Vectors Flashcards

1
Q

“Moved five meters”

Vector or Scalar?

A

Scalar

Only a
magnitude/size.

A scalar is a
magnitude/size
alone.

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2
Q

“Moved five meters to the right”

Vector or Scalar?

A

Vector

Both a
magnitude/size,
and a
direction.

A vector requires a
magnitude/size
and a
direction.

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3
Q

“Moved a distance of . . .”

Vector or Scalar?

A

Scalar,
probably.

Distance alone
tends to be a scalar quantity.

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4
Q

“Displaced by . . .”

Vector or Scalar?

A

Vector.

Displaced
is a vector term.

Often used like “Displaced five meters to the right.”

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5
Q

“Speed”

Vector or Scalar?

A

Scalar,
probably.

Speed tells you
distance/time, so without a
direction,
it’s a scalar quantity.

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6
Q

“Velocity”

Vector or Scalar?

A

Vector.

“Velocity” implies a
direction and a
speed,
so it’s a
vector quantity.

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7
Q

The number 5.

Can this represent a
vector?

A

No.

It could be a magnitude, but not a direction.

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8
Q

The angle measure 5°.

Can this represent a
vector?

A

No.

It could be a direction, but not a magnitude.

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9
Q

The point (5, 5).

Can this represent a
vector?

A

Yes.

If it’s relative to the origin,
then you have a
magnitude and a
direction.

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10
Q

A vector is written as
(a, b).

What
form
is that?

A

Component form

The vector is treated as a
point on the coordinate plane, or as a
directed line segment on that plane.

The components are the vector’s
x- and y-coordinates.

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11
Q

A vector is written as
aî + bĵ.

What
form
is that?

A

Unit vector form

With
vector addition and
scalar multiplication,
any two-dimensional vector can be represented as a
combination of the unit vectors.

Example:

(3, 4) = 3î + 4ĵ

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12
Q

A vector is written as

|| u ||, Θ.

What
form
is that?

A

Magnitude and direction form

Magnitude:
the
length of the line segment

Direction:
the
angle the line forms with the
positive x-axis

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13
Q

How do you know whether

  • *vectors** are
  • *equivalent**?
A

They have the

  • *same** magnitude and
  • *direction**.

Vectors are defined as a magnitude and a direction, so these two attributes must be the same if the vectors are the same.

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14
Q

If vectors have the

same magnitude and direction,

then they are_____.

A

Equivalent

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15
Q

If


AB = (−5, 4)

then

−5 is the _____
of the vector.

A

x-component

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16
Q

If


AB = (−__5, 4)

then

4 is the _____
of the vector.

A

y-component

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17
Q

If

A = (7, 2)
and
B = (17, −3),

then


AB = (__ , __)

A

(10, −5)


v = (Δx, Δy)

= (xf − xi, yf − yi)


AB = (17 − 7, −3 − 2)

= (10, −5)

18
Q

If

A = (7, 2)
and
B = (17, −3),

then


BA = (__ , __)

A

(−10, 5)


v = (Δx, Δy)

= (xf − xi, yf − yi)


BA = (7 − 17, 2 − (−3))

= (−10, 5)

19
Q

What does


|| u ||

mean?

A

The magnitude of

u

20
Q

If


AB = (−1, 4),

then


|| AB || = _____
.

A

√(17)


|| v || = √((Δx)2, (Δy)2)
(the Pythagorean theorem)

​ →
AB = (−1, 4)


|| AB || = √((Δx)2 + (Δy)2)

= √((−1)2 + (4)2)

= √(1 + 16)

= √(17)

21
Q

If


w = (2, −1),

then


2w = _____?

A

(−4, 2)

To
multiply a vector by a scalar,
you
multiply each component by the scalar.

Example:


w = (2, −1)


−2w = (−2 • 2, −2 • −1)

= (−4, 2)

22
Q

If


v = (x, y), || v || = 4,
and

w = (−2x, −2y),

then


|| w || = _____?

