Acid Base Concepts Flashcards

1
Q

Equation for acid base homeostasis:

A

See image

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2
Q

Henderson equation:

H+ =

A

24 x pCO2/ [HCO3-]

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3
Q

Daily acid produciton =

pH ~ 7 = how many mmol?

How is acid/base homeostatis maintained?

A

~20,000 mmol acid

pH~7 = 140 nmol

buffering

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4
Q

HCO3- is absorbed where and how?

A

in the Proximal tubule via carbonic anhydrase

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5
Q
A
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6
Q

where is H+ excreated?

A

In the Collecting duct

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7
Q

Components of arterial blood gas:

Components that make up basic chemistry:

A

pCO2 and pH

HCO3-, Na+, Cl-

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8
Q

Your patient has Primary respiratory acidosis… What must his pCO2 be?

A

primary respiratoyr acidosis have pCO2 > 40mmHg

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9
Q

Your pt has primary respiratory alkalosis… what does the pCO2 need to be?

A

pCO2 < 40mmHg

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10
Q

Patient has primary metabolic acidosis, what must the HCO3- be?

A

HCO3- < 24mmol/L in primary metabolic acidosis

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11
Q

Pt has primary metabolic alkalosis, what must our HCO3- value be?

A

HCO3- in primary metabolic alkalosis >24 mmol/L

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12
Q

What two things could lead to acidosis?

A

Primary respiratory: CO2 > 40mmHg

Primary metabolic: HCO3-

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13
Q

What two situations would cause alkalosis?

A

Primary respiratory: pCO2 < 40mmHg

Primary metabolic HCO3- >24 mmol/L

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14
Q

Four steps for systematic approach to determine acid/base disturbances

A
  1. pH (7.40 is normal)
  2. Determine primary disorder

–metabolic or respiratory

  1. Calculate expected compensation
  2. Calculate anion gap
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15
Q

What is meant by expected compenstation? Why is it important?

A

the body’s ability to appropriately compensate to primary acidosis or alkalosis.

If body cannot completely compensate, this is indicative of secondary disorder.

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16
Q

What equation do we use for compensation in the case of metabolic acidosis (when HCO3- is <24 mmol/L)?

A

-pCO2 = 1.5 x [HCO3-] + 8

or

-pCO2 = last 2 digits of pH (only down to pH of 7.2)

17
Q

What equation do we use to calculate compensation for metabolic alkalosis (HCO3- >24 mmol/L)?

A
18
Q

pCO2 compensates in same direction as:

A

bicarb change

19
Q

Calculation used for Respiratory Acidosis (PaCO2 > 40)

Acute:

Chronic:

A

Acute: bicarb increase 1 mmol/L per 10 mmHg increase of PaCO2

Chronic: bicarb increases 4 mmol/L per 10 mmHg PaCO2

20
Q

What are the calculations for compensation in respiratory Alkalosis (PaCO2 <40 mmHg)

Acute:

Chronic

A

– Acute: bicarb DEcreases 2 mmol/L per 10mmHg PaCO2
– Chronic: bicarb DEcreases 4 mmol/L per 10 mmHg PaCO2

21
Q

If your patient has a pCO2 = 60 mmHg and is acidotic, what is our primary disorder?

What is the acute and chronic compensation of the bicarb (HCO3-)?

A

Respiratory acidosis

pCO2 = 60 mmHg (normal is 40 mmHg) thus increase of 20mmHg

HCO3- increase by 2 mmol/L (acute) and 8 mmol/L (chronic)

[Acute: bicarb increase 1 mmol/L per 10 mmHg PaCO2
– Chronic: bicarb increase 4 mmol/L per 10 mmHg PaCO2]

22
Q

Your patient is acidotic with a bicarb = 15 mmol/L

What is the primary disorder?

What will the expected compensation be?

A

Metabolic acidosis

pCO2 = (1.5 x 15) + 8 = 30 mmHg

23
Q

What cations and anions are taken into account when calculating the anion gap?

A

Na+ cation

HCO3- and Cl- = anions

24
Q

65 yo with history of ileus presented to surgical team.
NG placed to suction and next am had seizure.

pH = 7.63
pCO2 = 55
sO2 = 94 %

Na+ = 128 K+ = 2.9

Cl-= 70 HCO3- = 50

  1. What is our primary disorder?
A

Patient is alkalemic, pCO2= 55 and HCO3- = 50

Primary metabolic alkalosis (HCO3- > 24mmol/L is alkalosis)

25
Q

65 yo with history of ileus presented to surgical team.
NG placed to suction and next am had seizure.

pH = 7.63
pCO2 = 55
sO2 = 94 %

Na+ = 128 K+ = 2.9

Cl-= 70 HCO3- = 50

Patient has primary metabolic alkalosis. What is the compensation?

A

with primary metabolic alkalosis, we compensate with pCO2-

Equation: –pCO2 = 0.9 x [HCO3] + 9

-pCO2 = 0.9 x [50] +9 = 54mmHg CO2

(our pts = 55mmHg CO2, thus is appropriately compensated)

26
Q

65 yo with history of ileus presented to surgical team.
NG placed to suction and next am had seizure.

pH = 7.63
pCO2 = 55
sO2 = 94 %

Na+ = 128 K+ = 2.9

Cl-= 70 HCO3- = 50

Calculate anion gap

A

[Na+] - [Cl- + HCO3-]

128 - [70 +50} = 8

27
Q
A