Exam 4 Flashcards

(113 cards)

1
Q

DNA was first (1869) isolated by Swiss chemist

A

Friedrich Meischer; called it “nuclein”.

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2
Q

(1929) Phoebus Levene discovered

A

deoxyribose as sugar component of DNA.
Discovered four nitrogenous bases of DNA: thymine, adenine, guanine, and cytosine.
Tetranucleotide hypothesis: DNA consisted of short chains of 4 repeating nucleotide units.

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3
Q

(1928-1943) Several investigators reported experimental results suggesting that DNA carried

A

heritable information

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4
Q

Nucleic acids are polymers of

A

nucleotides

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5
Q

nucleotides are consisted of

A

pentose sugar
- ribose in RNA
- deoxyribose in DNA

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6
Q

nitrogenous base consists of

A

purines and pyrimidines.
Purines: G, A
Pyrimidines: C, T (DNA), U (RNA)

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7
Q

Phosphate group consists of

A

Nucleoside: nitrogenous base + sugar.
Nucleotide: nucleoside + ≥ 1 phosphate.

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8
Q

Chargaff and Base Composition of DNA

A

analyzed base composition of DNA from several different species
base comparison varies between species
- suggests molecular diversity
regularity in the ratio of nucleotide bases

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9
Q

Chargaff’s Rules

A

Rule 1: Base composition of DNA varies btw species.
Rule 2: %A ≈ %T; %G ≈ %C.
- Use to calculate unknown %s.
Exception: фX174 = bacteriophage
- Has single stranded, circular genome.

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10
Q

Rosalind Franklin (7/25/1920 – 4/16/1958)

A

British biophysicist working in X-ray crystallography.
- ↑ understanding molecular structure of DNA, RNA, viruses.
Data was critical to Watson-Crick DNA model.
- Shown to Watson w/o her knowledge.
- Prepared papers recognizing two forms A and B-DNA

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11
Q

Franklin’s X-ray Crystallography Data

A

X-rays are deflected as pass through DNA fibers.
Watson and Crick assembled models conforming to Franklin’s data and Chargaff’s rules.

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12
Q

Watson-Crick Model of Double Helix

A

Duplex DNA: structure consists of two strands.
Two strands are anti-parallel:

Followed Franklin’s conclusion: sugar-phosphate backbone was outside.
- Places hydrophobic bases interior.
Helix makes a full turn every 3.4 nm and bases are stacked 0.34 nm apart.

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13
Q

Nucleic Acids are Directional

A

Phosphodiester bonds result in a polymer w/ distinct ends.
5’ end: ends in terminal phosphate.
3’ end: ends in pentose sugar with free 3’ hydroxyl group.

Covalently linked sugars and phosphates make up phosphodiester backbone.

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14
Q

________ - ________ only pairing that fits.

A

Purine-pyrimidine
Strands stabilized by hydrogen bonds.
Explains Chargaff’s Rules
Dictates combos btw strands
No sequence restrictions along strand

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15
Q

Watson-Crick base pairing is key to information sharing in

A

DNA replication
Transcription (DNA > RNA)
Translation (mRNA > polypeptide [protein])

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16
Q

Leading strand

A

synthesized continuously in direction of replication fork.

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17
Q

Lagging strand

A

synthesized discontinuously in direction away from replication fork

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18
Q

Helicase

A

uses ATP hydrolysis to unwind DNA duplex

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19
Q

Primase

A

Synthesizes a short RNA primer.

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20
Q

DNA polymerase

A

DNA-dependent synthesis of comple-mentary DNA molecule.

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21
Q

DNA ligase

A

joins adjacent replicated strands.

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22
Q

Enzymes that catalyze synthesis of new DNA by adding _________ to a preexisting chain.

A

nucleotides
Require primer and a template strand.

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23
Q

E. coli

A

several DNA polymerases; two most important for DNA replication
DNA Pol I: removes RNA primer and replaces w/ DNA.
- DNA Pol III: adds DNA nucleotide to RNA primer and continues to add Nts complementary to template strand.

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24
Q

Rate of elongation

A

≈ 500 Nt/sec in bacteria and ≈ 50 Nt/sec in human cells.

