E-3 Equilibria of Acids/Bases Flashcards
(39 cards)
Complete the formula
pH + pOH =
14
Complete the following equation
Kw =
[H3O+][OH-] = 1.00 x 10-14
Complete the following equation.
Ka•Kb =
1.0 x 10-14
Don’t use a calculator!
What is the pH of a when [H3O+] = 1.0 x 10-3 M?
3
Don’t use a calculator!
What is the pH of a when [H3O+] = 1.0 x 10-7 M?
7
Don’t use a calculator!
What is the pH of a when [H3O+] = 1.0 x 10-13 M?
13
Don’t use a calculator!
What is the pOH of a when [OH-] = 1.0 x 10-11 M?
11
Don’t use a calculator!
What is the pOH of a when [OH-] = 1.0 x 10-5 M?
5
Don’t use a calculator!
What is the pOH of a when [OH-] = 1.0 x 10-7 M?
7
Don’t use a calculator!
What is the pH of a when [OH-] = 1.0 x 10-2 M?
14 - 2 = 12
Don’t use a calculator!
What is the pH of a when [OH-] = 1.0 x 10-9 M?
14 - 9 = 5
Don’t use a calculator!
What is the pH of a when [OH-] = 1.0 x 10-7 M?
14 - 7 = 7
Don’t use a calculator!
The Ka of an acid is 1.0 x 10-4. What is the Kb of its conjugate base?
1.0 x 10-14 / 1.0 x 10-4 = 1.0 x 10-10
Don’t use a calculator!
The Ka of an acid is 1.0 x 10-12. What is the Kb of its conjugate base?
1.0 x 10-14 / 1.0 x 10-12 = 1.0 x 10-2
Don’t use a calculator!
The Kb of a base is 1.0 x 10-5. What is the Ka of its conjugate acid?
1.0 x 10-14 / 1.0 x 10-5 = 1.0 x 10-9
Don’t use a calculator!
The Kb of a base is 1.0 x 10-8. What is the Ka of its conjugate acid?
1.0 x 10-14 / 1.0 x 10-8 = 1.0 x 10-6
Write out the Bronsted-Lowry Reaction for nitrous acid (HNO2).
HNO2 + H2O ⇔ NO2- + H3O+
Write out the Bronsted-Lowry Reaction for methyl amine (CH3NH2).
CH3NH2 + H2O ⇔ CH3NH3+ + OH-
Write out the Bronsted-Lowry Reaction for the hydrogen sulfate ion (HSO4-) acting as a base.
HSO4- + H2O ⇔ H2SO4 + OH-
Write out the Bronsted-Lowry Reaction for the hydrogen sulfate ion (HSO4-) acting as an acid.
HSO4- + H2O ⇔ SO42- + H<span>3</span>O+
Write out the law of mass action for the following reaction.
HF + H2O ⇔ F-+ H3O+
Ka = [F-][H3O+] / [HF]
Write out the law of mass action for the following reaction.
F- + H2O ⇔ HF+ OH-
Kb = [HF][OH-] / [F-]
What is the conjugate base of HF?
HF + H2O ⇔ F-+ H3O+
F-
What is the conjugate acid of H2O?
HF + H2O ⇔ F-+ H3O+
H3O+