Thermodynamics Flashcards

(54 cards)

1
Q

What is Thermodynamics based on?

A

Thermodynamic is based on initial and final states of a system undergoing the change. Laws of thermodynamics apply only when a system is in equilibrium or moves from one equilibrium state to another equilibrium state.

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2
Q

Define system and surroundings.

A

A system in thermodynamics refers to that part of universe in which observations are made and remaining universe constitutes the surroundings. Surroundings include everything other than the system.
Universe = System + Surroundings

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3
Q

What is boundary?

A

Wall that separates the system from surroundings.

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4
Q

Define types of system.

A

Open System: In an open system there is an exchange of energy and matter between the system and surroundings. The presence of reactants in an open beaker is an example of an open system. Here, the boundary is imaginary.

Closed System: In a closed system, there is no exchange of matter but exchange of energy is possible between the system and surrounding. The presence of reactants in a closed system made of conducting material (Cu/Fe) is an example of closed system.

Isolated System: In an isolated system there is no exchange of energy or matter between the system and the surroundings. The presence of reactants in a thermos flask or any other closed insulated vessel is an example of isolated system.

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5
Q

How is state of a system described?

A

The state of a system is explained by State functions or State variables. The state of a thermodynamic system is described by its measurable or microscopic (bulk) properties. They are called so because their values depend only on the state of the system and not on how it is reached.

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6
Q

What is Internal Energy?

A

The total energy of a system in thermodynamics is explained by internal energy; denoted by U,it may change when:
•heat passes into or out of the system
•work is done on or by the system
•matter enters or leaves the system

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7
Q

What is an Adiabatic system/process/wall?

A

Adiabatic system is an system where the transfer of energy between the system and surroundings is not possible or allowed.
Adiabatic process is a process in which there is no transfer of heat between the system and surroundings.
The wall separating the system and surroundings in such a case are known as adiabatic walls.

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8
Q

A: Work is a state function.
R: Work does depend on the path taken to do it.

A

Answer: (c) A is true but (R) is false.
As, work is a path function and not a state function.

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9
Q

A: Internal Energy is a state function.
R: Given amount of work done on the system no matter how it was done (irrespective of path taken), produces the same change of state.

A

Answer: (a) A is True and (R) is true and (R) is the correct reason.

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10
Q

Give expression for Work Done in adiabatic system and Internal Energy .

A

∆U = U2 - U1 = Wad

The positive sin expresses that W is positive when work is done on the system and the internal energy of the system increases. If the work is done by the system W will be negative because the internal energy of the system decreases.

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11
Q

Explain Heat in Thermodynamics.

A

Exchange of energy, which is a result of temperature difference is called heat (q).

Heat absorbed by the system (water), q can be measured in terms of temperature difference:
T2 - T1

Also, ∆ U = q when no work is done at constant volume.

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12
Q

Is temperature (T) a state function or a path function, what about volume (V)?

A

Both are state functions.

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13
Q

Explain the First Law of Thermodynamics (FLOT).

A

It states that:
The energy of an isolated system is constant.
Also commonly stated as law of conservation of energy; i.e. energy can neither be created nor be destroyed.

It’s independent of the way the change is varied out (path).

Expression:
∆ U = q + w
∆ U = 0 when, no transfer of energy or work done (isolated system).

We cannot determine the absolute value of a system’s internal energy, only the change in internal energy that occurs during a process because there is no absolute reference point to measure it against; we can only measure the difference in internal energy between two states.

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14
Q

Explain W.D. on an ideal gas inside a cylinder getting compressed.

A

Cylinder which contains one mole of an ideal gas fitted with a frictionless piston. The total volume of the gases Vi and pressure of the gas inside is P if external pressure is Pex which is greater P. Piston is moved inward till the pressure inside becomes equal to Pex.

