Quiz 3 Flashcards
(37 cards)
How soluble is oxygen in water? (5)
At maximum saturation, there is only about 14.6 mg/L of oxygen
This is about 14.6 ppm in fresh water
This happens at 0 degrees
Cold water has a higher dissolved oxygen concentration
Boiling water has zero dissolved oxygen
What are the 3 core environmental factors that control how soluble oxygen is in the water?
Temperature - oxygen solubility declines with increasing temperature
Salinity - oxygen solubility declines with increasing salinity
Atmospheric pressure - oxygen solubility declines with decreasing atmospheric pressure (increasing elevation)
Why is dissolved oxygen important? (4)
Anything below 5.0ppm becomes stressful for fish
Anything below 3ppm becomes lethal for fish
The presence of dissolved oxygen is critical to sustaining any aerobic life in lakes
Salmonids in particular require high concentrations of dissolved oxygen to survive and reproduce
Why should we not use % saturation to describe oxygen concentrations in water?
Because is is confusing and misleading - as temperature increases, dissolved oxygen decreases but % doesn’t show all the details
Orthograde (2)
Oxygen concentration increases with depth (increases at the thermocline then stays steadily high throughout hypolimnion)
Found in cold, deep, oligotrophic lakes
Why do oxygen concentrations increase with depth in oligotrophic lakes? (4)
Decreasing temperatures
Increased hydrostatic pressure
Therefore % saturation stays the same with depth (related to increase in pressure)
And mg/L increases at the thermocline then steadies out
Clinograde (3)
Oxygen concentrations decrease with depth due to biological and chemical demands for oxygen
Found in eutrophic lakes
Decreases at thermocline and continues decreasing (unlike orthograde which settles out)
Dissolved oxygen profiles and seasonal stratification (4)
When combined with seasonal stratification, we get “typical” profiles in oligotrophic and eutrophic lakes
Spring and fall turnover are mixing so oxygen is high in both
Oligotrophic lake - summer stratification looks opposite of temperature/ density stratification (Orthograde)
Winter stratification - steady high oxygen
Eutrophic lake - summer stratification has medium oxygen at surface and decreases very quickly with depth so there is no oxygen in the hypolimnion (Clinograde)
Winter stratification has higher oxygen but decreases gradually with depth throughout hypolimnion (isn’t steady like in oligotrophic lake) = might have to worry
Metalimnetic oxygen maxima (4)
Variation for dissolved oxygen on typical seasonal profile
Sudden blip of oxygen increase at the thermocline
Also known as a positive heterograde profile
Caused by photosynthetic production from algae which congregate at this depth from density slowing sinking
Metalimnetic oxygen minima (4)
Variation of dissolved oxygen on typical seasonal profile
Sudden blip of oxygen decrease at the thermocline
Also known as a negative heterograde profile
Caused by decomposition of settling OM and small living organisms as it reaches the denser water of the thermocline where it accumulates and consumes oxygen
4 types of vertical oxygen profiles found in lakes and reservoirs
Orthograde
Clinograde
Positive heterograde
Negative heterograde
How is oxygen added to water? (3)
From aeration (splashing, waves)
Diffusion from the atmosphere
From photosynthesizing plants and algae
Photosynthetic vs decomposition reactions (2)
Photosynthetic reaction of phytoplankton creating oxygen in water
6CO2+12H2O—>C6H12O6+6H2O (+O2 )
Consumption of oxygen by decomposition is the same formula in reverse
C6H12O6+6H2O (+O2) —> 6CO2+12H2O
Why are eutrophic lakes subject to deoxygenation? (2)
Consumption of oxygen by decomposition (whether natural,sewage, or pulp discharge) is common due to algae blooms and increased decomposers so it can cause large diurnal changes in oxygen concentration
This leads to rises in oxygen throughout the day while algae produce oxygen then reductions throughout the night when algae die and are decomposed
Where is oxygen depletion most common in eutrophic lakes? (3)
In the hypolimnion because the epilimnion is replaced through the 3 pathways, but the hypolimnion is not
The thermocline acts as a barrier against oxygen diffusion into the hypolimnion from the epilimnion
Internal waves can cause significant mixing of oxygen across the thermocline
Where does oxygen demand occur? (3)
Usually occurs in the water column (WOD) and at the sediment water interface (SOD)
Oxygen demand is highest at the sediment water interface
This is because it is where the highest concentration of bacteria and carbonaceous material is location
Sediment layer of oligotrophic lakes (3)
In oligotrophic lakes there is a thin aerobic sediment layer at the water-sediment interface
As nutrient/organic loading increases, the sediment oxic layer decreases due to biological demands for oxygen
Some chemical reactions use oxygen to create other things like iron, which acts as a “lid” on the top of 10,000 years of sulphides etc. in the sediment
What are all the ways in which oxygen is lost? (4)
Respiration
Nitrification
Chemical reactions
Degassing and export
Why do you need to be very careful when artificially circulating lakes?
Because it can lead to fish kills as bacteria respond to increased oxygen availability leading to depletion
Measurement of oxygen demand (4)
Called BOD5 test - biochemical oxygen demand
It is a lab test for biochemical oxygen demand (BOD)
Measures the oxygen consumed by bacteria as they decompose organic matter
Change in DO concentration is measured over a given period of time in water samples at specific temperature
Standardized at 5 days and 20 degrees in the dark
What are the 2 stages of decomposition in the BOD test?
Carbonaceous stage
Nitrogenous stage
What is the carbonaceous stage of the BOD test?
First stage of decomposition that represents the portion of oxygen demand involved in the conversion of organic carbon to carbon dioxide
What is the nitrogenous stage of the BOD test? (2)
It is the second stage, representing a combined carbonaceous plus nitrogenous demand, when organic nitrogen, ammonia, and nitrite are oxidized to nitrate
Generally begins after about 6 days as there is a lag effect due to microbial adaptation
Equation of the BOD5 value
BOD=(IDO-FDO)/(VS/VB)
Where:
IDO = initial DO Oof diluted sample (mg/L) FDO = final DO of diluted sample (mg/L) VS = volume of sample (ml) VB = volume of bottle (ml) BOD = biochemical oxygen demand (mg/L)
Can also be shown by BOD5=(D1-D2)/P
Where:
D1 = initial DO D2 = final DO of the sample after 5 days P = decimal volumetric fraction of the sample used (sample volume/bottle volume) takes into account dilution - equal to 1 if none