Mole Concept and Stoichiometry Flashcards

(86 cards)

1
Q

basic unit/quantities

A

mole

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2
Q

of atom/element/compound

A

mole

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3
Q

avogadro’s number

A

6.02x10^23

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4
Q

are non-zero digits and any zeroes contained between non-zero digits counted as significant figures

A

yes

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5
Q

how many significant figures in 300042

A

6 significant digits

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6
Q

are leading zeroes significant

A

no

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7
Q

how many significant figures in 0.0000034

A

2 significant figures

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8
Q

do trailing zeroes count if there is a decimal point

A

yes

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9
Q

how many significant figures in 0.0002500

A

4 significant digits

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10
Q

can trailing zeroes count if there is no decimal point

A

no

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11
Q

how many significant figures in 19000000

A

2

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12
Q

formula for molar mass

A

mass(g)/moles (mol)

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13
Q

illustrate the mole map

A

grade yourself accordingly

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14
Q

Determine the mass (g) of 2.50 moles of Na

A

57.5g (3 s.f.)

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15
Q

How many moles are present in 50.0g in MgCl2?

A

0.525 moles

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16
Q

How many Fe atoms are present in 10.0 moles of Fe

A

6.02π‘₯10^24 π‘Žπ‘‘π‘œπ‘šπ‘  𝐹𝑒

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17
Q

Calculate the # of molecules present in 25.0g of CH3COOH (acetic acid)

A

2.51π‘₯10^23 π‘šπ‘œπ‘™π‘’π‘π‘’π‘™π‘’π‘  π‘œπ‘“ 𝐢𝐻3𝐢𝑂𝑂𝐻

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18
Q

Determine the # of Al atoms in 25.0 moles Al2S3

A

3.01π‘₯10^25 π‘Žπ‘‘π‘œπ‘šπ‘  𝐴𝑙

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19
Q

2 moles of Na is allowed to react with excess Cl2 to produce NaCl. Determine the # of moles of NaCl formed after the reaction

A

2 π‘šπ‘œπ‘™π‘’π‘  π‘π‘ŽπΆπ‘™

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20
Q

What mass (g) of Mg is needed to react with excess oxygen gas to produce 2.0 moles of MgO

A

48.608𝑔 π‘œπ‘“ 𝑀𝑔

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21
Q

used to refer to extremely small particles such as atoms, molecules, and ions

A

mole

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22
Q

SI unit to denote the amount of substance

A

mole

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23
Q

amount of substance that contains as many elementary particles as in 0.12kg of carbon-12.

