History of Genetics Flashcards

1
Q

1865: Mendel

A

Gregor Mendel

–> Two laws of inheritance are identified through Mendel’s pea plant experiments

–> Identified “heritable factor” transmitted between generations

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

1910: Morgan

A

Thomas Hunt (T.H.) Morgan

–> Published study showing chromosomes were the carriers of Mendel’s “heritable factors” (genes)

–> It was uncertain whether these heritable factors on the chromosomes were DNA or protein

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

The case for protein as the heritable factor:

A

1) Proteins were more studied:

Seemed to have more diversity in the amino acids that was thought to allow for more combination = more complexity = more likely to be our genetic makeup

2) Nucleic acids seemed too uniform to account for the multitude of specific inherited traits

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

1928: Griffith

A

Frederick Griffith’s Streptococcus Pneumoniae Experiment

–> Founder of the “transformation principle”

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Streptococcus Pneumoniae Experiment:

What is the difference between the strains?

A

Streptococcus Pneumoniae: Has 2 strains

1) R-Strain (Rough) = NON-pathogenic
–> Appearance: Smaller, no capsule

2) S-Strain (Smooth) = PATHOGENIC
–> Appearance: Bigger, HAS capsule

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

S-Strain Capsule Function

A

A polysaccharide coating that masks the bacteria from the immune system (hides it)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Genetic difference between R and S strains:

A

S-Strain = HAS the variant of the gene that encodes for capsule production

R-Strain = DOES NOT HAVE the variant of the gene that encodes for capsule production

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Streptococcus Pneumoniae Experiment:

METHODS

A

1) Injected mice with different types of streptococcus pneumoniae strains

2) Analyzed whether mice died or not

3) Blood sampling to look at the bacteria strains

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Streptococcus Pneumoniae Experiment:

What were the experiment groups?

A

1) Pathogenic CTRL = Treated cells with LIVING S-Strain

2) NON-Pathogenic CTRL = Treated with LIVING R-Strain

3) Non-Pathogenic “Ctrl.” = Treated with HEAT KILLED S-STRAIN (Dead S-Strain)

4) Test (Combo) Grp. = Treated with MIX:
–> LIVING R-STRAIN
–> HEAT-KILLED S-STRAIN

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Streptococcus Pneumoniae Experiment:

What was the result of the mice treated with LIVING S-STRAIN?

A

Mice DIED –> Pathogenic strain killed the mice

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Streptococcus Pneumoniae Experiment:

What was the result of the mice treated with LIVING R-STRAIN?

A

Mice LIVE –> Non-Pathogenic strain did NOT kill mice

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Streptococcus Pneumoniae Experiment:

What was the result of the mice treated with HEAT-KILLED S-STRAIN?

A

Mice LIVE –> Pathogenic strain was DEAD and so it had no pathogenic effect on the mice (didn’t kill the mice)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Streptococcus Pneumoniae Experiment:

What was the result of the mice treated with the COMBO?

–> MIX = Living R-Strain, Heat-Killed S-Strain

A

Mice DIE

–> Why? Took blood sample to look at the bacteria

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Streptococcus Pneumoniae Experiment:

Combo treated mice blood sample results

A

LIVING S-STRAIN FOUND

(Strange because the mice had been treated with only DEAD S-strain and living R-strain)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Streptococcus Pneumoniae Experiment:

OVERALL RESULT

A

The R-Strain cells acquired the pathogenicity trait, turning them into S-Strain cells

–> Some chemical component of the pathogenic cells caused this heritable change

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Streptococcus Pneumoniae Experiment:

Conclusion and Discovery

A

Conclusion: R-Strain bacteria had been “transformed” into S-Strain by some heritable factor

Discovery:

Transformation Principle

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

Streptococcus Pneumoniae Experiment:

What question remained at the end of the experiment?

A

–> What was the heritable factor that served as the transforming component?

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

Transformation (Definition as we know it today)

A

A change in genotype and phenotype due to the assimilation of external DNA by a cell

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

1944: Avery, MacLeod, McCarty

A

Oswald Avery, Colin MacLeod, Maclyn McCarty

–> Identified the “transforming substance” from Griffith’s experiment

–> First evidence of DNA as heritable factor (though most were skeptical of this study and did not accept the results as being accurate = DNA debate continued on until 1952)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

Avery, MacLeod, McCarty Experiment:

METHODS

A

1) Treated different groups of Heat-Killed S-Strain bacteria with different substances that would break down molecules such as proteins, DNA, RNA, lipids, and sugars

2) Mixed these altered heat-killed S-Strain bacteria with LIVING R-Strain

3) Injected these mixtures into mice

4) Analyzed mice survival

21
Q

Avery, MacLeod, McCarty Experiment:

What were the experiment groups?

A

1) CONTROL –> NON-TREATED Heat-Killed S-Strain (+ Living R-strain)

TEST GRPS:

2) Heat-Killed S-Strain with LIPIDS AND SUGARS DESTROYED (+ Living R-Strain)

3) Heat Killed S-Strain TREATED with PROTEASES (destroyed proteins) (+ living R-strain)

4) Heat Killed S-Strain TREATED with DNAses (destroyed DNA) (+ living R-strain)

5) Heat Killed S-Strain TREATED with RNAses (destroyed DNA) (+living R-Strain)

22
Q

Avery, MacLeod, McCarty Experiment:

What was the result of the Control (non-treated) group?

A

Mice DIE

–> Transformation of R-Strain occurs and they gain the pathogenic ability

23
Q

Avery, MacLeod, McCarty Experiment:

What was the result of the group with lipids and sugars destroyed?

