Part 2: Individual To Social Preferences Flashcards

(34 cards)

1
Q

Political institutions are not neutral. If they were neutral, what would be the effect on economic policy

A

No effect

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2
Q

2 key challenges of turning individual preferences into social preferences

A

Aggregation problem

Agency problem

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3
Q

Aggregation problem

A

Whether majority preference be applied

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4
Q

Agency problem

A

Information problem - does political process (voting) ensure majority preference will be achieved

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5
Q

Stable match

A

When no unmatched partner each prefers the other to their partner (not mutually profitable to break away)

E.g a married couple, NEITHER wants to join up with someone from another pair to make them mutally better off.

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6
Q

Stable roommate problem with 4 agents

Pick from other 3 in order.

Look at table pg 16:
A) is a room with Henry and Mary, and a second room with Peter and Jack stable?

B) a room with M+P, and room with J+H

C) room with M+J and room with P+H

A

Not stable, as Mary would prefer to be with Peter, as well as Peter prefer to be with Mary than Jack. Thus Mary and Peter are the blocking pair (mutually profitable: thus unstable)

B)
Not stable as Henry would prefer to be with Peter than Jack, and Peter would rather be with henry than Mary.
Thus Henry and Peter are blocking pair, deviation is mutually profitable: thus unstable!

C) stable as even though not all got first choices, no mutually profitable deviation

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7
Q

Arrow’s impossibility theorem

A

No mechanism is able to aggregate consistently i.e satisfy all 5 properties , thus political institutions cannot be neutral

Hence why called impossibility theorem

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8
Q

So no system that aggregates individual preferences consistently and satisfies 5 properties

What are the 5 properties for social welfare function

A

Unrestricted domain
Rationality
Unanimity
Independence of irrelevant alternatives (IIA)
Non-dictatorship

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9
Q

3 policy options Ω = [A, B, C]

Each individuals has preferences which are complete and transitive and strict: Meaning.

A

Completeness: either A>B or B>A

Transitivity: if A>B and B>C, A>C

Strict: no indifference

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10
Q

What is the mapping of individual prerences into social preference called

A

Social welfare function (SWF)

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11
Q

So explain the first 4 properties SWF needs to satisfy

A

Unrestricted domain (universality) - consider all preferences

Rationality (complete and transitive) (agenda-setting voting method violates!)

Unanimity i.e if everyone agrees A>B policy, SWF preference should prefer A>B

Independence of irrelevant alternatives: if we are trying to figure out whether society prefers A to B, what people think of C shouldn’t matter (irrelevant - just concentrate on issue at stake) (Borda count can violate this!)

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12
Q

Sad result Arrow’s impossibility theorem of SWF satisfying all 4 properties:

A

If satisfies all 4, it must be a dictatorship (i.e the SWF only accounts for the same certain individual’s preferences, ignoring anyone elses’)

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13
Q

So to avoid dictatorship, we can ignore other of the 4 properties

a) if we violate unrestricted domain what does this mean

b) example of violating rationality

c) when can unanimity be violated

d) example of violating IIA

A

violating unrestricted domain means ignoring some individuals preferences

b) condorcet paradox in pair-wise majority voting - completeness and transitivity violated, hence why have to solve other ways to break tie e.g voting agenda , which reduces legitimacy of outcome!

c) if fixed social preferences (regardless of individiual preferences)

d) borda count

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14
Q

Which one is the strongest property

A

IIA , since assuming IIA mean we ignores cardinal aspect of preferences, only ordinal pair-wise.

E.g if 100 policy options, and A and B ranked 45 and 47, you near indifferent between them.

However if ranked 1 and 100, you probably like A a lot more. IIA treats the 2 cases as the same

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15
Q

So this stuff looked at aggregation problem.