Vol. Change: l(dis. moved by piston) × A = ∆ V = (Vf - Vi)
Force = Pex • A (P = F/A)

Work Done = f × dis = Pex • A • l
Work Done = -Pex(Vf - Vi) = -Pex(∆V)

The negative sign of this expression is required to obtain a conventional sign for work done which will be positive. It indicates that in case of compression work is done on the system.

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15
Q

Explain importance of negative sign in the formula for work done in relation to gas inside a cylinder.

A

Expression: Work Done = -Pex(Vf - Vi) = -Pex(∆V)

The negative sign of this expression is required to obtain a conventional sign for work done which will be positive. It indicates that in case of compression work is done on the system.

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16
Q

Explain reversible process wrt Thermodynamics.

A

A process or change said to be reversible for changes brought out in such a way, that the process could at any moment, be reversed by an infinitesimal change. Reversible process proceeds infinitively slowly by series of equilibrium states such that the system and the surroundings are always in near equilibrium with each other.

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17
Q

When can we form a relation between work and internal pressure? Explain the relation.

A

We can form a relation between work and internal pressure of the system under reversible conditions.

Wrev = -nRTln(Vf/Vo)
Wrev = -2.303 nRT log(Vf/Vi)

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18
Q

Explain Free expansion.

A

Expansion of a gas in vacuum is called free expansion. No work is done during the expansion of an ideal gas (since, Pex = 0) whether the process is reversible or irreversible.

At constant volume: ∆ U = q
Here, q = qv = heat supplied at constant volume.

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19
Q

Explain isothermal and free expansion of an ideal gas.

A

For isothermal expansion (T constant) of an ideal gas into vacuum, w = 0 since Pex = 0. Also, experimentally derived that q = 0.

Expression for isothermal reversible change:
q = -w = -Pex(Vf/Vi)

Expression for isothermal irreversible change:
q = -w = nRTln (Vf/Vi) = 2.303 nRT log(Vf/Vi)

For adiabatic change (q = 0):
∆U = Wad

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20
Q

Explain Enthalpy wrt Thermodynamics.

A

When heat is absorbed by the system at constant pressure we are measuring changes in Enthalpy (∆H).

Enthalpy (H) expression:
H = U +pV
∆H = ∆U + p∆V (p constant)

q = ∆H = H2 - H1
Here, q = q(p) = heat absorbed by the system.

Also, we know **heat is a path function but clearly, heat absorbed by system [q(p)] is a state function. **
Also, ∆H is a state function.

∆H is negative for exothermic reactions which evolve heat during the reaction and is positive for endothermic reactions which absorb heat for the surroundings.

At constant volume:-
For solids and liquid: ∆H = ∆U = qv
For gases: ** ∆H = ∆U + ∆n(g)RT
Here, n(g) means no of moles of gaseous products - of gaseous reactants.

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21
Q

Differentiate between extensive and intensive properties.

A

Extensive property is a property whose value depends on the quantity or size of matter present in the system, ex; mass, volume, internal energy, enthalpy, heat capacity, etc.

Properties which do not depend on the quantity or size of the matter present or known as intensive properties; ex: temperature, density, pressure, etc.

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22
Q

Explain Heat Capacity.

A

We know increasing temperature is proportional to heat transferred.
q ∝ k × T

The constant or coefficient ‘k’ here is Heat Capacity (C).
q = C ∆T
A large heat capacity means a lot of energy is needed to raise its temperature.

23
Q

Explain Molar Heat Capacity.

A

Molar heat capacity of a substance is the heat capacity for one mole of the substance and in the quantity of heat needed to raise the temperature of 1mol by 1degree Celsius or 1Kelvin.

Cm = (C/n)
Where, Cm = Molar Heat Capacity.

C can be derived from; q = C ∆T

24
Q

Explain Specific Heat Capacity.

A

Specific heat capacity is the quantity of heat required to raise the temperature of 1 unit mass of a substance by 1degree Celsius or 1Kelvin.

q = c × m × ∆T = C ∆T
Here, small c (c) is specific heat capacity.