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25
DNA polymerase
catalyzes addition of a nucleotide to the 3’ end of a growing chain
26
Each nucleotide added is in the form of dNTP
dNTP - each monomer is added, pyrophosphate is lost. - Hydrolysis of pyrophosphate is a coupled exergonic rxn.
27
Structural differences RNA vs. DNA
Sugar = ribose (2’ OH) Uracil (U) instead of thymine (T). Usually single stranded
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Messenger RNA
mRNA: carries information from DNA to ribosome
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Transfer RNA
tRNA: delivers specific amino acids to ribosome
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Ribosomal RNA
rRNA: structural and catalytic part of ribosome.
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Regulatory RNA
regulate gene expression; include microRNA (miRNA), long, non-coding RNA (lncRNA), small interfering RNA (siRNA).
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intramolecular base pairings of purines and pyrimidines A=U G=C creates intramolecular regions with different structures;
stem: complementary base pairing by antiparallel turns of RNA strand. loop: unpaired region
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(Francois Jacob and Jacques Monod, 1961) hypothesized that single-stranded RNA
messenger RNA carries info from DNA to ribosomes.
34
Gene Expression in Bacteria
Most genes are continuous. Some genes are organized into operons. - Produce a polycistronic mRNA. Lack of compartment-alization allows coupling of transcription and translation
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Template strand
used to direct transcription; complementary and antiparallel to RNA. - Also called antisense strand.
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Non-template strand
NOT usually transcribed; same sequence and polarity as RNA - contains U instead of T. - also called sense = coding strand.
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Promoter
DNA sequence immediately upstream (5’) of transcription start site (tss); - Not transcribed; controls binding of RNA polymerase
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RNA coding region:
portion of gene transcribed into mRNA
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Termination region
sequences located 3’ to coding region; signals end of transcription
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A single promoter controls the expression of 3 genes
lacZ, lacY, and lacA Products of lacZ and lacY genes involved in lactose metabolism
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3 clustered genes are coordinately expressed in single mRNA
polycistronic mRNA
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uncoupled
Nuclear envelope separates trans-cription and translation - transcription = nuclear. - mRNA is transported to cytoplasm for translation.
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RNA splicing
introns are removed from pre-mRNA
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5’ cap
addition of a modified guanine to 5’ end of mRNA. - added after ≈ 20-40 Nts are transcribed.
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poly-A tail
addition of 50-250 adenine residues of 3’ end of pre-mRNA. Functions: - Prevent degradation - Help mRNA transport - Help position mRNA on ribosome
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Primary transcript is processed to mature mRNA.
introns: regions of gene that are transcribed, but not included in mature RNA. exons: regions of transcribed RNA retained in mature RNA. Exons included translated and untranslated regions.
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RNA Splicing
Pre-mRNA strand includes exons and introns. RNA splicing: removal of introns and joining of exons to produce mature mRNA
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Most contain RNA coding regions and noncoding regions
- Exons: RNA coding regions. - Introns: non-RNA coding regions. EX: Ovalbumin gene ≈ 7,700 bp 8 exons, 7 introns; Mature mRNA 1,872 bases
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Transfer RNA = tRNA
delivers specific amino acids to ribosome. - Specific interactions w/ codon of mRNA.
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Ribosomes
complex of proteins and rRNA that serve as platforms for translation. - Orient mRNA. - Position tRNAs - Catalyze addition of amino acid to growing polypeptide chain.
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Character
: a heritable feature that varies among individual. - EX: flower color.
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Trait
each variant for a character; - EX: purple vs white flowers
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Gregor Mendel (1822-1884)
Austrian monk who worked out principles of transmission genetics (simple inheritance). Proposed the first theory about the units of inheritance (genes). - Law of segregation - Law of independent assortment
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Hypothesis of Blended Inheritance
hereditary determinants carried by gametes blend as gametes fuse in fertilization - Blended determinants would produce intermediate traits. - Parental trait should not reappear if blended
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Hypothesis of Particulate Inheritance
determinants of inheritance are physically distinct. - Remain intact when gametes fuse
56
True breeding
gives rise to plants w/same traits over successive generations
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Cross-pollination
directed mating technique to ensure parentage of each generation of peas. - reciprocal cross: switch parents contributing trait.
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The Parental generation is the
P generation
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the first filial generation is the
F1 Generation
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Alternative versions of genes account for variations in inherited characters are called;
alleles an organism inherits two alleles, one from each parent
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If two alleles at a locus differ, then the ___________ _______ determines the organism’s appearance.
dominant allele
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Law of segregation
the two alleles for a heritable character segregate during gamete formation and end up in different gametes.
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Monohybrid cross
cross between individuals who are heterozygous for a character.
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P generation
true-breeding = identical alleles. Gametes produced by one parent will contain same allele.
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F1 generation
union of parental gametes produces F1 hybrids (Pp) When hybrids produce gametes, the two alleles segregate.
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F2 generation
Random combination of gametes in F1 x F1 cross result in 3:1 ratio observed by Mendel.
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Genotype (two types)
combination of alleles ≥ 1 gene of an organism. homozygous: pair of identical alleles heterozygous: 2 different alleles
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Phenotype (two types of traits)
one or more of an organism’s observable traits. Dominant trait: expressed in F1 organism Recessive trait: masked in F1 but reappears F2 generation.
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complete dominance
