1.2Amount Of Substance Flashcards

1
Q

Define relative atomic mass

A

The average mass of a molecule/element, compared to 1/12th of a Carbon-12 atom

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2
Q

What is the Avogadro constant?

A

The number of atoms in a mole of a substance

6.022x10^23

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3
Q

What equation can be done to work out moles?

A

Mass = Mr Moles

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4
Q

How can you find out the moles of a substance (involving concentration)

A

Moles = concentration x volume

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5
Q

What is the ideal gas equation ?

A
PV=nRT
Pressure
Volume
Number of moles
Gas constant 
Temperature
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6
Q

What are the units that should be used in the ideal gas equation ?

A

Pressure (Pa)
Volume (m^3)
Temperature (K)

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7
Q

What is empirical formula?

A

The simplest whole number ratio of atoms in a compound

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8
Q

Describe how to find empirical formula.

A
  • Mass of each atom divided by Mr to find moles
  • Divide each atom’s moles by the atom with the smallest no of moles
  • calculate a ratio that gives whole numbers.
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9
Q

What is the equation of atom economy?

A

Molecular mass of desired product divided by sum of molecular mass of all reactants

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10
Q

What is the mole in terms of gasses?

A

1 mole of a gas occupies 24dm^3 at room temperature and pressure

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11
Q

How do you write full ionic equations ?

A

By splitting up all the aqueous species into their ions, and writing the equation like that, eg
NaOH + HCl -> NaCl + H2O
Na+ + OH- + H+ + Cl- -> Na+ + Cl- + H2O

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12
Q

How do you write simplified ionic equations ?

A

You do the same for full ionic equations, but remove any of the ions that are on both sides. Eg.
Na+ + OH- + H+ + Cl- -> Na+ + Cl- + H2O
OH- + H+ -> H2O

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13
Q

How do you calculate the limiting reagent of an equation?

A

Calculate the moles of both reagent, and the reagent with the smallest moles (considering the ratio) is the limiting reagent.

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14
Q

How do you calculate the percentage yield?

A

Mass of product obtained divided by the maximum theoretical mass of product

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15
Q

What is a back titration?

A

A back titration is done to analyse a base/acid that does not react easily or quickly with an acid/base. The base is treated with an excess of acid, and the the left over acid is titrated. You can then work back to find out the original base.

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