Section 3: The Schrodinger Equation & QM Formalism Flashcards
(107 cards)
If two wavefunctions Ψ1 and Ψ2 are both solutions of a wave equation which is linear and homogeneous, the superposition principle ensures that
c1Ψ1+c2Ψ2 is also a solution of the same wave equation
this can be extended to as many waves as we want
a stationary state satisfies the condition
|Ψ (x,t)|^2 = |Ψ (x,0)|^2
derivation of the 1d time dependent schrodinger eqn
- plane wave in form of px-Et / h bar
- consider t=0
- find 1st and 2nd derivs
- compare using energy for free particle
since the one-dimensional time-dependent Schrödinger equation for a free particle is linear and homogeneous
a linear superposition of plane waves such as wavepakcets will still be a solution
We can generalise the Schrödinger equation to the case where a particle is not free, but it is subject to
a time-dependent potential U(x)
hence it is acted on by a force F=-dU/dx
Whilst we are considering a time-independent potential here, we can have an even more general form of the Schrödinger equation with
a time-dependent potential U(x,t)
the TDSE contains a first order time derivative which means that f the initial value of the wavefunction is given at t=t0, then
the value of the wavefunction at any later time t can be found by solving the TDSE
operator
mathematical entities that transform one wavefunction into another
the tern i h bar d/dt (LHS of TDSE) applied on the wavefunction is
the total energy operator
the total energy operator
a mathematical function, of time t, acting on the wavefunction that returns the total energy and we indicate with the symbol Ê
Hamiltonian operator
Ĥ yields the same result as the total energy operator but acts on spatial coords instead of time
Ĥ is the sum of
the potential and kinetic operators
(T hat and U hat)
momentum operator in 1D (p hat)
RHS of TDSE
-ih bar d/dx
Hamiltonian operator =
-h bar ^2/2m d2/dx2 + U(x,t)
if the potential U(x) is a continuous function of x, then
every function in the TDSE must be continuous
if U(x) shows any finite discontinuities with x then
d2Ψ (x)/dx2 should also have corresponding finite jumps
for this to happen, need dΨ/dx to be continuous with x
the continuity of dΨ/dx on the other end also implies that
Ψ(x,t) and dΨ/dt have to be continuous
if U(x,t) is a continuous function of t, so will
Ψ (x,t) and dΨ/dt
if U(x,t) has a finite jump with time
dΨ/dt will also have a corresponding finite jump, while Ψ (x,t) will still be a continuous function of t
how to generalise the 1D TDSE to 3d
using r instead of x
and ∇ instead of d/dx2
∇^2 =
d2/dx2 + d2/dy2 + d2/dz2
(the laplacian operator)
gradient of a function f
∇f = (df/dx, df/dy, df/dz)
how is the probability conserved?
consider what happens to probability over time
since no loss of information, expect this to be unchanged
wavefunction can be normalised at all times
how to mathematically write down that probability is conserved
d/dt integral over v
P(t,r)dr =0