Now look at voting rules. What is a condorcet winner

A

Policy that beats any other feasible policy in a pair-wise vote

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16
Q

Condorcet paradox:

A

Some voting rules can fail to produce a clear cut winner

17
Q

Condorcet paradox ice cream example pg37

18
Q

pg 38 ice cream example of concordet winner

A

no clear winner in a pairwise

19
Q

3 citizens with the following preferences:
A>B>C;
B >C>A;
C>A>B

A

Cycling outcome - there is no social transitivity!
A vs B: A wins
B vs C: B wins
C vs A: C wins

concorcet paradox! no clear winnerh

20
Q

When there is a cycling outcome i.e no transivity;

What do agents have an incentive to do

A

agents may not truthfully reveal their preference since a cycle, so vote strategically to get next best

21
Q

So we have chocolate vanilla or strawberry. How many strong preferences (no indifferences) ordering possibilities are there

b) as a result, how many possible socieites

A

6

b) 6 x 6 x 6 = 216 possible societies (since 3 agents)

23
Q

when would the cyclical outcome (condorcet paradox) occur

A

If one of the alternatives is ranked once first by one voter, 2nd by another voter, and 3rd by the last voter

(like 3 citizens with the following preferences:
A>B>C;
B >C>A;
C>A>B)

24
Q

given 6 strong preference orderings, and 216 possible societies, how many times will lead to a cycle?

b) what can we conclude; what is the probability of a condorcet cycle (not finding a winner)

A

12

b) 12/216 societies we get a cycle! so condorcet voting (pairwise comparisons) mostly works to find a clear winner!

probability of not finding a winner is 12/216 x 100 = 5.56%
(we see how this probability changes with the number of alternatives and voters!)

25
Q

What does probability of finding a condorcet cycle (no clear winner) changes with (2)

And state the relationship with them

A

Number of alternatives (policy options - only had 3 in example) POSITIVE REL

Number of voters - POSITIVE REL

26
this is bad for voting organisers, since more candidates and more voters lower chance of finding a clear winner
27
Pg 44 voting exercise q1
show majority voting yield intransitivity: A vs B: A wins. B vs C: B wins, C vs A: C wins thus no clear winner; condorcet cycle What is odd: Tim’s are ordered strange, right>left>middle
28
Q2 pg 45
Tim can vote strategically; B vs C: he prefers C, but he knows B vs C, B wins! thus now he must try get his 2nd best option, A. So stage 1 vote B (vote strategically not sincerely) This is so in stage 2 it is the winner vs A, so A vs B. Which , A wins! So he votes untruthfully to get his 2nd best option rather than B. However B wins anyways regardless of voting C, so Tim’s vote is not decisive!
29
pg 45 q3
Vote strategically and vote A over C, despite preferring C. since A can win, which is pitted against B, and then A beats B so Tim gets his 2nd best option again. (if he stayed true to preference, C wins, and then loses to B, which his worst outcome
30
issues of condorcet (pairwise) voting) (3)
Fair, but time consuming to find winner in large set (thus there are modifications for large sets) Doesn’t always lead to a winner (increases probability of not finding winner with number of candidates and voters). which is problem as doesn’t give incentive to tell truth. Also need to solve by other ways to break cyclical outcome e.g new voting rules , repeat voting etc which reduce legitimacy of outcome
31
Now explore different voting rules and their outcome Simple majority voting. Look at graph pg 47; what is this system, and what is problem
Rule: everyone indicates most preferred option. the policy with most votes wins. so, A would win! problem: given public info… Incentives for voters 4 5 6 and 7, prefer at least 2 other policies to A, e.g 4 and 5 would rather C than A, so vote C as their most preferred option to get 4 votes for C, so C wins! (so 4 and 5 get their 2nd best option of C)
32
another voting method: Agenda setting b) issue
Policies voted in pairwise comparison, in a pre-established order (sequence chosen by agenda) b) violates rationality as no transitivity
33
Borda count
Weights different preferences Most preferred alternative gets k points, next most preferred gets k-1 Winning alternative is one with max number of points
34
Borda count example: if k=2, using pg 47 preferences, who wins and how many points does A B C D get
B is voted 1st by voter 4 and 5, so 2 give 2 point = 4 then voted 2nd best by voters 123 so 3 points 3+4 = 7 points for B A has 3 votes for 1st place, so 6 points C = 6 points D = 2 points
35
What if Borda k=3? Which assumption is violated? and why??
Issue, C then wins! Violates IIA, as ranking has not changed, only the scoring rule, yet the winner did!