Periodicity Flashcards

(15 cards)

1
Q

State and explain how melting and boiling points change from Na and Al.

A
  • ionic charge increases and number of delocalised electrons increases
  • so electrostatic attraction / metallic bonding increases
  • therefore there is more energy required to break the metallic bonds
  • and so the melting / boiling point increases
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2
Q

State and explain how melting points change across period 3, from Na to Ar.

A
  • from Group 1 to Group 3, melting point increases as metallic bonding increases
  • Group 4 has a high melting point as it has a giant covalent structures and there many covalent bonds to be broken
  • Group 5 to Group 8 are simple covalent molecules with London forces between molecules, which are weak, and so require less energy to overcome
  • so have lower melting points
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3
Q

State and explain the trend in atomic radii down the group.

A
  • nuclear charge increases
  • shielding increases, and there are more full shells
  • there is an overall decrease in nuclear attraction
  • so the atomic radii increases
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4
Q

State and explain the trend in atomic radii across a period.

A
  • nuclear charge increases
  • similar shielding
  • outer electrons are more attracted to the nucleus and so there is a greater nuclear attraction
  • so atomic radii decreases
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5
Q

What is the first ionisation energy ?

A

the energy needed to form one mole of gaseous 1+ ions from gaseous atoms

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6
Q

What is the equation for the first ionisation energy of Na ?

A

Na (g) => Na+ (g) + e-

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7
Q

What are the three factors that affect the size of ionisation energy ?

A
  • the atomic radius (distance from the nucleus )
  • electron shielding ( number of full electron shells )
  • nuclear charge ( pulling power of the nucleus )
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8
Q

What is electron shielding ?

A

the number of full electron shells

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9
Q

What is successive ionisation energy ?

A

a measure of the energy required to remove each electron in turn

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10
Q

State and explain the trend in ionisation energy down a group.

A
  • atomic radius increases and shielding increases
  • so overall nuclear attraction decreases
  • so 1st ionisation energy increases
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11
Q

State and explain the trend in ionisation energy across a period.

A
  • nuclear charge increases
  • similar shielding
  • atomic radius decreases
  • more energy required to remove the highest energy electron, so 1st ionisation increases
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12
Q

Where in the periodic table are the smallest first ionisation energies ?

A

bottom left

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13
Q

Where in the periodic table are the largest first ionisation energies ?

A

top right

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14
Q

Why is there a drop in ionisation energy between groups 2 and 3 ?

A
  • highest energy in Gp 2 is in 2s, whereas in Gp 3 it is in 2p
  • 2p is higher energy than 2s
  • so less energy is required to remove an electron from 2p than 2s
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15
Q

Why is there a drop in ionisation energy between Gp 15 and Gp 16 ?

A
  • both Gp 15 and Gp 16 have the highest energy electron in 2p
  • Gp 15 has unpaired electrons, whereas Gp 16 has paired electrons, so has more repulsion
  • therefore less energy is required to remove the highest energy electron
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