A

8

Magnitude is always
positive.

23
Q


a = (−5, 3) and b = (−1, −2),

so


a + b = _____?

A

(−6, 1)

To add vectors, you add
x-components to x-components and
y-components to y-components.

24
Q


a = (−5, 3) and b = (−1, −2),

so


a − b = _____?

A

(−4, 5)

To subtract vectors, you subtract
x-components from x-components and
y-components from y-components.

25
_a = (4, −1)_ and _b = (1, 2)_. **Visualize** **a + b = \_\_\_\_\_.**
*Visualize the start of* * b on the end of a.*
26
→ → _a = (4, −1)_ and _b = (1, 2)_. **Visualize** → → **a − b = \_\_\_\_\_.**
* a − b = a + (−1)b.* *Visualize the start of −b on the end of a.*
27
u = (−1, −7) and w = (3, 1) What are the **steps** to solving ** 2u + (−3)w**?
1. **Multiply the vectors by the scalars** 2. **Add respective *x*-components and respective *y*-components**
28
Graphically, when **adding or subtracting vectors**, why can you **visualize** them **head-to-tail**?
Because vectors are **equivalent** if their **magnitude and direction** are equivalent. The vectors can be **drawn** **anywhere**.
29
→ → _a + b_ is graphed below. **Visualize** the graph of → → **b + a**.
*Addition is commutative, so the order doesn't matter. You'll end up with the same vector.*
30
a = [6] and b = [−4] [−2] [4] so ** a + b = \_\_\_\_\_**?
**[2] [2]** ## Footnote a + b = [6 + −4] = [2] [−2 + 4] = [2]
31
``` # _define_: unit vector ```
**A vector with a magnitude of one**
32
What are the **unit vector components**?
**î and ĵ**
33
What are the **unit vectors** in their **component form**?
**î = (1, 0) = [1] [0]** **ĵ = (0, 1) = [0] [1]**
34
Given vector w, how do you **indicate** **unit vector w**?
**ŵ**
35
If ** w = (4, 3)** and **magnitude of 5**, then **ŵ = \_\_\_\_\_**?
**(4/5, 3/5)** *Scaling each component by the _same number_ (here, the _magnitude_) leaves the _same direction_.* → → û = ( a / || u || , b / || u || ) ŵ = (4/5, 3/5)
36
If w = [2] [3], then what is w in **unit vector form**?
** w = 2î + 3ĵ** ## Footnote î = [1] [0] ĵ = [0] [1] [2] = 2 • [1] + 3 • [0] [3] [0] [1] = 2î + 3ĵ
37
What _unit vector_ lies in the direction of **(−2, 1)**?
**(−2 / √(5), 1 / √(5))** * If u = (a, b), then → → û = (a / || u ||, b / || u ||).* _Example_: w = (−2, 1) || w || = √( (−2)2 + (1)2 ) = √( (4 + 1 ) = √(5) ŵ = (−2 / √(5), 1 / √(5))
38
How do you determine the **magnitude** of **(−√3, −1)**?
**|| (a, b) || = √(a2 + b2)​** * || (a, b) || = √(a2 + b2) *(Pythagorean theorem)* * || (−√3, −1) || = √((−√3)2 + (−1)2) * = √(3 + 1) * = 2
39
How do you determine the **direction** of **(−√3, −1)**?
**Θ = tan−1(b/a)​** * Θ = tan−1(b/a)​ * Θ = tan−1(−1 / −√3)​ * =(?) 30° * NOTE: (−√3, −1) lies in Quadrant III, so must add 180° to get angle in Quadrant III * = 30° + 180° * = 210°
40
How do you determine the **components** given a **magnitude of 2** and **angle of 210°**?
** ( || u || cosΘ , || u || sinΘ)** * → → ( || u || cosΘ , || u || sinΘ ) * = ( 2 cos(210°) , 2 sin(210°)​ ) * = ( 2 (−√(3)/2), 2 (−1/2)) * = (−√3, −1)