Unit 4 Key Terms and Concepts Flashcards

(42 cards)

1
Q

Formula Unit

A

an atom, a molecule, an ion, or a
combination of cations and anions that gives a
balance of charges. Anything represented by a
chemical formula.

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2
Q

a Chemical Equation

A

uses chemical symbols to

represent what happens in a chemical reaction.

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3
Q

(s)

A

Solid State

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4
Q

(aq)

A

aqueous (dissolved in water) state

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5
Q

(l)

A

liquid state

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6
Q

(g)

A

gas state

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7
Q

coefficients

A

indicate how many of the chemical units participate in the reactions

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8
Q

balanced chemical equation

A

has the same number of atoms of each kind on both sides of the reaction

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9
Q

Law of Conservation of Matter

A

matter is not
created or destroyed in chemical reactions. Mass
of products = mass of reactants.

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10
Q

decomposition reaction

A

one substance splits into two or more simpler substances

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11
Q

Combustion reaction

A

a reaction of a substance

with O2 that produce heat and light and oxide products. (CO2 and H2O)

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12
Q

1 amu=

A

1.6605387 x 10−24 g

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13
Q

proton mass

A

1.007 amu

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14
Q

neutron mass

A

1.008 amu

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15
Q

Average atomic mass (atomic weight)

A

the weighted average mass of naturally occurring

isotopes in a sample expressed in amu’s.

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16
Q

Formula mass (formula weight)

A

the sum of the average atomic masses (atomic weights) of all the atoms in a formula unit. The mass of a compound in amu’s

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17
Q

Percentage composition

A

is the percentage of each element in a compound by mass.

18
Q

percent composition equation

A

% element A = mass from element A/(total compound mass) x 100

19
Q

1 mol=

A

6.022 x 1023 formula units

20
Q

mole (mol)

A

an amount of substance containing
the same number of formula units as there are
atoms in 12.000 g of ^12C.

21
Q

molar mass

A

the mass in grams of one mole of a

substance. Numerically equal to formula weight.

22
Q

The formula mass of water

A

2(1.008) + 16.00 = 18.02 amu

23
Q

The molar mass of water

A

2(1.008) + 16.00 = 18.02 g/mol

24
Q

The mole is the SI unit for

A

an amount of substance

25
Molecular Formula
The actual numbers of atoms or moles of each element in a compound
26
empirical formula
a chemical formula that gives the smalles whole number ratios of atoms or moles of each element in a compound
27
How do you find the empirical formula from a moleuclar formula?
Reduce the subscripts as much as possible. | ex: C6H12O6= CH2O
28
C6H6 Empirical Formula
CH
29
Na2SO4 Empirical Formula
NaSO2
30
C6H14 Empirical Formula
C3H7
31
C5H12
C5H12
32
How do you find the molecular formula from an empirical formula?
Step 1: You must know the formula weight or molar mass of the compound Step 2: Compare the mass of the molecule to the mass of the empirical formula unit. Express this as a whole number Step 3: Multiply the subscripts by the whole number factor
33
Percentage Composition can help identify compounds by
comparing experimental percentages to percentages in known compounds
34
Stoichiometry
the relationships among the amounts of reactants and products in a chemical reaction in terms of moles (Mole Bookkeeping)
35
When Determining how many moles of an element are in a specific weight of the same element, what are the procedures?
Use dimensional analysis to multiply the given amount times (1 mol of the element divided by the weight of the element) Ex. How many Moles of Zn are in 116 g of Zn. 116 g Zn*(1mol Zn/65.39 g Zn)... The g Zn will cancel out each other and leave the answer in grams.
36
When Determining how many moles of a compound are in a specific weight (in Grams) of the same compund, what are the procedures?
Use Dimensional Analysis to multiply the given amount times (1 Mol of the compound/mass of the compound) Ex: How many Moles of Sodium Bicarbonate are in 25.0 g Sodium Bicarbonate? 25.0 g NaHCO3x(1 mol NaHCO3/84.008 g NaHCO3)
37
When determining how many moles of an atom are in a specific amount (In grams) of a compound, what are the procedures?
Use Dimensional Analysis to multiply the given amount times (1 mol of the compound/mass of the compound)x(the number of atoms of the element in the compound/1 mol of the compound) Ex: How many moles of oxygen atoms are in 245 g of Chromium (III) Sulfate) 245 g Cr2(SO4)3 * (1 Mol Cr2(SO4)3/392.21 g Cr2(SO4)3) *(12 mol O/1Mol Cr2(SO4)3).... This leaves our end result in moles of oxygen as requested.
38
When determining how many moles of an element's atoms are in a specific amount (In moles of a compound, what are the procedures?
Use Dimensional Analysis to multiply the given amount times (the # of atoms in the compound formula/1 mol of the compound) Ex. Moles of Hydrogen atoms in 4.80 mol of calcium acetate 4.80 mol Ca(C2H3O2)2 * (6 Mol H/1 Mol Ca(C2H3O2)3)
39
When determining how many atoms are in a specific amount (in moles) of an element, what are the procedures?
Use Dimensional Analysis to multiply the given amount times (Avogadro's Number/1 Mol of the element) Ex. How many atoms are in 7.65 mol of Cu? 7.65 mol Cu *(6.022*10^23/1 Mol Cu)
40
When determining how many molecules are in a specific amount (in grams) of a compound, what are the procedures?
Use Dimensional Analysis to multiply the given amount times ( 1 mole of the compound/ mass of the compound) * (Avogadro's #/1 mol of the compound) Ex. How many molecules of C6H6 are in a 150 g sample of C6H6? 150.0 g C6H6 * (1Mol C6H6/78.108 g C6H6)* (6.022*10^23/1 mol C6H6)
41
When determining the formula Units in a specific amount (in grams) of a compound, what are the procedures?
Use Dimensional Analysis to multiply the given amount times *(1 Mol of the compound/mass of the compound)*( Avogadro's #/ 1mol of the compound) Ex: How many formula Units of NaCLO4 are in 500.0 g od NaCLO4? 500.0 g NaClO4*(1 mol NaClO4/122.44 g NaClO4) *(6.022*10^23 formula Units NaClO4/1 mol NaClO4)
42
When determining the mass(g) of a compound given in moles, what are the procedures?
Multiply the given amoutn times (mass of compound/1 mol of the compound). This will give the result in grams. Ex. What is the mass of 3.25 mol of Barium Chloride? 3.25 mol BaCl2 *(208.2 g BaCl2/1 mol BaCl2)