25
Derive the relationship between heat capacity at constant pressure (Cp) and heat capacity at constant volume (Cv) for an ideal gas.
At constant volume: q(v) = C(v) ∆T = ∆U (I) At constant pressure: q(p) = C(p) ∆T = ∆H (II) For mole of an ideal gas: ∆H = ∆U + p∆V ∆H = ∆U + ∆(pV) ∆H = ∆U + ∆(RT) ∆H = ∆U + R∆T (III) From (I) and (II) into (III): Cp∆T = Cv∆T + R∆T Cp = Cv + R Therefore, relationship: **Cp - Cv = R**
26
What is the reaction enthalpy?
Reaction enthalpy is nothing but the enthalpy change accompanying a reaction. **∆H(r) = (Sum of enthalpies of products) - (Sum of enthalpies of reactants)**.
27
What is standard enthalpy (of reaction)?
The standard enthalpy of reaction is the enthalpy change for a reaction when all the participating substances are in their standard states. The standard state of a substance at a specified temperature is it's pure form at one bar. Standard conditions are denoted by adding the superscript^ '°' symbol (∆H°).
28
What does a calorimeter do?
A calorimeter measures the amount of heat absorbed or released during a chemical or physical reaction under two conditions: 1. Constant volume. (qv) 2. Constant pressure. (qp)
29
Explain working of a calorimeter through the measurement of **internal energy** and **heat**.
30
Explain standard enthalpy of formation.
The standard enthalpy change for the formation of one mole of a compound from its element in the most stable states of aggregation (also known as references) is called standard Molar enthalpy of formation. (∆fH°) The reference state of an element is its most stable state of aggregation at 25 degree Celsius and 1bar pressure.
31
Explain enthalpy change during phase transformations.
The enthalpy change that accompanies melting of one mole of a solid substance in the standard state is called **standard enthalpy of fusion** or **molar enthalpy of fusion**. Melting of a solid is endothermic so all enthalpy of fusion are positive. (∆fusH°) Amount of heat required to vaporize 1mole of a liquid at constant temperature and under standard pressure (1Bar) is called its **standard enthalpy of vaporization** or **molar enthalpy of vaporization**. (∆vapH°) **Standard enthalpy of sublimation** is the change of enthalpy when the mole of a solid substance sublimes at a constant temperature in under standard pressure (1 Bar). (∆subH°) The magnitude of the enthalpy change depends on the strength of the internal molecular interactions in the substance undergoing the phase transformations. For example: it requires less heat to vaporize 1 mole of acetone then it does to vaporize 1 mole of water.
32
Standard reaction enthalpy is a special case of standard enthalpy of formation. True or False?
False, it is actually the other way around. **Standard enthalpy of formation (∆fH°)** is just a special case of **Standard reaction enthalpy (∆rH°)** where obviously the compounds are formed from their reactants, but the elements must also be in their most stable forms.
33
By convention the standard enthalpy for formation (∆fH°) of an element in reference state or in the most stable state of aggregation is taken as what?
Zero
34
What is standard enthalpy of combustion?
Standard enthalpy of combustion is defined as the enthalpy change per mole of substance when it undergoes combustion and all the reactants and products being in the standard states at the specified temperature. (∆cH°) Ex: Cooking gas in cylinders contain mostly butane (C4H10) During complete combustion of one mole of butane, ≈2600 kJ of heat is released. C4H10 (g) + 13/2 O2 (g) **→** 4 CO2 (g) + 5 H2O (l); ∆cH° = -2658.0 kJ/mol
35
What are thermochemical equations?
Thermochemical equations are Balanced chemical equations together with the value of their enthalpy of reaction, which specify the physical state along side allotropic state of the substance in the equation.. The coefficients in a balanced thermochemical equation always refer to the number of moles and never the number of molecules of reactants and products involved in the reaction. The numerical value of enthalpy of reaction refers to the number of moles of substance specified by an equation.
36
What is enthalpy of atomisation?