A

Mice DIE

–> Transformation of R-Strain still occurs, and they gain the pathogenic ability

–> Destruction of sugars and lipids didn’t stop the transformation, THEREFORE, they are not the heritable factors

24
Q

Avery, MacLeod, McCarty Experiment:

What was the result of the group treated with proteases?

A

Mice DIE

–>Transformation of R-Strain still occurs, and they gain the pathogenic ability

–> Destruction of proteins didn’t stop the transformation, THEREFORE, they are NOT the heritable factors

25
Q

Avery, MacLeod, McCarty Experiment:

What was the result of the group treated with RNAses?

A

Mice DIE

–> Transformation of R-Strain still occurs and they gain the pathogenic ability

–> Destruction of RNA didn’t stop the transformation, THEREFORE, they are NOT the heritable factors

26
Q

Avery, MacLeod, McCarty Experiment:

What was the result of the group treated with DNAses?

A

Mice LIVE

–>Transformation of R-strain DIDNT HAPPEN

–> Destruction of DNA stopped the transformation, THEREFORE DNA IS THE HERITABLE FACTOR OF TRANSFORMATION

27
Q

Avery, MacLeod, McCarty Experiment:

OVERALL RESULT

A

Transformation of R-strain into S-strain was lost when DNA was destroyed by nucleases

28
Q

Avery, MacLeod, McCarty Experiment:

Conclusion + Discovery

A

Conclusion = DNA of the S-strain bacteria is responsible for heritable changes during bacterial transformation

Discovery = DNA IS THE HERITABLE MATERIAL

29
Q

Avery, MacLeod, McCarty Experiment:

Why did scientists not accept the conclusion/discovery of this experiment?

A

Scientists were skeptical

–> Concerned that some contaminating substance present in small amounts (that wasn’t DNA) was the actual transforming substance

= Debate continued until 1952

30
Q

1952: Hershey

A

Alfred Hershey and Martha Chase Experiment

–> Studied bacteriophage replication, specifically which component actually entered the cell (insertion) and what was left outside of cell (shell)

31
Q

Alfred Hershey and Martha Chase Experiment:

What bacteriophage was studied?

A

T2 Phage

–> A bacteriophage that infects E.coli

32
Q

Virus

A

A little more than DNA (or RNA) enclosed by a protective, usually protein, coat

–> Take over cell machinery to produce more of the virus

33
Q

Bacteriophage

A

A virus that infects bacteria

34
Q

Alfred Hershey and Martha Chase Experiment:

Main question of the study

A

Which component (protein or DNA) was responsible for the ability to reprogram the host cell (into producing more virus)?

–> At this point in time, scientists knew viruses were made of protein and DNA but not which part was responsible for the reprogramming (AKA the heritable factor)

35
Q

Alfred Hershey and Martha Chase Experiment:

METHODS

A

1) 2 batches of T2 were grown: one with a protein label and one with a DNA label

2) Each batch was mixed with E.coli –> Allowing infection

3) The phage-E.coli complexes were put into blender to separate shell from E.coli

4) Blended contents were centrifuged

5) Supernatant and pellet were tested for the radioactive labels (protein and DNA labels)

36
Q

Alfred Hershey and Martha Chase Experiment:

What were the radiolabels utilized?

A

1) 35-S (radioactive sulfur) –> Protein Label
–> sulfur is a main building block of many proteins
2) 32-P (radioactive phosphorous) –> DNA label
–> phosphorous is part of the DNA phosphate group

37
Q

Alfred Hershey and Martha Chase Experiment:

RESULTS

A

35-S was found in the SUPERNATANT (NOT in the E.coli cells)
–> Viral protein didn’t enter the cell

32-P was found in the PELLET (in the E.coli cells)
–> Viral DNA entered the cell

EXTRA RESULT:
–> After allowing phage replication to occur, the new phages had 32-P in them

38
Q

Alfred Hershey and Martha Chase Experiment:

Conclusion + Discovery

A

Conclusion =

DNA injected by the phage into the host cell must be the molecule carrying the genetic information that makes cells produce new phages

Discovery =

DNA is the material of heredity!

39
Q

1950: Chargoff

A

Erwin Chargoff

–> Nucleotide base compositional analysis study

–> Developed Chargaff’s Principle (evidence of base pairing)

40
Q

Erwin Chargoff’s Study:

METHODS

A

1) DNA samples collected from different species

2) Separated DNA components by paper chromatography

3) Converted the separated components into mercury salts

4) Identified purines and pyrimidines by their UV light absorption spectra

41
Q

Erwin Chargoff’s Study:

Results

A

1) Base composition of DNA varied from one species to another

2) In each species, the #A~#T and the #C~#G

42
Q

Chargaff’s Rules

A

I. DNA base composition varies between species

II. For each species, the percentages of A is proportional to the percentages of T, and the same for C and G

43
Q

Implications of Erwin Chargoff’s Study

A

1) Evidence of molecular diversity among species

2) Implied base pairing (A-T, G-C)

44
Q

1953: 2 sets of scientists

–> Franklin + Wilkins
–> Watson + Crick

A

The data, experimentation, and studies conducted by these scientists led to the development of the double helix model of DNA

45
Q

Franklin + Wilkins Work

A

Conducted X-Ray Crystallography on DNA

–> Produced an image showing the double helix shape of DNA with uniform diameter and geometries

46
Q

X-Ray Crystallography

A

Franklin and Wilkins suspended a tiny fiber of DNA and then bombarded it with X-Rays for 100 hours of exposure

–> The X-Rays defract due to the electrons in the atoms of the fiber which then produces a pattern on a photographic plate

47
Q

Watson + Crick Work

A

Built a model of DNA (double helix model) from Franklin’s diffraction findings, Chargaff’s rules, and other DNA research

48
Q

1962: Watson + Crick

A

Win the nobel prize