when true-breeding parents carry different traits then, F1 genotypic proportions: all Rr F1 phenotypic proportions: all express dominant phenotype. - F2 genotypic proportions: ¼ RR, 2/4 R/r, ¼ rr. - F2 phenotypic proportions: ¾ dominant, ¼ recessive.
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transmission of genetic traits is determined by the _______ on homologous chromosomes
alleles
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Alleles of a gene reside at the same position =
locus on homologous chromosomes
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Dependent assortment
: two characters assort as a package during gamete formation. Parental combinations of alleles stay together.
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Independent assortment
two characters assort independently during gamete formation. - Nonparental combinations of alleles can occur.
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Dihybrid cross
obtain characteristic 9/16, 3/16/, 3/16, 1/16 phenotypic proportions
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Multiplication rule
probability of ≥ 2 independent events occurring together is product of their individual probabilities. - P(2H,2 tosses) = (1/2)(1/2) = 1/4 (Practice Slide 27 G&H)
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Addition rule
probability of any one of ≥ 2 mutually exclusive events is sum of their individual probabilities. - P(F2 = heterozygous) = ¼ +1/4) = ½ - Two ways to achieve outcome. (Practice Slide 27 G&H)
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lack of compartment allows
coupling of transcription and translation
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F1 phenotype is __________ phenotype of parents.
intermediate
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Heterozygote
phenotypes of both alleles are measurable
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ABO blood typing
3 alleles Exhibit both complete dominance and codominance. IA vs. IB = codominant IA, IB vs. i = complete dominance Use to determine transfusion compatibility.
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Autosomal
located on chromosomes 1-22.
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Sex chromosome
: located on X or Y.
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In pictorial representation of family history a horizontal line represents:
mating
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In pictorial representation of family history a vertical line represents:
connects parents to children
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In pictorial representation of family history a shading line represents:
indicates whether a person is affected with the trait
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penetrance
proportion of individuals w/ a genotype that express corresponding phenotype; - trait due to acquisition of new mutation.
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Incidence of some autosomal dominant disorders is high: Familial hypercholesterolemia Myotonic dystrophy Huntington’s Disease
: ≈ 1/500 in families of European or Japanese descent. ≈ 1/550 in regions of northeastern Quebec vs. 1/8000 worldwide : ≈ 5.7/1x105 if European, N. American, or Australian descent; ≈ 4/1 x 106 if Asian descent.
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Carrier
individual w/ heterozygous genotype, who is unaffected, but can pass on disease causing allele.
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Co-sanguinity
: mating btw closely related people. - Increases probability mating between two heterozygotes. - ≈ 1/4 offspring will be affected
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Genotypes for XX Genotypes for XY
inherit two alleles; homozygous dominant, heterozygous, homozygous recessive. only one allele for each gene = hemizygous Not the same as gender: sex characteristics that are socially constructed.
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Congenital Generalized Hypertrichosis (CGH)
X-linked dominant disorder. Increased number of hair follicles and body hair. - ♂: full body expression; - ♀: asymmetrical; may be present in patches.
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Regarding a mutation in a gene on the X chromosome causes the phenotype to be expressed in MALES:
hemizygous for the mutation b/c only contain one X chromosome
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Regarding a mutation in a gene on the X chromosome causes the phenotype to be expressed in FEMALES:
homozygous for the mutation (copy on each of their 2 X chromosomes).
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DNA > RNA (mRNA) >
protein
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a site
aminoacyl- holds an tRNA carrying the next amino acid to be added s
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p site
peptidyl- hold tRNA with the growing polypeptide attached
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e site
site from which discharged tRNA will exit
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triplet code
smallest units possible to code for 20 biological amino acids (4)(4)(4) = 64 possible combinations
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information flow from DNA to protein is written in a non-overlapping genetic code DNA: mRNA: Protein:
DNA: instructions for protein written as series non-overlapping nucleotides mRNA: series of non-overlapping 3 nucleotide "words" = codons Protein: each codon interacts with tRNA to specify amino acids
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lack of ambiguity
no codon specifies > 1 amino acid
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redundancy
some codons are synonyms; specify the same amino acid
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reading frame
translational machinery reads as series of non=overlapping 3 letter words = codon
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nearly universal
conserved from bacteria to plants and humans - allows genes to be transplanted from one species to another >>>gene transcribed and translated in cells of second species
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implication
near universality indicates "language" present early in life - shared by common ancestor
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melanocortin
hormone influencing deposit of dark pigment in fur mice with dark fur GCG > CGC > Arg mice with light fur ACG > UGC > Cys
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nucleic acid is
DNA or RNA
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covered in a protein coat
capsid
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covered in a coat of membrane
envelope
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lytic cycle
after making many copies of phage, cell breaks open to release particles - phage injects DNA, which circularizes - phage DNA and proteins are synthesized - phage particles assemble - cell lyses to release phages
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isogenic cycle
viral DNA inserts into bacterial chromosome and DNA replication occurs without death of bacterium
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papaya ringspot potyvirus
spread of aphids wiped out native papaya in certain parts of Hawaii reintroduction of genetically engineered PRSV-resistant papaya plants allowed reintroduction
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3 types of COVID tests approved by FDA
rapid antigen tests: nasal swab, immunoassay, antibodies are the detection method molecular tests: antibody (serology) test: blood sample to detect circulating antibodies, detect with color change
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