Enthalpy of atomization is the enthalpy change on breaking 1mole of bonds completely to obtain atoms in the gaseous phase. (∆aH°) In case of diatomic molecules like dihydrogen enthalpy of atomization is also the bond is also the bond dissociation enthalpy. Ex: Dihydrogen H2 (g) **→** 2H (g) ; ∆aH° = 435.0 kJ/mol
37
What is Hess's Law of Constant Heat Summation?
Hess's law of constant heat summation states that **if a reaction takes place in several steps then its standard reaction enthalpy is the sum of the standard enthalpy of the intermediate reactions into which the overall reaction may be divided at the same temperature. This means that because enthalpy is a state function, **enthalpy change for a reaction is the same whether it occurs in one step for in a series of steps**. ∆rH = ∆rH1 + ∆rH2 + ∆rH3 + ...... + ∆rHn Can be represented as a polygon.
38
Define Bond enthalpy.
Relation of heat of reaction to changes in energy **associated with breaking and making of chemical bonds** is known as Bond Enthalpy. Types: 1.**Bond dissociation enthalpy**: HD change in enthalpy when one mole of covalent bonds of a gaseous covalent compound is broken to warm products in the gas phase more that it is the same as the enthalpy of atomization of dihydrogen. Therefore, **we use bond dissociation enthalpy in diatomic molecules**. Ex: Cl2 (g) **→** 2Cl2 (g); ∆cl-clH° = -242 kJ/mol 2.**Mean Bond Enthalpy**: It is the same as bond dissociation enthalpy but in case of polyatomic molecules, **bond dissociation enthalpy is different for different bonds in the same molecule**. Therefore, **it is used for polyatomic molecules**._₹ Ex: CH4 (g) **→** C(g) +4H(g); ∆aH = -1665 kJ/mol However, for bond enthalpy; CH4 (g) **→** CH3(g) +H(g); ∆bondH° = +427 kJ/mol CH3 (g) **→** CH2(g) +H(g); ∆bondH° = +439 kJ/mol • • Therefore; **∆c-hH° = 1/4(∆aH°) = (1/4) × 1665 kJ/mol = 416 kJ/mol** Remember the symbol used to denote both types of Bond enthalpy is the same; ∆bondH°
39
Ionization energy and electron affinity are defined at?
Absolute zero, at any other temperature heat capacities for the reactants and products are to be taken into account.
40
Define enthalpy of solution.
Enthalpy of solution of a substance is the enthalpy change when one mole of it dissolves in a specified amount of solvent. The enthalpy of solution at infinite dilution is the enthalpy change observed on dissolving the substance in an infinite amount of solvent when the interactions between the ions (or solute molecules) are negligible. (∆solH°) When an ionic compound dissolves in a solvent, the ions leave their ordered positions onto the crystal lattice. **For most of the ionic compounds enthalpy of solution is positive and the dissociation process is endothermic**. Therefore, the solubility of most salts in water increases with rise of temperature. If the lattice enthalpy is very high, the dissolution of the compound may not take place at all. **∆solH° = ∆latticeH° + ∆hybH°**
41
Define Enthalpy of dilution.
Enthalpy of dilution, also known as heat of dilution, is the change in enthalpy that happens when a solution is diluted. As more and more solvent is used the enthalpy of solution approaches a limiting value; the value in infinitely dilute solution.
42
Define Lattice Enthalpy.
The latice enthalpy of an ionic compound is the enthalpy change which occurs when one mole of an ionic compound dissociates its ions in gaseous state. Ex: Na+ Cl- (s) **→** Na+(g) **+** Cl- (g); ∆latticeH° = +788 kJ/mol It's impossible to determine lattice enthalpy directly therefore we use born-haeber cycle. See ex. of NaCl
43
What is Spontaneity?
Spontaneity **doesn't** actually mean the ability to perform a reaction very quickly. **It means having the potential to proceed without the assistance of external agencies**. **It does not tell about the rate of reaction or process**. **Spontaneous processes is an irreversible process, which may only be reversed by some external agency**.
44
The first law of thermodynamics puts restrictions on directions of heat flow. True or False?
False. All natural occuring processes whether chemical or physical will tend to proceed spontaneously in one direction only.
45
Is decrease in enthalpy a criteria for spontaneity?
