Lecture 20: Developmental Genetics Flashcards

(58 cards)

1
Q

How are all living forms related?

A
  • evolution has conserved basic strategies of development across multicellular eukaryotes
  • many homologous proteins have highly conserved functions
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2
Q

give examples of homologous genes in different organisms

A
  • eyeless (Drosophila), Pax-6 (mouse), and Aniridia (humans) genes are homologous
  • Pax-6 and Aniridia wild-type genes can direct eye development in Drosophila
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3
Q

distinguish between forward and reverse genetics

A

Forward:
Phenotype → Find gene
- Mutagenize, screen for trait, map gene
- Use when you know the trait but not the gene

Reverse:
Gene → Find phenotype
- Knockout/mutate gene, observe effect
- Use when you know the gene but not its function

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4
Q

what is an example of mutagenesis screens in organisms?

A
  • motor axon guidance mechanisms in Drosophila.
  • scientists mutagenise C. elegans, observe the phenotype, then try and identify the gene responsible for each phenotype
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5
Q

what is a modifier mutagenesis screen?

A

type of genetic screen used to find genes that influence the severity or expression of a known phenotype, rather than causing the phenotype on their own.

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6
Q

define redundancy

A

two or more genes perform overlapping or similar functions, so that loss of one gene has little or no effect on phenotype

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7
Q

why is it not possible to just mutagenise the wild-type organism in a modifier mutagenesis screen?

A

if you just mutagenise the wild type, you may have a whole bunch of different mutations, but if there’s redundancy you won’t see the phenotype you are studying

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8
Q

what is the function of the sev gene in Drosophila?

A

sev is a receptor tyrosine kinase that activates Ras signaling to specify the R7 photoreceptor.

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9
Q

what is the function of the Ras gene in Drosophila?

A

When sev is activated by its ligand, it triggers a cascade that activates Ras, which in turn promotes cell differentiation (the specification of the R7 photoreceptor neuron).

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10
Q

what is Ras^G12V?

A

gain of function mutation - this mimics constant “on” signaling, so R7 cells develop even without the proper upstream signal, or develop abnormally, causing things like a rough eye phenotype.

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11
Q

What does the “modifier mutagenesis screen” using sev::Ras^G12V in Drosophila eyes reveal about genetic interactions?

A
  • Wild type: Normal eye structure.
  • sev::Ras^G12V: Rough eye due to hyperactive Ras signaling.
  • Enhanced phenotype (E⁻/E⁺; sev::Ras^G12V): worsened mutant phenotype → E is a negative regulator of Ras.
  • Suppressed phenotype (S⁻/S⁺; sev::Ras^G12V): More normal eye → S is a positive regulator of Ras.
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12
Q

Use of Genome wide screens

A
  • we can design RNAs that can target specific genes and inactivate them, similar to a knockout
  • this produces a phenocopy of a loss of function mutation
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13
Q

define a phenocopy

A

a phenotype that mimics the effects of a gene knockout, caused by methods like RNAi or CRISPR.

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14
Q

4 ways in which we can analyse developmental pathways

A

Nature of the encoded protein:
- we can infer amino acid sequence from nucleotide sequence and use computer searches to identify known motifs

Location and timing of gene expression:
- during development, where and when is the mRNA found?

Location of the protein product:
- during development, where and when is the protein found?

Developmental phenotypes:
- what cells or tissues are affected by loss-of-function?

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15
Q

two methods to follow the localisation of proteins

A
  • attach antibodies to the protein
  • tag the proteins with GFP
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16
Q

why must the interactions of genes in a developmental pathway be determined?

A

genes don’t work in isolation, and many biological processes are complicated and require the coordinated action of many genes

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17
Q

two key steps to ordering genes in a pathway

A

analysis of effects of one gene on expression of another gene:
- does a mutation in one gene affect the level or distribution of mRNA or protein from another gene?

analysis of double mutants - epistatic interactions:
- do mutations in two different genes define successive steps in a pathway?

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18
Q

give an example of the impacts that gene products can have on the expression of other genes

A
  • staining of Drosophila wing imaginal disks for wingless protein (Wg, green) and vestigial protein (Vg, red)
  • wild-type produces a different staining pattern than wingless mutant
  • this suggests that the wingless gene product is required for the expression of the vestigial gene
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19
Q

2 requirements for an epistasis analysis:

A
  • phenotypes of the two mutants must differ
  • alleles must either be null or constitutive
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20
Q

null allele

A

A mutant allele that results in complete loss of function of the gene.

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21
Q

constitutive allele

A

A mutant allele that causes the gene to be continuously active, regardless of normal regulatory signals.

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22
Q

use the sevenless signalling pathway as an example of epistasis analysis

A
  • the phenotype of the double mutants reveals epistatic interactions
  • in a double mutant, the phenotypes the same as the Ras^G12V mutant, therefore seven less is upstream of Ras
  • the downstream gene is the one that is epistatic
  • thus, Ras is downstream and epistatic to sevenless (‘masks’ sevenless)
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23
Q

what is the programmed cell death pathway and how was it understood?

