be equal to 0

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7
Q

GENOTYPIC VARIANCE

  • formula?
A

Vg = Va + Vd + Vi

Va = variance due to additive gene effects

Vd = variance due to dominance gene effects

Vi = = variance due to epistatic gene effects (alleles at different loci)

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8
Q

GENOTYPIC VARIANCE

  • can this be measured?
A

It is DIFFICULT TO MEASURE but can be assumed to be equal to 0

UNLESS given in the problem

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9
Q

DETERMINE THE AUTHOR

  • continuous variation is due to MULTIPLE GENES
A

Yule (1906)

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10
Q

DETERMINE THE AUTHOR

  • every gene has a small effect on the character
A

Yule (1906)

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11
Q

DETERMINE THE AUTHOR

  • studied grain color in wheat is a continuous variable
  • found that as NO. OF INDEPENDENT GENES ARE INCREASED, distribution follows a normal curve
A

Herman Nilsson-Ehle

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12
Q

DETERMINE THE AUTHOR

  • proposed the term “polygenes”

(group of genes that influence the expression of a quantitative trait in an additive manner”

A

mather (1943)

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13
Q

example of polygenes (5)

A

kernel color

skin color

corolla length

IQ

crop yield

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14
Q

Metric vs Economic characters

*types of quantitative traits

A

METRIC CHARACTERS
- distributed in a continuous manner
- measurable
(weight, height, head size, limb length)

ECONOMIC CHARACTERS
- grain yield
- seed size
- meat yield

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15
Q

are quantitative traits polygenic

A

yes

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16
Q

are quantitative traits influenced by environmental factors?

+ examples (2)?

A

yes

IQ is affected by nutritous diet + good health + good education

YIELD is affected by soil, climate, and fertilizer

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17
Q

BASIC ASSUMPTIONS for POLYGENIC INHERITANCE

(7)

A
  1. genes do not have individually recognizable phenotypic effects
  2. a series of genes control the trait
  3. genes have cumulative effect
  4. dominance of allele is ordinarily absent**

**instead a series of genes create an additive effect for phenotype

  1. F1 is intermediate of parents
  2. there is appreciable influence of environment
  3. classification of trait is thru measurable units
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18
Q

when will Vp = Ve?

Vp = phenotypic variation
Ve = environmental variation

+ formula for Ve

A

Vp = Ve will only be for P1, P2, and F1

this is because 100% of all individuals in this generation have the SAME genotype…. so, they’re variation would only be based on environmental factors

thus… from the formula Vp = Vg + Ve + (Vgxe)….

Vg = 0

so

Vp = Ve

thus… the value of Ve can be ESTIMATED by (Vp1+Vp2+Vf1) / 3

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19
Q

formula for Vp, Vg, and Va of F2 generation?

A

Vf2 = Vg + Ve

Vg = Vf2 - Ve

Va = 2(Vf2 - VBC1)

20
Q

refers to the proportion of a POPULATION’S (not an individual) phenotypic variation that is attributable to genetic factors

+ 2 types + difference

A

heritability

*used to examine the relative contributions of genes and environments to variation in a specific trait

OR “measures amount of phenotypic variation in a population due to genetic factors”

1.) broad sense - measures full contribution of genetic variation to phenotypic variation

2.) narrow sense - measures only contribution of additive alleles to phenotypic variation

21
Q

HERITABILITY

interpret the ff values of heritability:

  • 0
  • 0.5
  • 1
A
  • 0 = none can be attributed to genotypic variation (only due to environment)
  • 0.5 = 50% of observed phenotypic variation among individuals is due to genotypic variation
  • 1 = 100% of observed phenotypic variation among individuals is due to genotypic variation
22
Q

FORMULA of:

broad sense heritability vs narrow sense heritability

A

BS: h²B = (Vg / Vp)

NS: h²N = (Va / Vp)

23
Q

why is narrow sense heritability more useful to animal and plant breeders?

A

bc narrow sense only takes into consisderation ADDITIVE GENES which are predictable and consistent when passed from gen to gen

broad sense takes into account the FULL CONTRIBUTION of genetic variation (which includes additive, dominance, and epistatic genes) wherein the latter 2 are inconsistent and cannot be predicted

24
Q

is heritability fixed for a trait?

