Renal Physiology Flashcards
(95 cards)
Distributed wherever water is found. Marker for TBW?
Titrated water
A large molecule that cannot cross cell membranes. Marker for ECF?
Mannitol
A dye that binds to serum albumin. Marker for plasma ?
Evans Blue
What’s the Clearance of Na?
Plasma Na: 140 mEq /L
Urine Na: 700mEq /L
Urine flow rate: 1ml/min
5ml/min
Urine Flow Rate = Urine Conc x Urine vol / Plasma Conc
Urine flow rate = 700 x 1ml/min / 140
Urine flow rate = 5mL/ min
Insulin is infused in a patient. Whats the GFR?
Plasma conc = 1mg/mL
Urine vol= 60ml
Inulin concentration = 120mg/mL
120mL/min
GFR= urine conc x urine vol / plasma conc
GFR= 120 x 60 per hr / 1 = 7200 /60mins
GFR= 120mL/ min
50/M untreated DM.
What’s the clearance rate?
GFR= 120mL/min
Plasma glucose= 400mg/dL
Urine glucose= 2,500mg/dL
Urine flow rate= 4mL/min
25mL/ min
Clearance Rate = UV/ P
Clearance Rate = 2,500 x 4 / 400
Clearance Rate= 25 mL/min
50/M untreated DM.
What’s the Filtration Fraction?
GFR= 120mL/min
Plasma glucose= 400mg/dL
Urine glucose= 2,500mg/dL
Urine flow rate= 4mL/min
Since PAH values are not given for this example , FF cannot be computed .
However , in this context , if we have to guess in the exam, FF is above its normal average value of 20%.
RPF & FF increases in DM , which leads to eventual increase in GFR
Excretion of morphine can be increased by acidifying or alkalinizing the urine?
Acidifying urine, morphine is weak base.
When there’s No reabsorption of the substance. What is the TF/P value?
TF/P =1.0
TF: Tubular Filtration is urine at any point along the nephron.
P: Plasma is systemic plasma. It is considered to be constant
Reabsorption of the substance has been exactly proportional to the reabsorption of water. What’s the TF/P Value?
TF/P= 1.0
Reabsorption of the substance has been greater than the reabsorption of water. What’s the TF/P value?
TF/P = <1.0
Mas lesser ang reabsorption ng water
Reabsorption of the substance has been less than the reabsorption of water. What’s the TF/P value?
TF/P >1.0
Mas Greater ang reabsorption ng water.
Secretion of the substance. What’s the TF/P value?
TF/P >1.0
Wala ge reabsorb, ge secrete
What happens to the filtered load of Na+ if GFR spontaneously increases?
Filtered load of Na also increases.
Without a change in reabsorption, this increase in GFR would lead to increased Na excretion. However, glomerulotubular balance functions such that Na reabsorption also will increase, ensuring that a constant fraction is reabsorbed.
Effect of hyperaldosteronism on K+ levels and NH3 synthesis?
Causes Hypokalemia , hypokalemia stimulates NH3 synthesis which produces increase H+ excretion
What’s the free water clearance?
Urine flow rate : 10ml/ min
Urine osmolarity: 100 mOsm/ L
Plasma osmolarity: 300 mOsm /L
+6.7 mL/ min
CH2O = V - Osmolar
Free Water Clearance = 10 - (100x10/ 300)
Free Water Clearance = 10 - 3.33
Free Water Clearance= +6.7 mL/min
Vomiting effect on H+ and HCO3 ?
Metabolic alkalosis
H is lost from the stomach
HCO3 remains behind in the blood and the
HCO3 increases
Factors that Increases K+ secretion in the DCT. (6)
- Metabolic alkalosis
- High K+ diet
- Hyperaldosteronism
- Thiazide diuretic
- Loop diuretic
- Luminal anions
Boy 1 drinks 2L distilled water.
Boy 2 drinks 2L of isotonic NaCl. Both of them weighs 70kg.
Boy 2 will have ___________ urine osmolarity?
a. Increased
b. Decreased
Increased / Higher urine osmolarity
Boy 1: after drinking a distilled water, will have an increase in ICF and ECF volumes, a decrease in plasma osmolarity @ suppression of ADH secretion , and will produce dilute urine with a high flow rate.
Boy 2 : after drinking the same vol of isotonic NaCl, will have an increase in ECF volume only and no change in plasma osmolarity . Because Boy 2 ADH will not be suppressed , he will have a higher urine osmolarity and a lower urine flow rate.
45 / M with severe diarrhea. What’s the ABG interpretation?
ABG
pH = 7.25
PCO2 = 24 mmHg
HCO3= 10mEq/L
Decreased venous K+
Normal anion gap
Metabolic acidosis
45 / M with severe diarrhea. What’s the cause of decreased K?
ABG
pH = 7.25
PCO2 = 24 mmHg
HCO3= 10mEq/L
Decreased venous K+
Normal anion gap
A result of increased circulating levels of Aldosterone.
-loss of ECF volume due to diarrhea stimulates the release of aldosterone ; thus K secretion will increase in the distal tubule.
Arterial PCO2 level that inhibits reabsorption of filtered HCO3?
Inhibited by a DECREASED in arterial PCO2
-Decrease in arterial PCO2 cause a decrease in the reabsorption of filtered HCO3 by diminishing the supply of H+ in the cell for secretion into the lumen.
If X is freely filtered , is there net secretion or reabsorption of X?
Plasma inulin = 1 mg /mL
Plasma X= 2mg/ mL
Urine Inulin= 150mg/mL
Urine X= 100mg/mL
Urine flow rate= 1mL/min
There is net reabsorption of X
GFR= 150x1 / 1 = 150
Cx= 100 x1 / 2 = 50
Clearance of X is less than the clearance of Inulin (GFR) net reabsorption of X must have occurred.
Total daily excretion of H+ should equal to what ? to maintain balance.
Fixed acid production plus fixed acid ingestion.