A
  • eliminates unwanted or damaged cells
  • was understood by epistatic analysis screens
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24
Q

relationship between embryonic and adult body axes in drosophila

A

each embryonic segment defines a specific structure in the adult: 3 head segments, 3 thoracic segments, 8 abdominal segments

25
who made discoveries concerning the genetic control of early embryo development
Christiane Nusslein-Volhard, Eric Wieschaus, Edward B. Lewis
26
What two mutagenesis screens were conducted to identify genes that control embryonic development?
1. Screening for abnormal embryos in homozygous mutant females - Identified recessive mutations in maternal-effect genes 2. Screening for abnormal homozygous mutant embryos - Identified recessive mutations in three classes of zygotic segmentation genes
27
define a maternal-effect gene
genes that are 100% inherited from the maternal side
28
Four classes of genes responsible for segment formation in drosophila embryos
Function in a hierarchy that progressively subdivides the embryo into successively smaller units - maternal genes - gap genes - pair-rule genes - segment polarity genes
29
maternal genes
- expressed by the mother - mRNAs deposited in egg but not translated until after fertilisation - products of maternal effect genes establish morphogenic gradients in the egg - these gradients ensure that gap genes are expressed only in certain broad regions of the embryo
30
gap genes
- expression is controlled by maternal gene products - expression begins at syncytial blastoderm stage - activate pair-rule genes in a series of seven stripes
31
pair-rule genes
- seven zones of expression are controlled by gap and maternal gene products - levels of pair-rule gene products restrict the expression of segment polarity genes to a series of 14 stripes, one per segment
32
segment polarity genes
- expression in 14 segments is controlled by pair-rule gene products - this divides the embryo into 14 segment-sized units
33
what controls the anterior and posterior patterning in the drosophila embryo?
two maternal-effect gene products which are morphogens: bicoid (bcd) and nanos (nos)
34
define a morphogenetic
a substance that defines cell fate in a concentration-dependent manner
35
how do bcd and nos work?
- bcd and nos are transcribed by the mother and their mRNAs are localized to opposite poles of the oocyte - bcd and nos mRNAs are not translated in the embryo until after fertilisation - each protein forms a gradient in the embryos (diffusion)
36
bcd protein gradient
bcd is highest at anterior and lowest at the posterior
37
nos protein gradient
nos is lowest at anterior and highest at the posterior
38
localisation of bicoid mRNA and protein
- bcd mRNA localizes to the anterior pole of the oocyte - bcd protein diffuses from the anterior pole of the embryo to produce an anterior-to-posterior gradient
39
evidence that bicoid is the anterior morphogenetic
- dosage of maternal bcd gene determines how much of the embryo becomes head structures (the more protein in the anterior, the greater the size of the segment) - bicoid null mothers produce embryos that lack all head and thoracic structures
40
describe and draw the distribution of RNA and protein products of maternal-effect genes within the early drosophila embryo
- bicoid protein activates the expression of hunchback gene and represses translation of caudal mRNA - this causes posterior-to-anterior gradient of caudal protein - nanos protein represses the translation of hunchback mRNA - this causes anterior-to-posterior gradient of hunchback protein
41
how is segment number further specified?
by zygotic genes: - bicoid, hunchback, and caudal proteins are transcription factors that control the spatial expression of zygotic genes - zygotic gene expression begins in the syncytial blastoderm stage
42
three classes of zygotic segmentation genes
- gap genes - pair-rule genes - segment polarity genes
43
look at slide 30
44
two classes of pair-rule genes
primary pair-rule genes and secondary pair-rule genes
45
primary pair-rule genes
- expression is controlled by transcription factors encoded by maternal genes and zygotic gap genes - upstream region of each pair-rule gene has multiple binding sites for transcription activation/repression
46
secondary pair-rule genes
- expression is controlled by transcription factors encoded by other pair-rule genes
47
how are pair-rule genes expressed at the early blastoderm stage?
- in seven stripes - two segment periodicity: each stripe has two segments
48
stripe 2
eve transcription is activated by Bcd and Hb, but repressed by giant (Gt) and Kruppel (Kr) proteins
49
how is individual pair-rule stripe formation controlled?
by combinations of maternal-effect and gap proteins (see slide 32_
50
distribution of engrailed proteins in 14 stripes
- segment polarity genes are expressed in stripes that are repeated with single segment periodicity (one stripe per segment) - interactions between various polarity genes maintains the periodicity
51
many of the Drosophila A-P axis genes that contribute to pattern formation code for
transcription factors
52
genetic hierarchy leading to segmentation in drosophila
in successive levels of the hierarchy, genes are expressed in narrower bands
53
how is segment identity established by homeotic genes?
- transcription of homeotic genes is controlled by gap, pair-rule, and segmentation genes - at the cellular blastoderm stage, each homeotic gene is expressed within a subset of body segments - homeotic genes are master regulators that control transcription of many genes responsible for development of segment-specific structures
54
homeotic transformation
when one body part develops as if it were another, due to mutations in homeotic (Hox) genes, which control body plan identity during development.
55
example of a homeotic transformation in drosophila
Wild type wing vs bithorax mutant vs postbithorax mutant
56
how are hox genes expressed?
in spatially restricted domains
57
mammalian Hox genes are organised into four gene clusters:
each on a different chromosome: HoxA HoxB HoxC HoxD
58
how do we know that Hox genes play an important role in developmental patterning of all animals?
all animal genomes - even those of sponges - contain Hox genes