The Henderson-Hasselbalch Equation and Aromatic Carboxylic Acids Flashcards
What does the pH of a solution relate to?
How many hydronium ions there are in a solution.
What will a high level of hydronium ions do to the equilibrium?
By Le Chatelier’s Principle, more H+ ions will force the equilibrium back to HA (or HB+ depending on system)
What will a low level of hydronium ions do to the equilibrium?
By Le Chatelier’s Principle, less H+ ions will force the equilibrium towards A- (or B)
What determines how far equilibrium will shift in response to a change in a number of hydronium ions?
The equilibrium constant (pKa)
What does it mean if the pH is less than the pKa of the compound?
When the pH is less than the pKa, this means the acid is largely undissociated, and therefore fewer H+ ions exist in the solution. According to LeChatelier’s principle, that means there is more HA in solution
What does it mean if the pH is greater than the pKa of the compound?
When the pH is greater than the pKa, there are more H+ ions in the solution. According to LeChatelier’s principle, this means there is more A- in the solution.
How can we figure out which form predominates?
We can figure out which form predominates using the Henderson-Hasselbalch equation: pH=pKa+log([A-]/[HA])
When is pH=pKa?
When [A-} and [HA] are equal (or [B] and [HB+])
What is it important to remember when considering induction and resonance?
If you’re considering one, you need to consider the other.
Alcohols are not normally acidic, but a phenol (alcohol with a benzene ring) is different, why?
The electrons in the lone pair of oxygen can be delocalized into the ring by resonance. This puts a positive charge on the oxygen, which repels the hydrogen and makes it more likely to be donated. Hence phenols are acidic
What two things are important to remember about the transfer of electrons?
All substituents either donate electrons or withdraw electrons via induction
All substituents either donate electrons or withdraw electrons via resonance
How can lone pairs interact with benzene rings?
If a substituent directly attached to a benzene has a lone pair, the lone pair can be delocalized into the ring. This places a positive charge on the electronegative atom donating lone pair and makes the proton more easily donated. It also puts more electrons into the ring, which will decrease the acidity of a carboxylic acid attached or increase basicity of an amine attached
How can double and triple bonds interact with benzene rings?
If the substituent attached to the benzene ring is also double or triple bonded to a more electronegative atom, the p electrons from the ring are delocalised onto the substituent These groups result in fewer electrons in the ring, these will mean that a carboxylic acid attached will be more acidic as charge moves to the basic group. In the case of an amine, it will not want to accept a positively charged proton as there will be repulsion
How do the induction and resonance of lone pairs with benzene rings relate?
Groups with lone pairs adjacent to the ring donate electrons into the ring by resonance and withdraw electrons inductively, donation of electrons by resonance is just much greater than the inductive withdrawal of electrons
How do alkyl groups donate electrons?
Alkyl groups only donate electrons inductively