Moles Flashcards
(18 cards)
RAM
Relative atomic mass/Ar
(Sq 24) Mg
(Sq 25) Mg
(Sq 26) Mg
These are all … Of eachother ad they have more/ less …
Isotopes
Neutrons
RAM is the … Of one mole of atoms compared to the mass of one mole of … Which is the most common isotope of … Which is the most common … On earth
Mass
Carbon-12
Carbon
Element
RAMs are found on an element in the periodic table at the
Top left hand number in the element box
Find the RAM of (sq35) Cl 75% and (sq37) Cl 25%
Total mass of 100 atoms: (75 x 35) + (25 x 37) = 3550
3550/100
Average Mass of one atom = 35.5
RFM
Relative formula mass/Mr
RFM is the … Of compounds can be measured on the same … Scale as elements
Masses
Carbon-12
To calculate the RFM of a compound, the RAM of the individual elements are added together eg for H2O
Mr = (2 x H) + (1 x O)
(2 x 1) + (1 x 16)
Mr = 18
Volume of gas equation
Volume = moles x 24
Empirical formula is the … Ratio of the atoms in a compound eg hydrogen peroxide H2O2
Simplest
HO
The empirical formula can be calculated from the mass of each element in a compound there are three stages to this process:
1) determination of mads or percentage of elements
2) divide the given mass or percentage by their RAM
3) calculate the ratio of atoms by dividing by the smallest value
Find empirical formula for calcium bromide
Ca 20%/40(RAM) Br 80%/80(RAM)
Ca 0.5/0.5 Br 1/0.5
= 1 : 2
= CaBr2
Equation for mass of a mole
Mass = Mr x moles
Can be rearranged
Find the mass of two moles of air
[(78 x 28) + (22 x 32) /100] x 2 = 57.76g
Find the mass of 1 mole of lead (II) nitrate Pb(NO3)2
207 + (2 x14) + (6 x 16) = 331g
Find the molecular formula from the empirical formula of CH2
CH2 has a Mr of 14 (RAMs H=1; C=12)
All you need to find out is how many times 14 goes into eg 56. 56/14=4 so all you need is 4 lots of CH2. Finally the molecular formula is C4H8
Reacting masses (the 4 steps) What mass of ammonium nitrate fertiliser can be made from 18.9g of nitric acid
1) calculate the Mr of known substance (HNO3) Mr = 1.0 + 14.0 + (3 x 16.0) = 63.0
2) calculate the number of moles of known substance (HNO3)
3) calculate the number of moles required substance required substance (NH4NO3) from equation
4) calculate mass of required substance (NH4NO3) Mr= 80, mass= 0.30 x 80.0 = 24g
Work out the percentage yield when 10g of ‘a’ would give 12.5g of product but you would only get 11.2g
(11.2/12.5) x 100 = 89.6%