No, it is true that while decrease in enthalpy may be a contributary factor for spontaneity but **it is not true for all cases**.
46
Define Entropy.
Entropy (S) maybe described as a measure of the degree of randomness or disorder in the system. The greater the disorder in an isolated system the higher is the entropy. As far is a chemical reaction concerned, these entropy changes can be attributed to rearrangement of atoms or ions from one pattern in the reactants to another. **If the structure of the products is very much disordered than that of the reactants, there will be resultant increase in entropy**. Decrease in regularity of structure would mean increase in entropy. **The crystalline solid state is the state of lowest entropy (most ordered). The gaseous state is the state of highest entropy.** **It's a state function. Independent of path.** Whenever heat is added to the system it increases molecular motions causing increases randomness in the system, therefore heat has randomising influence on the system. **A system in greater temperature has greater randomness than one at lower temperature**. Temperature is the measure of average chaotic motion of particles in the system. **Entropy change is inversely proportional to the temperature.** Entropy for reversible reaction: **∆S = qrev/T** Entropy for system and surroundings of spontaneous process: **∆Stotal = ∆Ssystem + ∆Ssurr > 0** When a system is in equilibrium the entropy is maximum and the change in entropy, ∆S = 0. We can say entropy for spontaneous process increases till it reaches maximum and at equilibrium the change in entropy is zero. Entropy for irreversible reaction: **∆Ssys = qsys,rev/T**
47
Internal energy does not discriminate between reversible and irreversible process whereas entropy does. True or False?
True.
48
What is Gibbs Energy?
The Gibbs Energy or Gibbs function was created to determine direction of spontaneous change for systems. (G) **It's a state function**. G = H - TS **∆Gsys = ∆Hsys - T∆Ssys - Ssys∆T** For constant temperature, (∆T = 0) ∆Gsys = ∆Hsys - T∆Ssys **∆G = ∆H - T∆S** Gibbs equation: **Gibbs energy change = enthalpy change - temperature × entropy change** **Unit: J** At spontaneous process: ∆G < 0 (-ve At non-spontaneous process: ∆G > 0 (+ve)
49
Why is Gibbs Energy sometimes also called Free Energy?
It represents the maximum amount of energy within a thermodynamic system that is available to perform useful work under constant temperature and pressure conditions; essentially, the "free" part refers to the usable energy that can be extracted from a system to do work, not that the energy is "free" in the sense of costing nothing.
50
Define Second Law of Thermodynamics.
The second law of thermodynamics states that **the total entropy of an isolated system always increases over time**, meaning that in any spontaneous process, the disorder of the universe will always increase, and a system naturally moves towards a state of maximum entropy; it can never decrease in an isolated system. It explains why spontaneous exothermic reactions are so common. In exothermic reactions, heat released by the reaction increases the disorder of this surroundings and overall entropy change is positive which makes the reactions spontaneous.
51
State Third Law of Thermodynamics.
**The entropy of any pure crystalline substance approaches zero as the temperature approaches absolute zero. This is called the third law of thermodynamics**. This is also because there is perfect order in a crystal at absolute zero. **This statement is confined to pure crystalline solids because theoretical arguments and practical evidences have shown that the entropy of solutions and super cooled liquids is not zero at 0K.**
52
We can predict spontaneity of a reaction by:
Gibbs/Free Energy Change (∆G)
53
How does reversibility in a reaction show that gives energy should almost be equal to zero or zero.
In reversible reactions, reactions in both the directions should proceed with the decrease in free energy, which seems impossible. It is only possible if at the equilibrium the free energy of the system is minimum, if it is not, the system would spontaneously change to configuration of lower free energy. Hence, ∆G ≈ 0 or ∆G = 0
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