A

no.,.. it is dependent on genetic make up and environment

SO varies across generations

25
FORMULA for determining the phenotypic contribution of EACH ALLELE for a quantitative trait? + check lec vid for practice problems
contributory effect per allele = [(largest phenotype - smallest phenotype) / 2n] wherein n = number of gene pairs controlling the trait *largest phenotype: homo dominant *smallest phenotype: homo recessive
26
FORMULA for the number of gene pairs controlling a quantitative trait
n = [log (total # of progeny / frequency of extreme phenotype)] ----- [log 4] *extreme phenotype can EITHER be the biggest or smallest amount of individuals with a specific phenotype
27
FORMULA for the quantitative phenotype based from genotype
Phenotype = [(no. of contributory alleles x CEPA) + basal phenotype --- Contributory alleles = dominant alleles Basal phenotype = the lowest phenotype (homozygous recessive or all: aaaaa)
28
how many contributory alleles in here: AAAAa AAaaa
1.) 4 2.) 2
29
2 ways to determine the GENOTYPIC PHENOTYPIC ratio of F2 + notes to remember
1. Binomial expansion - study solving *first and last term has 1 as its coefficient *in (a+b)^[2n] a = A (contributory / dominant) b = a (non-contributory / recessive) * a = 2n to 0 * b = 0 to 2n 2. Pascal's triangle - study solving
30
FORMULA for phenotype for F1 or F2
phenotype of homo recessive parent + (number of dominant alleles x contributory effect per allele)
31
PROBLEM SOLVING: GIVEN: AAAA = 100 g aaaa = 20 g number of gene pairs = 4 find the: 1. contributory effect per allele 2. phenotype of F1 3. phenotype of F2 4. frequencies of F2
1.) (100 g / 20 g) / (2*4) = 10g / allele -- 2.) 20g + (4) (10g) = 60g -- 3.) use binomial / pascal OR use same formula as number 2 OR manually do the phenotypes, wherein at: 0 contributory alleles = 20g 1 contributory allele = 30g 2 contributory alleles = 40g .... 20g is lowest phenotype so it occurs at phenotype with 0 contributory / dominant alleles 4.) use coefficient based on binomial / pascal triangle
32
what is LARGEST and SMALLES phenotype? + what do u call this both?
*largest phenotype: homo dominant *smallest phenotype: homo recessive both are considered as "extreme phenotypes"
33
CRITERIA for n to be a valid estimate (3)
1. Alleles must have equal and additive effects. 2. Genes assort independently. 3. Original parents are homozygous.
34
EFFECT of the ff to quantitative traits: 1. dominance 2. epistasis
1. average phenotype of F1 is closer to the dominant parent 2. graph is asymmetric and skewed towards one parent
35
FORMULA for finding the no of gene pairs (2)
1.) extreme phenotype = 1/(4^n) 2.) n = (D^2) / (8*Vg) wherein D = difference of the MEAN of P1 and P2 Vg = genotypic variance of F2 (Vg = Vf2 - Ve)
36
ROUNDING OFF RULES 9.49 9.50
9.49 = 9 9.5 = 10 *round off based on first decimal place
37
is QTL associated with environmental factors and quantitative traits?
yes
37
WHAT IS a map location for a chromosomal region that is associated with a trait
Quantitative Trait Loci (QTL)
38
used for studying presence of specific genes
QTL
39
aims to localize chromosomal regions that affect variation of quantitative traits in a population
QTL mapping
40
statistical method that links phenotypic and genotypic data to explain genetic basis of variation in complex traits
QTL analysis
41
what is used to map the position of QTL?
molecular markers - since it is associated consistently associated with inheritance of a trait - unlikely to affect trait of interest
41
3 examples of molecular markers
DNA MARKERS 1. single nucleotide polymorphisms 2. simple sequence repeats 3. restriction fragment length polymorphisms
41
TRAITS of longest-lived people in blue zone?
1. Move Naturally every 20 minutes 2. Life Outlook (time for happy hours, emotional wellbeing, dreams and goals) - 15% lower risk of dying + live up to 7 years 3. Diet - wine: 2-4 glasses per day - plant-based diet - max 80% full 4. Connections (relationships) : live up to 4 to 14 years longer
41
Danish Twin Studies - author? - results on life span of twins?
- Dan Buettner - 20% genetics ; 80% lifestyle and environment
41
CASE STUDY - Twins - how many twins were studied? - BROAD sense heritability value of propensity for divorce?
- 1500 + parents + spouses - 52% (goes up by 6x in identical twins; max 2x for fraternal)