T-2: Enthalpy Flashcards
Energy required to break a chemical bond
Bond Energy
Standard states
Phase at 25ºC, 1 atm for gases and 1 M for solutions.
Energy change that occurs when you make one mole of a compound from its constituent elements at standard states
Standard Enthalpy of Formation
The equation to find ΔHº from standard enthalpies of formation
ΔHº = Σ(nΔHºf,prod) - Σ(nΔHºf, react)
The equation to find ΔH from bond energies.
ΔH = Σ(nB.E.broken) - Σ(nB.E.formed)
The amount of energy required to break a chemical bond.
Bond energy
Bond Energy
Energy required to break a chemical bond
Phase at 25ºC, 1 atm for gases and 1 M for solutions.
Standard states
Standard Enthalpy of Formation
Energy change that occurs when you make one mole of a compound from its constituent elements at standard states
ΔHº = Σ(nΔHºf,prod) - Σ(nΔHºf, react)
The equation to find ΔHº from standard enthalpies of formation
ΔH = Σ(nB.E.broken) - Σ(nB.E.formed)
The equation to find ΔH from bond energies.
Bond energy
The amount of energy required to break a chemical bond.
Exothermic or Endothermic
Breaking a covalent bond
Endothermic
Exothermic or Endothermic
Making a covalent bond
exothermic
Exothermic or Endothermic
F2(g) → 2F(g)
endothermic - breaking a bond
Exothermic or Endothermic
2Br(g) → Br2(g)
exothermic - making a bond
Exothermic or Endothermic
Li+(g) + Cl-(g) → LiCl(s)
exothermic - making a bond
Exothermic or Endothermic
NaF(s) → Na+(g) + F-(g)
endothermic - breaking a bond
Write out reaction equation for standard enthalpy of formation for HCl.
1/2H2(g) + 1/2Cl2(g) → HCl(g)
Write out reaction equation for standard enthalpy of formation for CO2.
C(s) + O2(g) → CO2(g)
S8(s) + 8 O2(g) →8 SO2 (g)
Write this reaction as a enthalpy of formation for SO2
1/8 S8(s) + O2(g) → SO2(g)
The ΔHº for the following reaction is…
1/2H2(g) + 1/2Cl2(g) → HCl(g) ΔHº = -92 kJ/mol
What is the ΔHº for this reaction?
H2(g) + Cl2(g) → 2 HCl(g)
ΔHº = - 184 kJ/mol
- multiply reaction by 2 so multiple value by 2
The ΔHº for the following reaction is…
1/2H2(g) + 1/2Cl2(g) → HCl(g) ΔHº = -92 kJ/mol
What is the ΔHº for this reaction?
HCl(g) → 1/2H2(g) + 1/2Cl2(g)
ΔHº = 92 kJ/mol
- reverse reaction so reverse sign
The ΔHº for the following reaction is…
1/2H2(g) + 1/2Cl2(g) → HCl(g) ΔHº = -92 kJ/mol
What is the ΔHº for this reaction?
2 HCl(g) → H2(g) + Cl2(g)
ΔHº = 184 kJ/mol
- reversed the reaction so reverse the sign
- multiplied reaction by 2 so multiple value by 2