A

mole

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24
Q

experimentally determined value to describe a mole of a pure substance

A

6.02x10^23

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25
honored using the Avogadro’s number
Amadeo Avogadro
26
1 mole of any substance = ____particles
6.02x10^23
27
1 mol of Ag atom will contain ___ Ag atoms
6.02x10^23
28
born on August 9 1776 in Turin Piedmont-Sardinia (now part of Italy)
Lorenzo Romano Amadeo Carlo Avogadro
29
father of Avogadro (lawyer), well-known magistrate and senator in Piedmnt region of northern Italy
Fillippo Avogadro
30
Avogadro’s mother, a noblewoman
Anna Vercellone of biella
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Avogadro received his doctorate in ecclesiastical law
age of 20
32
Three different types of molecules that Avogadro described
integral molecule constituent molecule elementary molecule
33
when did Avogadro stated that β€œequal volumes of all gases at the same temperature and pressure contain the same number of molecules”
1811
34
was given as equivalent to 1/12 the mass of carbon-12 and that all other atomic masses of the elements are determined relative to carbon 12
atomic mass (amu)
35
as such as the mass in grams of one mole of any substance is called with the unit of grams/mole
molar mass
36
Determine the molar mass of the following compounds: A. MgO
40.303 g/mol
37
Determine the molar mass of the following compounds: H2SO4
98.5206 g/mol
38
Determine the molar mass of the following compounds: Zn3(PO4)2
=386.08 𝑔/π‘šπ‘œπ‘™
39
Francium, the alkali metal named after France, was discovered by Marguerite Perey in 1939. Though known to be radioactive, as of today it has no known uses because it is unstable and rare. Determine the number of atoms present in 2.50 moles of Francium, Fr.
1.505525π‘₯1024 π‘Žπ‘‘π‘œπ‘šπ‘  π‘œπ‘“ πΉπ‘Ÿ
40
Lithium is an element that produces a red flame. Calculate the number of moles in Li in 7.35x1024 atoms of Li
12.20504475 π‘šπ‘œπ‘™π‘’π‘  π‘œπ‘“ 𝐿𝑖
41
Incomplete combustion of fuels produce carbon monoxide, a colorless, tasteless, odorless poisonous gas. Calculate the number of CO molecules present in 4.50 moles of CO.
2.709945π‘₯1024 π‘šπ‘œπ‘™π‘’π‘π‘’π‘™π‘’π‘  𝐢𝑂
42
Convert 5.78x1022 molecules released in the atmosphere in number of moles
0.09597980771 𝐢𝑂 π‘šπ‘œπ‘™π‘’π‘π‘’π‘™π‘’π‘ 
43
determines the number of moles present for every mole of the compound
subscript
44
Nitrous oxide with the molecular formula N2O is also known as laughing gas. It is colorless and odorless and is known to have analgesic and anesthetic purposes Calculate the mass (g) of 8.75 moles N2O
385.09625 𝑔 𝑁2𝑂
45
Nitrous oxide with the molecular formula N2O is also known as laughing gas. It is colorless and odorless and is known to have analgesic and anesthetic purposes If the mass of N2O is 35.89g, what is the corresponding number of moles?
0.8154 π‘šπ‘œπ‘™π‘’π‘  𝑁2𝑂
46
Hydrogen cyanide, HCN, also known as prussic acid is a toxic compound that boils above 26oC. It can readily be absorbed through inhalation, ingestion, or even by dermal exposure. Calculate the number of moles of H atom present in 2.50 moles of HCN
2.50 π‘šπ‘œπ‘™π‘’π‘  𝐻
47
Determine the number of N atom present in 1.25g of HCN
2.784685525π‘₯1022 π‘Žπ‘‘π‘œπ‘šπ‘ 
48
Compute the mass in grams of H and N atoms present in 5.85 moles of HCN
81.90351 𝑔 𝑁
49
used as a safety device in most vehicles
air bags
50
occurs that allow the air bag to inflate and provide protection during collision
chemical reactions
51
its decomposition to sodium metal and nitrogen gas is the main chemical reaction involved
sodium azide
52
also incorporated in air bags to ensure that the bag is inflated enough
oxidizers
53
ordinary airbag has what volume
36 liters
54
hwow many sodium azide must be decomposed to produce the volume of 36 liters of nitrogen gas
130g sodium azide
55
science of measuring the quantitative proportions or mass ratios in which chemical elements stand to one another
stoichiometry
56
Stoicheion means
element
57
metron means
measure
58
involves the mass relationships between reactants and products in a chemical reaction
stoichiometry
59
all reaction stoichiometry relationships start here
balanced chemical equation
60
