Chemistry Unit 3 Flashcards

(56 cards)

1
Q

How to test if solution of metal compounds are amphoteric

A

If the solution forms a precipitate on addition of hydroxide, which is then able to redissolve in excess hydroxide, the compound is amphoteric.

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2
Q

Define the inert pair effect

A

This is the tendency of the outermost s2 pair of electrons in
an atom to remain unshared in compounds, leading to a lower oxidation state.
This occurs in groups 3, 4 and 5. As you go down a group, the tendency increases.

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3
Q

Define octet expansion

A

This is the ability of some atoms to use d-orbitals to have more than 8 electrons in their valence (outer) shell.

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4
Q

Give one difference between graphite and hexagonal BN

A

There are no delocalised electrons in BN, (the B – N bonds are polar), whilst there are in graphite. So unlike graphite, BN cannot conduct electricity and is used as an electrical insulator.

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5
Q

Give two similarities between diamond and cubic BN

A

Both are extremely hard and have high melting points due to strong covalent bonds between the atoms.

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6
Q

Why does the stability of the +2 state increase as you go down group 4

A

The inert pair effect becomes more significant.

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7
Q

Why does SiCl4 react violently to form a white ppt and steamy fumes with water but CCl4 doesn’t react with water despite them both being covalently bonded tetrachlorides

A

Silicon tetrachloride can react due to the availability of d-orbitals in the silicon atom. They allow a lone pair from oxygen to bond with the SiCl4. These d-orbitals are not available in the carbon atom, so it cannot react.

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8
Q

Define disproportionation reaction

A

Atoms of the same element are oxidised and reduced to form different products.

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9
Q

Chlorine and cold NaOH reaction

A

Sodium chloride and sodium chlorate(I) (NaOCl) and water are formed

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10
Q

Chlorine and hot NaOH reaction

A

Sodium chloride and sodium chlorate(V) (NaClO3) and water are formed

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11
Q

Define transition metal

A

An element that possesses a partially filled d sub-shell in its atom or stable ions

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12
Q

Why can transition metals have variable oxidation states

A

Because the energies of the 4s and 3d orbitals are very similar, so the energy required to remove any of these electrons is similar

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13
Q

Why do transition metals make good homogeneous catalysts

A

By using their variable oxidation states to oxidise/reduce a reactant which makes it more reactive. Products are released and the metal returns to the original
oxidation state

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14
Q

Why do transition metals make good heterogeneous catalysts

A

They provide a surface for molecules to be adsorbed and come closer together for reaction.
Molecules can form coordinate bonds to the metal atom because there are empty d orbitals to accept electron pairs due to the d-orbitals only being partially filled

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15
Q

Define ligand

A

A small molecule or ion with a lone pair of electrons

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16
Q

Give the molecular formula, bond angle and colour of the two tetrahedral complex ions

A

[CoCl4]2– is blue
[CuCl4]2– is yellow/green
Bond angle of 109.5

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17
Q

What does EMF tell you about the feasibility of a reaction

A

If EMF is positive, the reaction is feasible

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18
Q

Give the energy in terms of wavelength equation

A

Energy (in Joules) = Planck constant (h) x speed of light (c) / wavelength (in metres)

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19
Q

Give the energy in terms of frequency equation

A

Energy (in Joules) = Planck constant x frequency

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20
Q

What does the enthalpy change tell you about stability

A

If enthalpy change of formation is negative, the compound is more stable than its elements

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21
Q

Give the equation for standard enthalpy of solution

A

Standard enthalpy of hydration + enthalpy of lattice breaking

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22
Q

Give the equation for Gibbs free energy change

A

delta G = delta H - (T x delta S)

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23
Q

What does a negative Gibbs free energy change tell you

A

The reaction occurs spontaneously

24
Q

What is pH equal to when salt concentration and acid concentration are equal in a buffer solution

25
Equation for Ka of a buffer solution
Ka = [H+][A-]/[HA] where A- is the concentration of salt used and HA is the concentration of acid used
26
Explain why aluminium forms compounds that are electron deficient
Aluminium has three outer shell electrons so it is able to form three covalent bonds giving six outer shell electrons leaving it electron deficient
27
5 soluble compounds
All nitrates All group 1 All group 1 and 2 halides Ba(OH)₂ MgSO₄
28
6 insoluble compounds
PbI₂ (yellow) BaCO₃ BaSO₄ Mg(OH)₂ MgCO₃ CaCO₃
29
Stable oxidation states of Cr
+3 +6
30
Stable oxidation states of Mn
+2 +4 +7
31
Stable oxidation states of Co
+2
32
Stable oxidation states of Cu
+1 +2
33
Colour of [Cu(H₂​O)₆​]²⁺
Blue
34
Colour of [Fe(H₂O)₆]​²⁺
Pale green
35
Colour of [Fe(H₂​O)₆​]³⁺
Yellow
36
Colour of [Cr(H₂O)₆​]³⁺
Dark green
37
Colour of [Co(H₂O)₆]​²⁺
Pink
38
Colour of [CuCl₄]​²⁻
Yellow or green
39
Colour of [CoCl₄]​²⁻
Blue
40
Colour of [Cu(NH₃)₄(H₂O)₂]²⁺
Royal blue
41
Reaction of [Cu(H₂​O)₆​]²⁺ with NaOH
Dropwise - Pale blue ppt (Cu(OH)₂) Excess - No change
42
Reaction of [Fe(H₂O)₆]​²⁺ with NaOH
Dropwise - Dark green ppt (Fe(OH)₂) Excess - No reaction but turns brown as oxidised by the air (Fe(OH)₃)
43
Reaction of [Fe(H₂​O)₆​]³⁺ with NaOH
Dropwise - Brown ppt (Fe(OH)₃) Excess - No change
44
Reaction of [Cr(H₂O)₆​]³⁺ with NaOH
Dropwise - Grey-green ppt (Cr(OH)₃) Excess - Dissolves (forms deep green solution of [Cr(OH)₆]³⁻)
45
Define conjugate acids and bases
Conjugate acids are formed by the addition of H+ to a base. Conjugate bases are formed by the loss of H+ from an acid.
46
Predict the pH of a strong acid/weak base solution
2 to 6.5, base (e.g ammonium ion) dissociates to release protons
47
Predict the pH of a weak acid/strong base solution
6.5 to 11, weak acids (e.g organic acids) react with water and form an equilibrium in which hydroxide ions are formed
48
Name the only soluble lead salts
Lead (II) nitrate and lead (II) ethanoate
49
MnO₄⁻ is reduced to ____
Mn²⁺
50
Cr₂O₇²⁻ is reduced to _____
Cr³⁺
51
S₂O₃²⁻ is oxidised to ________
S₄O₆²⁻
52
Aluminium as a base reaction
Al₂O₃ + 6HCl -> 2AlCl₃ + 3H₂O
53
Aluminium as an acid reaction
Al₂O₃ + 2NaOH + 3H₂O -> 2Na[Al(OH)4]
54
3 disadvantages of hydrogen fuel cells
Hydrogen fuel must be generated elsewhere which will likely use fossil fuel energy sources Gases are difficult to store Fuel cells operate at lower temperatures so need efficient catalysts (expensive metals)
55
How does a hydrogen fuel cell work
Electrons are removed from hydrogen atoms at one electrode, the protons diffuse through a semi-permeable membrane to the other electrode where they recieve electrons and oxygen molecules to form water
56
Advantages and disadvantages of sampling and quenching
Can be used for a large range of reactions Labour and time intensive as each sample is analysed individually Only appropriate when reaction mixture is homogenous (e.g. all in solution)