Module 2 - Amount of Substance Flashcards

(59 cards)

1
Q

define relative atomic mass

A

weighted mean mass of an atom relative to 1/12th of the mass of one atom of carbon 12

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2
Q

define relative formula mass

A

term used when working out the calculation for compounds with giant structures

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3
Q

examples of giant structures for relative formula mass

A

giant ionic, giant covalent, giant metallic

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4
Q

define relative molecular mass

A

term used when working out the calculation for compounds that are simple molecules

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5
Q

equation for percentage of an element

A

number of atoms of element x relative atomic mass of element / relative formula mass of compound x100

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6
Q

define molar mass

A

the mass per mol of a substance in g mol^-1

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7
Q

what does the mass of one mole equal

A

the ar of that substance

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8
Q

define amount of substance

A

chemists use amount of substance as a means of counting the number of particles in a substance. its unit is the mole (mol)

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9
Q

define avogadros constant

A

6.02 x 10^23. the number of atoms per mole of carbon 12

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10
Q

equation for number of atoms/ions/molecules

A

moles x 6.02x10^23

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11
Q

equation for number of mols

A

mass (g) / molar mass

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12
Q

units for molar mass

A

g mol -1

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13
Q

define molecular formula

A

the number and type of atoms in each element of a molecule

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14
Q

define empirical formula

A

shows the simplest whole number ratio of atoms of each element in a compound

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15
Q

steps to calculate empirical formula

A
  • calculate number of moles
  • divide number of moles by smallest value for a ratio
  • adjust to make ratios whole numbers
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16
Q

define water of crystallisation

A

water molecules that are bonded into a crystalline structure of a compound

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17
Q

what does heated hydrated copper sulfate form

A

anhydrous copper sulfate + water

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18
Q

symbol equation for heating copper sulfate

A

CuSO4 . 5H2O -> CuSO4 + 5H2O

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19
Q

define hydrated

A

a crystallised compound containing water molecules

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20
Q

define anhydrous

A

contains no waters of crystallisation

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21
Q

method for calculating amount of water

A

-weigh the crucible
-add a known amount of hydrated salt
-weigh the crucible and hydrated salt together
-heat the hydrated salt strongly for a few minutes
-weigh and heat the sample until the mass stays constant

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22
Q

assumptions in calculating amount of water

A

-assuming all water has been lost by heating to constant mass
-when heating the salt its not breaking down further to other compounds

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23
Q

define molar gas volume

A

the volume per mole of gas molecules at the stated temperature and pressure (RTP)

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24
Q

room temperature

25
room pressure
101 kPa
26
what is the volume of a gas at RTP
1 mole of gas is 24.0dm^3
27
equation for volume of a gas in dm^3
moles = volume (dm3) / 24
28
equation for volume of a gas in cm^3
moles = volume (cm3) / 24,000
29
ideal gas equation
pV = nRT
30
degrees to kelvin conversion
add 273
31
kPa to Pa
add x10^3 on the end
32
cm^3 to m^3
add x10^-6 on the end
33
dm^3 to m^3
add x10^-3 on the end
34
ideal gas equation in words
volume x pressure = amount of gas x ideal gas constant x temperature
35
volume units in ideal gas equation
m^3
36
pressure units in ideal gas equation
Pa
37
amount of gas units in ideal gas equation
mol
38
temperature units in ideal gas equation
K
39
define stoichiometry
-the ratio, of the amount in moles, of each substance in a chemical reaction
40
steps for stoichiometry calculation
-write mr of substance known and unknown -calculate moles of known -ratio for moles of unknown -work out question
41
steps for limiting reactant calculation
-calculate moles for both reactants -do a ratio of how much you need for each one -use the limiting reactant moles to work out the rest of the question
42
units for concentration
mol dm^-3
43
equation for number of moles (concentration)
volume x concentration / 1000
44
units of volume in concentration equation
cm^3
45
why do you divide by 1000 in the concentration equation
to convert volume to dm^3
46
what is percentage yield
the amount of product made from the starting materials
47
why does no reaction ever have 100% yield
-the reaction may have not gone to completion -side reactions may have occurred -purification of the product may have resulted in loss of product
48
percentage yield equation
actual moles/ theoretical moles x 100
49
percentage yield calculation steps
-workout mr or the reactant and product you have a mass for -work out the actual moles (mass of the product) -workout the theoretical moles (mass of the reactant-> ratio) -put in equation
50
what happens in an ideal reaction
-all reactant atoms end up within the useful product molecule -no waste is produced
51
which reactions have low atom economy
-inefficient, wasteful reactions
52
which reactions have high atom economy
-efficient processes have high atom economy
53
why are high atom economy reactions important
-sustainable development -conserve natural resources -create less waste
54
atom economy equation
sum of molar masses of all desired products / sum of molar masses of all products x100
55
what is atom economy a measure of
-the proportion of reactant included in the final useful product
56
how are atom economy and percentage yield linked in a reaction
a reaction can have a -high percentage yield -low atom economy
57
what is the percentage atom economy if a reaction has 1 product
100%
58
define mole
the amount of any substance containing as many particles as there are carbon atoms in 12g of carbon 12 (6.02x10^23 particles)
59
which reactant do you use for theoretical moles in percentage yield if there are multiple
the limiting reactant