gives the relative numbers of moles of reactants and products
equation
61
is used to solve problems from the balanced equations
ratios
62
N2 + 3H2 -> 2NH3 how many are the following: Number of atoms: ___ atoms of Nitrogen, _ atoms of Hydrogen, and _ atoms of ammonia
Number of atoms: 2 atoms of Nitrogen, 6 atoms of Hydrogen, and 8 atoms of ammonia
63
N2 + 3H2 -> 2NH3 how many are the following: Number of molecules: _ molecule of Nitrogen, _ molecules of hydrogen, and _ molecules of ammoni
Number of molecules: 1 molecule of Nitrogen, 3 molecules of hydrogen, and 2 molecules of ammoni
64
N2 + 3H2 -> 2NH3 how many are the following: Number of relative moles: _ mole of nitrogen, _ relative moles of hydrogen, _ relative moles of ammonia
Number of relative moles: 1 mole of nitrogen, 3 relative moles of hydrogen, 2 relative moles of ammonia
65
N2 + 3H2 -> 2NH3 how many are the following: Mass: of Nitrogen, of Hydrogen, of ammonium
Mass: 28.012g of Nitrogen, 6.0468g of Hydrogen, 34.0588g of ammonium
66
N2 + 3H2 -> 2NH3 how many are the following: volume: of Nitrogen, of Hydrogen, of ammonium
Volume: 22.4L of nitrogen, 67.2L of hydrogen, and 44.8L of ammonia
67
Magnesium metal can react with dry ice (solid CO2) to produce magnesium oxide and carbon. The chemical reaction is shown below 𝑀𝑔 (𝑠)+𝐢𝑂2 (𝑠)→𝑀𝑔𝑂 (𝑠)+𝐢 (𝑠) Balance the chemical equation
2𝑀𝑔 (𝑠)+𝐢𝑂2 (𝑠)β†’2𝑀𝑔𝑂 (𝑠)+𝐢 (𝑠)
68
Magnesium metal can react with dry ice (solid CO2) to produce magnesium oxide and carbon. The chemical reaction is shown below 𝑀𝑔 (𝑠)+𝐢𝑂2 (𝑠)→𝑀𝑔𝑂 (𝑠)+𝐢 (𝑠) Determine the number of moles carbon produced when 5.0 mole of Mg is used
=2.50 π‘šπ‘œπ‘™π‘’π‘  𝐢
69
Magnesium metal can react with dry ice (solid CO2) to produce magnesium oxide and carbon. The chemical reaction is shown below 𝑀𝑔 (𝑠)+𝐢𝑂2 (𝑠)→𝑀𝑔𝑂 (𝑠)+𝐢 (𝑠) c. If 10.0 moles of MgO must be obtained, how much CO2 is needed
5.0 π‘šπ‘œπ‘™π‘’π‘  𝐢𝑂2
70
Magnesium metal can react with dry ice (solid CO2) to produce magnesium oxide and carbon. The chemical reaction is shown below 𝑀𝑔 (𝑠)+𝐢𝑂2 (𝑠)→𝑀𝑔𝑂 (𝑠)+𝐢 (𝑠) If the amount of Mg in letter b is totally consumed, how much CO2 is required
2.50 π‘šπ‘œπ‘™π‘’π‘  𝐢𝑂2
71
is an effective cleaning agent commonly found in households. It contains sodium hypochlorite, NaClO, which can produce toxic chlorine gas, Cl2, when combined with muriatic acid (HCl).
bleach
72
𝐻𝑂𝐢𝑙+𝐻𝐢𝑙→𝐻2𝑂+𝐢𝑙2 Determine the number of moles of Cl2 produced from 15.0g HOCl
0.286 π‘šπ‘œπ‘™π‘’ 𝐢𝑙2
73
𝐻𝑂𝐢𝑙+𝐻𝐢𝑙→𝐻2𝑂+𝐢𝑙2 What mass (g) of HCl is needed to completely react with 4.50 moles HOCl
164.0421𝑔 𝐻𝐢𝑙
74
is the starting material that is totally consumed when the chemical reaction is completed
limiting reagent or reactant
75
It limits the amount of product that is formed in a chemical reaction
limiting reagent
76
In most cases, problems dealing with limiting reagents give the amount (mass or moles) of both reactants
limiting reagent
77
How many moles of water can we make from 6 moles of hydrogen and 4 moles of oxygen? 2 𝐻2 (𝑔)+ 𝑂2(𝑔)β†’2𝐻2𝑂(𝑔)
limiting reagent = H2 Amount of H2O = 6 moles
78
What mass of iron in grams could be formed from 113g Al and 279g Fe2O3 2 𝐴𝑙 (𝑠)+ 𝐹𝑒2𝑂3 (𝑠)β†’ 𝐴𝑙2𝑂3 (𝑠)+2 𝐹𝑒 (𝑙)
limiting reactant Fe2O3 amount of Fe = 195g
79
What mass of C3H3N in grams can be made when 21.6g of C3H6 react with 21.6g of NO 4𝐢3𝐻6(𝑔)+6 𝑁𝑂(𝑔)β†’4𝐢3𝐻3𝑁(𝑠)+6𝐻2𝑂(𝑙)+𝑁2(𝑔)
25.5𝑔 𝐢3𝐻3𝑁 limiting reagent 21.6g
80
Consider the reaction between magnesium and carbon dioxide: 𝑀𝑔 (𝑠)+𝐢𝑂2→𝑀𝑔𝑂 (𝑠)+𝐢 (𝑠) If 4.50g each of Mg and CO2 were reacted, how many grams of carbon will be produced?
limiting reagent = Mg carbon produced = 1.11g C
81
Consider the reaction between magnesium and carbon dioxide: 𝑀𝑔 (𝑠)+𝐢𝑂2→𝑀𝑔𝑂 (𝑠)+𝐢 (𝑠) How much of the excess reagent will be left after the reaction?
0.43𝑔 𝐢𝑂2
82
ratio of actual yield/theoretical yield
percent yield
83
formula of percent yield
actual yield/theoretical yield x 100
84
amount of product made under ideal conditions, the most possible product you can make (almost never happens), the number you calculate using stoichiometry
theoretical yield
85
amount of product made during the actual reaction in the laboratory
actual yield
86
If the amount of carbon obtained in sample exercise 2.2 is 1.00g, determine the percentage yield of the reaction theoretical yield = 1.11g
90.1%